{"problem": "The number of intense detective thriller in West Sahara Movie Festival equals 4. The number of calm road movie in Taylor Movie Festival equals 2. The number of futuristic sci-fi movie in West Sahara Movie Festival equals the number of futuristic sci-fi movie in Verdi Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 1 plus the number of intense detective thriller in West Sahara Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival exists, and its number is greater than 0. The number of futuristic sci-fi movie in Taylor Movie Festival equals 3 times the number of intense detective thriller in West Sahara Movie Festival. The number of calm road movie in Verdi Movie Festival equals the number of futuristic sci-fi movie in Verdi Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 3. The number of intense detective thriller in Verdi Movie Festival equals 4 times the number of futuristic sci-fi movie in Verdi Movie Festival. The total number of movies in Verdi Movie Festival equals 18. ", "question": "How many futuristic sci-fi movie does Verdi Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Verdi Movie Festival as x; we don't know its value yet but will find it out later. Define intense detective thriller in Verdi Movie Festival as O; F = x = x; so O = 4 * F = (4) * (x) = 4*x. Define calm road movie in Verdi Movie Festival as z; so z = x = x. Define total number of movies in Verdi Movie Festival as n; U = x + O = x + 4*x = 5*x; so n = U + z = 5*x + x = 6*x. We know n = 18, so we have 6*x = 18 and we solve it through the following steps: Simplifying the equation: 6*x = 18. Move all terms to one side: 6*x - 18 = 0. Isolate the term with x: 6*x = 18. Divide both sides by 6: x = 18 / 6. Solution: x = 3. Answer: 3.", "op": 7, "id": "12_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult fox in Beverly Forest exists, and its number is greater than 0. The number of adult fox in Cedar Valley equals 3 times the total number of adult animals in Beverly Forest. The total number of adult animals in Cedar Valley equals 18. The number of adult racoon in Beverly Forest equals 4. ", "question": "How many adult fox does Beverly Forest have?", "solution": "The question is difficult, so we use equations to solve it. Define adult racoon in Beverly Forest as N; so N = 4. Define adult fox in Beverly Forest as x; we don't know its value yet but will find it out later. Define total number of adult animals in Beverly Forest as B; so B = N + x = 4 + x = x + 4. Define adult fox in Cedar Valley as r; P = B = x + 4; so r = 3 * P = (3) * (x + 4) = 3*x + 12. Define total number of adult animals in Cedar Valley as m; so m = r = 3*x + 12. We know m = 18, so we have 3*x + 12 = 18 and we solve it through the following steps: Simplifying the equation: 3*x + 12 = 18. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.", "op": 7, "id": "18_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of futuristic sci-fi movie in R\u00eaves de Belleville equals 3. The number of calm road movie in R\u00eaves de Belleville equals the sum of the number of futuristic sci-fi movie in R\u00eaves de Belleville, the number of calm road movie in Festival Lumi\u00e8re de Valmont, the number of solemn period drama in Festival Lumi\u00e8re de Valmont, and the number of calm road movie in Festival de Clairmont. The total number of movies in Festival de Clairmont equals 11. The number of futuristic sci-fi movie in Festival de Clairmont exists, and its number is greater than 0. The number of solemn period drama in Festival de Clairmont equals 2 plus the number of calm road movie in Festival de Clairmont. The number of solemn period drama in R\u00eaves de Belleville equals 3. The number of calm road movie in Festival Lumi\u00e8re de Valmont equals 3 plus the number of solemn period drama in Festival Lumi\u00e8re de Valmont. The number of solemn period drama in Festival Lumi\u00e8re de Valmont equals 3. The number of futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont equals the number of solemn period drama in Festival Lumi\u00e8re de Valmont. The number of calm road movie in Festival de Clairmont equals 3. ", "question": "How many futuristic sci-fi movie does Festival de Clairmont have?", "solution": "The question is difficult, so we use equations to solve it. Define calm road movie in Festival de Clairmont as D; so D = 3. Define solemn period drama in Festival de Clairmont as C; O = D = 3; so C = 2 + O = 2 + 3 = 5. Define futuristic sci-fi movie in Festival de Clairmont as x; we don't know its value yet but will find it out later. Define total number of movies in Festival de Clairmont as U; V = D + C = 3 + 5 = 8; so U = V + x = 8 + x = x + 8. We know U = 11, so we have x + 8 = 11 and we solve it through the following steps: Simplifying the equation: x + 8 = 11. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.", "op": 7, "id": "20_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of intense detective thriller in Northwood Movie Festival equals 3 plus the difference between the number of intense detective thriller in Taylor Movie Festival and the number of upbeat metropolis comedy in Northwood Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals 2. The total number of movies in Northwood Movie Festival equals 6. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 4. The number of upbeat metropolis comedy in Taylor Movie Festival equals 1 plus the number of solemn period drama in Taylor Movie Festival. The number of intense detective thriller in Taylor Movie Festival exists, and its number is greater than 0. The number of solemn period drama in West Sahara Movie Festival equals the sum of the number of intense detective thriller in Taylor Movie Festival and the number of intense detective thriller in Northwood Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 3. The number of upbeat metropolis comedy in Northwood Movie Festival equals the number of intense detective thriller in Taylor Movie Festival. ", "question": "How many intense detective thriller does Taylor Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define intense detective thriller in Taylor Movie Festival as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in Northwood Movie Festival as i; so i = x = x. Define intense detective thriller in Northwood Movie Festival as Z; D = x - i = (x) - (x) = 0; so Z = 3 + D = 3 + 0 = 3. Define total number of movies in Northwood Movie Festival as d; so d = i + Z = x + 3 = x + 3. We know d = 6, so we have x + 3 = 6 and we solve it through the following steps: Simplifying the equation: x + 3 = 6. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.", "op": 7, "id": "14_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of schools in Brightford equals 12. The number of public highschool in Evervale City equals 3 times the total number of schools in Glenfield City. The number of elementary school in Brightford equals the total number of schools in Evervale City. The number of culinarian school in Glenfield City exists, and its number is greater than 0. ", "question": "How many culinarian school does Glenfield City have?", "solution": "The question is difficult, so we use equations to solve it. Define culinarian school in Glenfield City as x; we don't know its value yet but will find it out later. Define total number of schools in Glenfield City as g; so g = x = x. Define public highschool in Evervale City as q; Y = g = x; so q = 3 * Y = (3) * (x) = 3*x. Define total number of schools in Evervale City as c; so c = q = 3*x. Define elementary school in Brightford as J; so J = c = 3*x. Define total number of schools in Brightford as a; so a = J = 3*x. We know a = 12, so we have 3*x = 12 and we solve it through the following steps: Simplifying the equation: 3*x = 12. Move all terms to one side: 3*x - 12 = 0. Isolate the term with x: 3*x = 12. Divide both sides by 3: x = 12 / 3. Solution: x = 4. Answer: 4.", "op": 7, "id": "8_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of culinarian school in Brightford equals the number of public highschool in Brightford. The number of private middle school in Evervale City equals the number of culinarian school in Brightford. The number of public highschool in Brightford equals the sum of the total number of schools in Glenfield City and the number of culinarian school in Glenfield City. The number of culinarian school in Glenfield City exists, and its number is greater than 0. The total number of schools in Evervale City equals 4. ", "question": "How many culinarian school does Glenfield City have?", "solution": "The question is difficult, so we use equations to solve it. Define culinarian school in Glenfield City as x; we don't know its value yet but will find it out later. Define total number of schools in Glenfield City as f; so f = x = x. Define public highschool in Brightford as C; so C = f + x = x + x = 2*x. Define culinarian school in Brightford as k; so k = C = 2*x. Define private middle school in Evervale City as I; so I = k = 2*x. Define total number of schools in Evervale City as M; so M = I = 2*x. We know M = 4, so we have 2*x = 4 and we solve it through the following steps: Simplifying the equation: 2*x = 4. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.", "op": 7, "id": "8_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of elementary school in Ruby Bay equals the sum of the number of regional medical school in Oakbridge City and the number of private middle school in Shoreline City. The number of private middle school in Shoreline City equals the number of elementary school in Shoreline City. The total number of schools in Shoreline City equals 8. The number of elementary school in Shoreline City equals 2. The number of regional medical school in Ruby Bay equals 4. The number of private middle school in Oakbridge City exists, and its number is greater than 0. The number of regional medical school in Oakbridge City equals 4. The number of regional medical school in Shoreline City equals the number of private middle school in Oakbridge City. The number of elementary school in Oakbridge City equals the total number of schools in Shoreline City. The number of private middle school in Ruby Bay equals the sum of the number of elementary school in Shoreline City and the number of regional medical school in Shoreline City. ", "question": "How many private middle school does Oakbridge City have?", "solution": "The question is difficult, so we use equations to solve it. Define elementary school in Shoreline City as K; so K = 2. Define private middle school in Oakbridge City as x; we don't know its value yet but will find it out later. Define regional medical school in Shoreline City as Z; so Z = x = x. Define private middle school in Shoreline City as y; so y = K = 2. Define total number of schools in Shoreline City as Y; n = Z + K = x + 2 = x + 2; so Y = n + y = x + 2 + 2 = x + 4. We know Y = 8, so we have x + 4 = 8 and we solve it through the following steps: Simplifying the equation: x + 4 = 8. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.", "op": 7, "id": "12_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult owl in Beverly Forest equals 2. The number of adult owl in Maple Creek equals 4. The number of adult parrot in Beverly Forest equals the number of adult blue jay in Oakridge Riverside. The number of adult blue jay in Beverly Forest equals 2. The number of adult blue jay in Oakridge Riverside equals the number of adult parrot in Oakridge Riverside. The number of adult parrot in Oakridge Riverside exists, and its number is greater than 0. The number of adult blue jay in Maple Creek equals the number of adult blue jay in Oakridge Riverside. The number of adult parrot in Maple Creek equals the sum of the total number of adult animals in Maple Creek and the total number of adult animals in Oakridge Riverside. The total number of adult animals in Oakridge Riverside equals 12. The number of adult owl in Oakridge Riverside equals the number of adult blue jay in Maple Creek. ", "question": "How many adult parrot does Oakridge Riverside have?", "solution": "The question is difficult, so we use equations to solve it. Define adult parrot in Oakridge Riverside as x; we don't know its value yet but will find it out later. Define adult blue jay in Oakridge Riverside as r; so r = x = x. Define adult blue jay in Maple Creek as I; so I = r = x. Define adult owl in Oakridge Riverside as m; so m = I = x. Define total number of adult animals in Oakridge Riverside as d; u = r + m = x + x = 2*x; so d = u + x = 2*x + x = 3*x. We know d = 12, so we have 3*x = 12 and we solve it through the following steps: Simplifying the equation: 3*x = 12. Move all terms to one side: 3*x - 12 = 0. Isolate the term with x: 3*x = 12. Divide both sides by 3: x = 12 / 3. Solution: x = 4. Answer: 4.", "op": 7, "id": "4_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of calm road movie in Verdi Movie Festival equals 3 times the number of upbeat metropolis comedy in Verdi Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival exists, and its number is greater than 0. The number of intense detective thriller in Verdi Movie Festival equals the number of calm road movie in Verdi Movie Festival. The total number of movies in Verdi Movie Festival equals 28. ", "question": "How many upbeat metropolis comedy does Verdi Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in Verdi Movie Festival as x; we don't know its value yet but will find it out later. Define calm road movie in Verdi Movie Festival as F; W = x = x; so F = 3 * W = (3) * (x) = 3*x. Define intense detective thriller in Verdi Movie Festival as c; so c = F = 3*x. Define total number of movies in Verdi Movie Festival as T; U = x + F = x + 3*x = 4*x; so T = U + c = 4*x + 3*x = 7*x. We know T = 28, so we have 7*x = 28 and we solve it through the following steps: Simplifying the equation: 7*x = 28. Move all terms to one side: 7*x - 28 = 0. Isolate the term with x: 7*x = 28. Divide both sides by 7: x = 28 / 7. Solution: x = 4. Answer: 4.", "op": 7, "id": "17_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult parrot in Oakridge Riverside exists, and its number is greater than 0. The number of adult eagle in Beverly Forest equals the number of adult eagle in Oakridge Riverside. The number of adult eagle in Pine Ridge equals 4. The total number of adult animals in Oakridge Riverside equals 8. The number of adult blue jay in Pine Ridge equals 1. The number of adult eagle in Oakridge Riverside equals 3. The number of adult parrot in Beverly Forest equals 2 plus the sum of the number of adult eagle in Pine Ridge and the number of adult blue jay in Pine Ridge. The number of adult blue jay in Oakridge Riverside equals the number of adult blue jay in Beverly Forest. The number of adult blue jay in Beverly Forest equals 2. The number of adult parrot in Pine Ridge equals the total number of adult animals in Oakridge Riverside. ", "question": "How many adult parrot does Oakridge Riverside have?", "solution": "The question is difficult, so we use equations to solve it. Define adult blue jay in Beverly Forest as q; so q = 2. Define adult blue jay in Oakridge Riverside as b; so b = q = 2. Define adult eagle in Oakridge Riverside as l; so l = 3. Define adult parrot in Oakridge Riverside as x; we don't know its value yet but will find it out later. Define total number of adult animals in Oakridge Riverside as S; w = x + b = x + 2 = x + 2; so S = w + l = x + 2 + 3 = x + 5. We know S = 8, so we have x + 5 = 8 and we solve it through the following steps: Simplifying the equation: x + 5 = 8. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.", "op": 7, "id": "16_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of calm road movie in Taylor Movie Festival equals 3 times the number of intense detective thriller in Taylor Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 4 times the difference between the number of calm road movie in Taylor Movie Festival and the number of intense detective thriller in Taylor Movie Festival. The total number of movies in Verdi Movie Festival equals 16. The number of intense detective thriller in Taylor Movie Festival exists, and its number is greater than 0. ", "question": "How many intense detective thriller does Taylor Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define intense detective thriller in Taylor Movie Festival as x; we don't know its value yet but will find it out later. Define calm road movie in Taylor Movie Festival as L; e = x = x; so L = 3 * e = (3) * (x) = 3*x. Define intense detective thriller in Verdi Movie Festival as R; o = L - x = (3*x) - (x) = 2*x; so R = 4 * o = (4) * (2*x) = 8*x. Define total number of movies in Verdi Movie Festival as t; so t = R = 8*x. We know t = 16, so we have 8*x = 16 and we solve it through the following steps: Simplifying the equation: 8*x = 16. Move all terms to one side: 8*x - 16 = 0. Isolate the term with x: 8*x = 16. Divide both sides by 8: x = 16 / 8. Solution: x = 2. Answer: 2.", "op": 7, "id": "11_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of public highschool in Ruby Bay equals 1 plus the number of elementary school in Ruby Bay. The number of elementary school in Clearwater Bay equals 3 plus the difference between the number of public highschool in Riverton City and the total number of schools in Ruby Bay. The number of regional medical school in Riverton City equals 3 times the sum of the number of elementary school in Ruby Bay, the number of public highschool in Ruby Bay, and the number of regional medical school in Ruby Bay. The number of public highschool in Clearwater Bay equals 4. The number of public highschool in Riverton City equals the sum of the number of public highschool in Ruby Bay and the number of elementary school in Riverton City. The number of regional medical school in Clearwater Bay equals the difference between the number of public highschool in Clearwater Bay and the number of regional medical school in Ruby Bay. The number of elementary school in Riverton City equals the sum of the number of elementary school in Ruby Bay and the total number of schools in Ruby Bay. The number of regional medical school in Ruby Bay exists, and its number is greater than 0. The number of elementary school in Ruby Bay equals 3. The total number of schools in Ruby Bay equals 11. ", "question": "How many regional medical school does Ruby Bay have?", "solution": "The question is difficult, so we use equations to solve it. Define elementary school in Ruby Bay as Y; so Y = 3. Define public highschool in Ruby Bay as o; w = Y = 3; so o = 1 + w = 1 + 3 = 4. Define regional medical school in Ruby Bay as x; we don't know its value yet but will find it out later. Define total number of schools in Ruby Bay as r; M = o + x = 4 + x = x + 4; so r = M + Y = x + 4 + 3 = x + 7. We know r = 11, so we have x + 7 = 11 and we solve it through the following steps: Simplifying the equation: x + 7 = 11. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.", "op": 7, "id": "7_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of regional medical school in Brightford equals 2. The number of regional medical school in Westhaven City exists, and its number is greater than 0. The number of public highschool in Brightford equals the number of public highschool in Westhaven City. The number of culinarian school in Westhaven City equals 1 plus the number of public highschool in Westhaven City. The number of public highschool in Hawkesbury equals the difference between the number of regional medical school in Brightford and the number of culinarian school in Brightford. The total number of schools in Westhaven City equals 5. The number of culinarian school in Hawkesbury equals the number of public highschool in Westhaven City. The number of public highschool in Westhaven City equals 1. The number of regional medical school in Hawkesbury equals 4 times the number of regional medical school in Brightford. The number of culinarian school in Brightford equals 4 times the number of regional medical school in Brightford. ", "question": "How many regional medical school does Westhaven City have?", "solution": "The question is difficult, so we use equations to solve it. Define public highschool in Westhaven City as g; so g = 1. Define regional medical school in Westhaven City as x; we don't know its value yet but will find it out later. Define culinarian school in Westhaven City as b; l = g = 1; so b = 1 + l = 1 + 1 = 2. Define total number of schools in Westhaven City as z; W = g + b = 1 + 2 = 3; so z = W + x = 3 + x = x + 3. We know z = 5, so we have x + 3 = 5 and we solve it through the following steps: Simplifying the equation: x + 3 = 5. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "18_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of regional medical school in Shoreline City equals 4. The number of culinarian school in Ruby Bay exists, and its number is greater than 0. The total number of schools in Ruby Bay equals 11. The number of regional medical school in Ruby Bay equals 2 plus the number of public highschool in Ruby Bay. The number of culinarian school in Shoreline City equals the total number of schools in Riverton City. The number of culinarian school in Riverton City equals 2 times the sum of the number of regional medical school in Ruby Bay, the number of public highschool in Ruby Bay, and the total number of schools in Ruby Bay. The number of public highschool in Riverton City equals 3. The number of public highschool in Shoreline City equals the number of regional medical school in Shoreline City. The number of regional medical school in Riverton City equals 3. The number of public highschool in Ruby Bay equals the number of culinarian school in Ruby Bay. ", "question": "How many culinarian school does Ruby Bay have?", "solution": "The question is difficult, so we use equations to solve it. Define culinarian school in Ruby Bay as x; we don't know its value yet but will find it out later. Define public highschool in Ruby Bay as i; so i = x = x. Define regional medical school in Ruby Bay as T; e = i = x; so T = 2 + e = 2 + x = x + 2. Define total number of schools in Ruby Bay as P; V = i + T = x + x + 2 = 2*x + 2; so P = V + x = 2*x + 2 + x = 3*x + 2. We know P = 11, so we have 3*x + 2 = 11 and we solve it through the following steps: Simplifying the equation: 3*x + 2 = 11. Move all terms to one side: 3*x - 9 = 0. Isolate the term with x: 3*x = 9. Divide both sides by 3: x = 9 / 3. Solution: x = 3. Answer: 3.", "op": 7, "id": "7_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of schools in Hawkesbury equals 5. The number of culinarian school in Hawkesbury equals 1 plus the total number of schools in Brightford. The number of public highschool in Hawkesbury equals the number of public highschool in Brightford. The number of public highschool in Brightford exists, and its number is greater than 0. ", "question": "How many public highschool does Brightford have?", "solution": "The question is difficult, so we use equations to solve it. Define public highschool in Brightford as x; we don't know its value yet but will find it out later. Define total number of schools in Brightford as r; so r = x = x. Define culinarian school in Hawkesbury as D; Q = r = x; so D = 1 + Q = 1 + x = x + 1. Define public highschool in Hawkesbury as d; so d = x = x. Define total number of schools in Hawkesbury as T; so T = d + D = x + x + 1 = 2*x + 1. We know T = 5, so we have 2*x + 1 = 5 and we solve it through the following steps: Simplifying the equation: 2*x + 1 = 5. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.", "op": 7, "id": "17_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of regional medical school in Glenfield City equals the number of culinarian school in Glenfield City. The number of culinarian school in Westhaven City equals 2. The number of public highschool in Glenfield City exists, and its number is greater than 0. The number of public highschool in Evervale City equals 2. The number of culinarian school in Evervale City equals the sum of the number of public highschool in Glenfield City, the total number of schools in Westhaven City, the number of culinarian school in Glenfield City, and the number of regional medical school in Glenfield City. The number of culinarian school in Glenfield City equals the number of regional medical school in Westhaven City. The number of regional medical school in Evervale City equals 2 plus the number of culinarian school in Glenfield City. The number of public highschool in Westhaven City equals 4. The number of regional medical school in Westhaven City equals 1. The total number of schools in Glenfield City equals 5. ", "question": "How many public highschool does Glenfield City have?", "solution": "The question is difficult, so we use equations to solve it. Define regional medical school in Westhaven City as g; so g = 1. Define culinarian school in Glenfield City as y; so y = g = 1. Define public highschool in Glenfield City as x; we don't know its value yet but will find it out later. Define regional medical school in Glenfield City as l; so l = y = 1. Define total number of schools in Glenfield City as L; i = y + l = 1 + 1 = 2; so L = i + x = 2 + x = x + 2. We know L = 5, so we have x + 2 = 5 and we solve it through the following steps: Simplifying the equation: x + 2 = 5. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.", "op": 7, "id": "16_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of calm road movie in Northwood Movie Festival equals the number of solemn period drama in Northwood Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 3. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 1 plus the number of calm road movie in Golden Banana Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 1 plus the difference between the number of calm road movie in Golden Banana Movie Festival and the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of solemn period drama in Northwood Movie Festival equals the number of upbeat metropolis comedy in Northwood Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival exists, and its number is greater than 0. The total number of movies in Northwood Movie Festival equals 9. The number of upbeat metropolis comedy in Northwood Movie Festival equals the number of upbeat metropolis comedy in West Sahara Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 3. The number of upbeat metropolis comedy in West Sahara Movie Festival exists, and its number is greater than 0. ", "question": "How many upbeat metropolis comedy does West Sahara Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in West Sahara Movie Festival as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in Northwood Movie Festival as l; so l = x = x. Define solemn period drama in Northwood Movie Festival as v; so v = l = x. Define calm road movie in Northwood Movie Festival as D; so D = v = x. Define total number of movies in Northwood Movie Festival as Q; S = v + D = x + x = 2*x; so Q = S + l = 2*x + x = 3*x. We know Q = 9, so we have 3*x = 9 and we solve it through the following steps: Simplifying the equation: 3*x = 9. Move all terms to one side: 3*x - 9 = 0. Isolate the term with x: 3*x = 9. Divide both sides by 3: x = 9 / 3. Solution: x = 3. Answer: 3.", "op": 7, "id": "20_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of regional medical school in Evervale City equals the number of culinarian school in Glenfield City. The number of regional medical school in Westhaven City equals the difference between the number of regional medical school in Glenfield City and the total number of schools in Glenfield City. The total number of schools in Glenfield City equals 8. The number of elementary school in Evervale City equals 1 plus the number of culinarian school in Westhaven City. The number of elementary school in Glenfield City equals 2 plus the number of culinarian school in Glenfield City. The number of culinarian school in Westhaven City equals 1. The number of regional medical school in Glenfield City equals the number of culinarian school in Glenfield City. The number of elementary school in Westhaven City equals 3 plus the number of culinarian school in Glenfield City. The number of culinarian school in Evervale City equals 3 plus the number of regional medical school in Glenfield City. The number of culinarian school in Glenfield City exists, and its number is greater than 0. ", "question": "How many culinarian school does Glenfield City have?", "solution": "The question is difficult, so we use equations to solve it. Define culinarian school in Glenfield City as x; we don't know its value yet but will find it out later. Define regional medical school in Glenfield City as H; so H = x = x. Define elementary school in Glenfield City as T; n = x = x; so T = 2 + n = 2 + x = x + 2. Define total number of schools in Glenfield City as v; r = T + x = x + 2 + x = 2*x + 2; so v = r + H = 2*x + 2 + x = 3*x + 2. We know v = 8, so we have 3*x + 2 = 8 and we solve it through the following steps: Simplifying the equation: 3*x + 2 = 8. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.", "op": 7, "id": "2_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult deer in Mayer Aquarium equals 2 times the total number of adult animals in Hamilton Farm. The number of adult racoon in Hamilton Farm exists, and its number is greater than 0. The total number of adult animals in Mayer Aquarium equals 12. The number of adult deer in Hamilton Farm equals 2. ", "question": "How many adult racoon does Hamilton Farm have?", "solution": "The question is difficult, so we use equations to solve it. Define adult deer in Hamilton Farm as t; so t = 2. Define adult racoon in Hamilton Farm as x; we don't know its value yet but will find it out later. Define total number of adult animals in Hamilton Farm as C; so C = t + x = 2 + x = x + 2. Define adult deer in Mayer Aquarium as k; Z = C = x + 2; so k = 2 * Z = (2) * (x + 2) = 2*x + 4. Define total number of adult animals in Mayer Aquarium as l; so l = k = 2*x + 4. We know l = 12, so we have 2*x + 4 = 12 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 12. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.", "op": 7, "id": "8_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult bear in Bundle Ranch equals the total number of adult animals in Jefferson Circus. The total number of adult animals in Hamilton Farm equals 6. The number of adult wolf in Jefferson Circus exists, and its number is greater than 0. The number of adult deer in Hamilton Farm equals 3 plus the total number of adult animals in Bundle Ranch. ", "question": "How many adult wolf does Jefferson Circus have?", "solution": "The question is difficult, so we use equations to solve it. Define adult wolf in Jefferson Circus as x; we don't know its value yet but will find it out later. Define total number of adult animals in Jefferson Circus as k; so k = x = x. Define adult bear in Bundle Ranch as Z; so Z = k = x. Define total number of adult animals in Bundle Ranch as H; so H = Z = x. Define adult deer in Hamilton Farm as m; F = H = x; so m = 3 + F = 3 + x = x + 3. Define total number of adult animals in Hamilton Farm as q; so q = m = x + 3. We know q = 6, so we have x + 3 = 6 and we solve it through the following steps: Simplifying the equation: x + 3 = 6. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.", "op": 7, "id": "14_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of schools in Hawkesbury equals 14. The number of public highschool in Evervale City equals 3 plus the sum of the number of culinarian school in Westhaven City, the number of regional medical school in Evervale City, and the number of culinarian school in Hawkesbury. The number of culinarian school in Hawkesbury equals 3. The number of public highschool in Hawkesbury equals the sum of the number of culinarian school in Hawkesbury and the number of regional medical school in Hawkesbury. The number of culinarian school in Westhaven City equals 3 times the number of culinarian school in Evervale City. The number of regional medical school in Westhaven City equals the total number of schools in Hawkesbury. The number of regional medical school in Evervale City equals 2 plus the number of culinarian school in Hawkesbury. The number of regional medical school in Hawkesbury exists, and its number is greater than 0. The number of culinarian school in Evervale City equals 1. ", "question": "How many regional medical school does Hawkesbury have?", "solution": "The question is difficult, so we use equations to solve it. Define culinarian school in Hawkesbury as I; so I = 3. Define regional medical school in Hawkesbury as x; we don't know its value yet but will find it out later. Define public highschool in Hawkesbury as t; so t = I + x = 3 + x = x + 3. Define total number of schools in Hawkesbury as F; D = I + x = 3 + x = x + 3; so F = D + t = x + 3 + x + 3 = 2*x + 6. We know F = 14, so we have 2*x + 6 = 14 and we solve it through the following steps: Simplifying the equation: 2*x + 6 = 14. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.", "op": 7, "id": "11_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult blue jay in Maple Creek equals 2. The number of adult crow in Oakridge Riverside equals the number of adult blue jay in Oakridge Riverside. The number of adult blue jay in Oakridge Riverside equals 1 plus the number of adult parrot in Oakridge Riverside. The number of adult parrot in Oakridge Riverside exists, and its number is greater than 0. The number of adult parrot in Maple Creek equals 2. The total number of adult animals in Oakridge Riverside equals 11. The number of adult crow in Pine Ridge equals 4 plus the number of adult blue jay in Maple Creek. ", "question": "How many adult parrot does Oakridge Riverside have?", "solution": "The question is difficult, so we use equations to solve it. Define adult parrot in Oakridge Riverside as x; we don't know its value yet but will find it out later. Define adult blue jay in Oakridge Riverside as Y; e = x = x; so Y = 1 + e = 1 + x = x + 1. Define adult crow in Oakridge Riverside as R; so R = Y = x + 1. Define total number of adult animals in Oakridge Riverside as G; k = x + Y = x + x + 1 = 2*x + 1; so G = k + R = 2*x + 1 + x + 1 = 3*x + 2. We know G = 11, so we have 3*x + 2 = 11 and we solve it through the following steps: Simplifying the equation: 3*x + 2 = 11. Move all terms to one side: 3*x - 9 = 0. Isolate the term with x: 3*x = 9. Divide both sides by 3: x = 9 / 3. Solution: x = 3. Answer: 3.", "op": 7, "id": "4_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of intense detective thriller in Verdi Movie Festival equals 2. The number of futuristic sci-fi movie in Taylor Movie Festival exists, and its number is greater than 0. The number of intense detective thriller in Northwood Movie Festival equals 4 times the number of futuristic sci-fi movie in Northwood Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 3. The number of upbeat metropolis comedy in Northwood Movie Festival equals 4 times the sum of the number of futuristic sci-fi movie in Taylor Movie Festival and the number of intense detective thriller in Taylor Movie Festival. The total number of movies in Taylor Movie Festival equals 11. The number of upbeat metropolis comedy in Taylor Movie Festival equals 3 plus the number of intense detective thriller in Taylor Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals 1. The number of futuristic sci-fi movie in Verdi Movie Festival equals the number of intense detective thriller in Northwood Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals 1. ", "question": "How many futuristic sci-fi movie does Taylor Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define intense detective thriller in Taylor Movie Festival as C; so C = 3. Define futuristic sci-fi movie in Taylor Movie Festival as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in Taylor Movie Festival as z; r = C = 3; so z = 3 + r = 3 + 3 = 6. Define total number of movies in Taylor Movie Festival as q; v = z + x = 6 + x = x + 6; so q = v + C = x + 6 + 3 = x + 9. We know q = 11, so we have x + 9 = 11 and we solve it through the following steps: Simplifying the equation: x + 9 = 11. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "3_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of private middle school in Riverton City equals 1 plus the number of public highschool in Riverton City. The total number of schools in Riverton City equals 11. The number of public highschool in Riverton City equals 4. The number of private middle school in Shoreline City equals 1 plus the sum of the number of public highschool in Riverton City and the number of private middle school in Riverton City. The number of public highschool in Shoreline City equals 3. The number of elementary school in Riverton City exists, and its number is greater than 0. The number of private middle school in Clearwater Bay equals 1 plus the number of public highschool in Shoreline City. The number of elementary school in Clearwater Bay equals 2. The number of public highschool in Clearwater Bay equals the difference between the number of private middle school in Clearwater Bay and the number of public highschool in Shoreline City. The number of elementary school in Shoreline City equals 2. ", "question": "How many elementary school does Riverton City have?", "solution": "The question is difficult, so we use equations to solve it. Define public highschool in Riverton City as b; so b = 4. Define private middle school in Riverton City as p; h = b = 4; so p = 1 + h = 1 + 4 = 5. Define elementary school in Riverton City as x; we don't know its value yet but will find it out later. Define total number of schools in Riverton City as Z; U = b + p = 4 + 5 = 9; so Z = U + x = 9 + x = x + 9. We know Z = 11, so we have x + 9 = 11 and we solve it through the following steps: Simplifying the equation: x + 9 = 11. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "1_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of private middle school in Glenfield City equals the number of elementary school in Hawkesbury. The number of elementary school in Hawkesbury equals 2. The number of elementary school in Westhaven City equals 3. The number of private middle school in Hawkesbury equals 2. The number of private middle school in Westhaven City exists, and its number is greater than 0. The number of public highschool in Westhaven City equals the sum of the number of private middle school in Westhaven City and the number of elementary school in Westhaven City. The total number of schools in Westhaven City equals 12. ", "question": "How many private middle school does Westhaven City have?", "solution": "The question is difficult, so we use equations to solve it. Define elementary school in Westhaven City as n; so n = 3. Define private middle school in Westhaven City as x; we don't know its value yet but will find it out later. Define public highschool in Westhaven City as o; so o = x + n = x + 3 = x + 3. Define total number of schools in Westhaven City as E; m = o + x = x + 3 + x = 2*x + 3; so E = m + n = 2*x + 3 + 3 = 2*x + 6. We know E = 12, so we have 2*x + 6 = 12 and we solve it through the following steps: Simplifying the equation: 2*x + 6 = 12. Move all terms to one side: 2*x - 6 = 0. Isolate the term with x: 2*x = 6. Divide both sides by 2: x = 6 / 2. Solution: x = 3. Answer: 3.", "op": 7, "id": "2_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in Festival Lumi\u00e8re de Valmont equals the number of upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont. The number of solemn period drama in R\u00eaves de Belleville equals the number of upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont. The number of upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont exists, and its number is greater than 0. The total number of movies in R\u00eaves de Belleville equals 10. The number of upbeat metropolis comedy in R\u00eaves de Belleville equals 4 times the number of solemn period drama in Festival Lumi\u00e8re de Valmont. ", "question": "How many upbeat metropolis comedy does Festival Lumi\u00e8re de Valmont have?", "solution": "The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont as x; we don't know its value yet but will find it out later. Define solemn period drama in Festival Lumi\u00e8re de Valmont as J; so J = x = x. Define upbeat metropolis comedy in R\u00eaves de Belleville as H; L = J = x; so H = 4 * L = (4) * (x) = 4*x. Define solemn period drama in R\u00eaves de Belleville as C; so C = x = x. Define total number of movies in R\u00eaves de Belleville as Z; so Z = H + C = 4*x + x = 5*x. We know Z = 10, so we have 5*x = 10 and we solve it through the following steps: Simplifying the equation: 5*x = 10. Move all terms to one side: 5*x - 10 = 0. Isolate the term with x: 5*x = 10. Divide both sides by 5: x = 10 / 5. Solution: x = 2. Answer: 2.", "op": 7, "id": "16_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of intense detective thriller in Northwood Movie Festival equals 2 times the number of intense detective thriller in Golden Banana Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 2 times the number of intense detective thriller in Taylor Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 4 plus the sum of the number of solemn period drama in Northwood Movie Festival and the number of solemn period drama in Golden Banana Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 10. The number of solemn period drama in Golden Banana Movie Festival exists, and its number is greater than 0. The number of futuristic sci-fi movie in Northwood Movie Festival equals 3 plus the difference between the number of solemn period drama in Northwood Movie Festival and the total number of movies in Golden Banana Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals 2. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 3. The number of intense detective thriller in Taylor Movie Festival equals the number of solemn period drama in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Taylor Movie Festival equals 3 times the number of futuristic sci-fi movie in Northwood Movie Festival. ", "question": "How many solemn period drama does Golden Banana Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define solemn period drama in Golden Banana Movie Festival as x; we don't know its value yet but will find it out later. Define intense detective thriller in Taylor Movie Festival as J; so J = x = x. Define solemn period drama in Northwood Movie Festival as e; Z = J = x; so e = 2 * Z = (2) * (x) = 2*x. Define solemn period drama in Taylor Movie Festival as q; H = e + x = 2*x + x = 3*x; so q = 4 + H = 4 + 3*x = 3*x + 4. We know q = 10, so we have 3*x + 4 = 10 and we solve it through the following steps: Simplifying the equation: 3*x + 4 = 10. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.", "op": 7, "id": "11_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of adult animals in Beverly Forest equals 10. The number of adult wolf in Cedar Valley exists, and its number is greater than 0. The number of adult wolf in Beverly Forest equals 1 plus the total number of adult animals in Cedar Valley. The number of adult fox in Beverly Forest equals the number of adult wolf in Beverly Forest. ", "question": "How many adult wolf does Cedar Valley have?", "solution": "The question is difficult, so we use equations to solve it. Define adult wolf in Cedar Valley as x; we don't know its value yet but will find it out later. Define total number of adult animals in Cedar Valley as J; so J = x = x. Define adult wolf in Beverly Forest as K; m = J = x; so K = 1 + m = 1 + x = x + 1. Define adult fox in Beverly Forest as a; so a = K = x + 1. Define total number of adult animals in Beverly Forest as t; so t = K + a = x + 1 + x + 1 = 2*x + 2. We know t = 10, so we have 2*x + 2 = 10 and we solve it through the following steps: Simplifying the equation: 2*x + 2 = 10. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.", "op": 7, "id": "18_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of public highschool in Ruby Bay exists, and its number is greater than 0. The number of public highschool in Riverton City equals 3. The total number of schools in Ruby Bay equals 36. The number of culinarian school in Shoreline City equals 2. The number of private middle school in Riverton City equals 4 times the sum of the number of culinarian school in Ruby Bay and the number of public highschool in Ruby Bay. The number of private middle school in Shoreline City equals the sum of the number of culinarian school in Ruby Bay, the number of culinarian school in Riverton City, and the total number of schools in Riverton City. The number of culinarian school in Riverton City equals 1 plus the sum of the number of private middle school in Riverton City, the number of culinarian school in Ruby Bay, and the total number of schools in Ruby Bay. The number of culinarian school in Ruby Bay equals the number of private middle school in Ruby Bay. The number of public highschool in Shoreline City equals 1 plus the total number of schools in Ruby Bay. The number of private middle school in Ruby Bay equals 4 times the number of public highschool in Ruby Bay. ", "question": "How many public highschool does Ruby Bay have?", "solution": "The question is difficult, so we use equations to solve it. Define public highschool in Ruby Bay as x; we don't know its value yet but will find it out later. Define private middle school in Ruby Bay as Z; B = x = x; so Z = 4 * B = (4) * (x) = 4*x. Define culinarian school in Ruby Bay as T; so T = Z = 4*x. Define total number of schools in Ruby Bay as q; r = T + Z = 4*x + 4*x = 8*x; so q = r + x = 8*x + x = 9*x. We know q = 36, so we have 9*x = 36 and we solve it through the following steps: Simplifying the equation: 9*x = 36. Move all terms to one side: 9*x - 36 = 0. Isolate the term with x: 9*x = 36. Divide both sides by 9: x = 36 / 9. Solution: x = 4. Answer: 4.", "op": 7, "id": "4_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult parrot in Pine Ridge exists, and its number is greater than 0. The total number of adult animals in Cedar Valley equals 4. The number of adult parrot in Beverly Forest equals 2 plus the total number of adult animals in Pine Ridge. The number of adult eagle in Cedar Valley equals the total number of adult animals in Beverly Forest. ", "question": "How many adult parrot does Pine Ridge have?", "solution": "The question is difficult, so we use equations to solve it. Define adult parrot in Pine Ridge as x; we don't know its value yet but will find it out later. Define total number of adult animals in Pine Ridge as a; so a = x = x. Define adult parrot in Beverly Forest as A; v = a = x; so A = 2 + v = 2 + x = x + 2. Define total number of adult animals in Beverly Forest as W; so W = A = x + 2. Define adult eagle in Cedar Valley as j; so j = W = x + 2. Define total number of adult animals in Cedar Valley as r; so r = j = x + 2. We know r = 4, so we have x + 2 = 4 and we solve it through the following steps: Simplifying the equation: x + 2 = 4. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "16_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of intense detective thriller in Verdi Movie Festival equals 2. The number of upbeat metropolis comedy in Verdi Movie Festival equals 1 plus the number of intense detective thriller in Verdi Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 2 plus the number of intense detective thriller in Golden Banana Movie Festival. The number of solemn period drama in Verdi Movie Festival exists, and its number is greater than 0. The number of intense detective thriller in Golden Banana Movie Festival equals 4. The number of solemn period drama in Taylor Movie Festival equals the number of solemn period drama in Verdi Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 4. The total number of movies in Verdi Movie Festival equals 6. The number of upbeat metropolis comedy in Taylor Movie Festival equals the number of intense detective thriller in Golden Banana Movie Festival. ", "question": "How many solemn period drama does Verdi Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define intense detective thriller in Verdi Movie Festival as W; so W = 2. Define upbeat metropolis comedy in Verdi Movie Festival as t; o = W = 2; so t = 1 + o = 1 + 2 = 3. Define solemn period drama in Verdi Movie Festival as x; we don't know its value yet but will find it out later. Define total number of movies in Verdi Movie Festival as j; q = x + W = x + 2 = x + 2; so j = q + t = x + 2 + 3 = x + 5. We know j = 6, so we have x + 5 = 6 and we solve it through the following steps: Simplifying the equation: x + 5 = 6. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1.", "op": 7, "id": "11_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of public highschool in Evervale City equals the number of public highschool in Westhaven City. The number of culinarian school in Westhaven City equals 3 plus the number of private middle school in Westhaven City. The number of private middle school in Westhaven City exists, and its number is greater than 0. The total number of schools in Westhaven City equals 12. The number of public highschool in Westhaven City equals the number of private middle school in Westhaven City. The number of public highschool in Hawkesbury equals 2 times the number of culinarian school in Evervale City. The number of culinarian school in Evervale City equals 3. The number of private middle school in Hawkesbury equals 3 plus the sum of the number of private middle school in Westhaven City, the number of culinarian school in Westhaven City, and the total number of schools in Westhaven City. ", "question": "How many private middle school does Westhaven City have?", "solution": "The question is difficult, so we use equations to solve it. Define private middle school in Westhaven City as x; we don't know its value yet but will find it out later. Define public highschool in Westhaven City as J; so J = x = x. Define culinarian school in Westhaven City as H; j = x = x; so H = 3 + j = 3 + x = x + 3. Define total number of schools in Westhaven City as B; V = x + J = x + x = 2*x; so B = V + H = 2*x + x + 3 = 3*x + 3. We know B = 12, so we have 3*x + 3 = 12 and we solve it through the following steps: Simplifying the equation: 3*x + 3 = 12. Move all terms to one side: 3*x - 9 = 0. Isolate the term with x: 3*x = 9. Divide both sides by 3: x = 9 / 3. Solution: x = 3. Answer: 3.", "op": 7, "id": "0_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult owl in Bundle Ranch equals 2 plus the number of adult blue jay in Bundle Ranch. The number of adult crow in Jefferson Circus equals 4 plus the number of adult blue jay in Mayer Aquarium. The number of adult crow in Bundle Ranch equals the number of adult blue jay in Bundle Ranch. The number of adult owl in Mayer Aquarium equals the difference between the number of adult owl in Jefferson Circus and the total number of adult animals in Bundle Ranch. The number of adult blue jay in Mayer Aquarium equals 4. The number of adult blue jay in Jefferson Circus equals 3. The total number of adult animals in Bundle Ranch equals 11. The number of adult owl in Jefferson Circus equals 4. The number of adult crow in Mayer Aquarium equals 3 plus the sum of the number of adult blue jay in Mayer Aquarium, the total number of adult animals in Mayer Aquarium, and the number of adult owl in Mayer Aquarium. The number of adult blue jay in Bundle Ranch exists, and its number is greater than 0. ", "question": "How many adult blue jay does Bundle Ranch have?", "solution": "The question is difficult, so we use equations to solve it. Define adult blue jay in Bundle Ranch as x; we don't know its value yet but will find it out later. Define adult owl in Bundle Ranch as v; Q = x = x; so v = 2 + Q = 2 + x = x + 2. Define adult crow in Bundle Ranch as h; so h = x = x. Define total number of adult animals in Bundle Ranch as P; i = x + h = x + x = 2*x; so P = i + v = 2*x + x + 2 = 3*x + 2. We know P = 11, so we have 3*x + 2 = 11 and we solve it through the following steps: Simplifying the equation: 3*x + 2 = 11. Move all terms to one side: 3*x - 9 = 0. Isolate the term with x: 3*x = 9. Divide both sides by 3: x = 9 / 3. Solution: x = 3. Answer: 3.", "op": 7, "id": "4_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of movies in Golden Banana Movie Festival equals 12. The number of intense detective thriller in Golden Banana Movie Festival equals 3 plus the number of calm road movie in Golden Banana Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 2. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 2. The number of intense detective thriller in West Sahara Movie Festival equals 4. The number of calm road movie in Verdi Movie Festival equals 4 times the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of calm road movie in West Sahara Movie Festival equals the total number of movies in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival exists, and its number is greater than 0. The number of calm road movie in Golden Banana Movie Festival equals 3. The number of upbeat metropolis comedy in Verdi Movie Festival equals the total number of movies in Golden Banana Movie Festival. ", "question": "How many upbeat metropolis comedy does Golden Banana Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define calm road movie in Golden Banana Movie Festival as Y; so Y = 3. Define upbeat metropolis comedy in Golden Banana Movie Festival as x; we don't know its value yet but will find it out later. Define intense detective thriller in Golden Banana Movie Festival as g; F = Y = 3; so g = 3 + F = 3 + 3 = 6. Define total number of movies in Golden Banana Movie Festival as N; d = x + g = x + 6 = x + 6; so N = d + Y = x + 6 + 3 = x + 9. We know N = 12, so we have x + 9 = 12 and we solve it through the following steps: Simplifying the equation: x + 9 = 12. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.", "op": 7, "id": "22_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of adult animals in South Zoo equals 24. The number of adult owl in South Zoo equals 3 times the number of adult blue jay in Mayer Aquarium. The number of adult blue jay in South Zoo equals 3 times the number of adult blue jay in Mayer Aquarium. The number of adult parrot in Mayer Aquarium equals 1 plus the sum of the total number of adult animals in South Zoo, the number of adult owl in Jefferson Circus, and the number of adult parrot in Jefferson Circus. The number of adult owl in Mayer Aquarium equals the sum of the number of adult parrot in Mayer Aquarium, the number of adult blue jay in South Zoo, and the number of adult owl in Jefferson Circus. The number of adult blue jay in Mayer Aquarium exists, and its number is greater than 0. The number of adult owl in Jefferson Circus equals 2. The number of adult parrot in Jefferson Circus equals 2. ", "question": "How many adult blue jay does Mayer Aquarium have?", "solution": "The question is difficult, so we use equations to solve it. Define adult blue jay in Mayer Aquarium as x; we don't know its value yet but will find it out later. Define adult owl in South Zoo as P; u = x = x; so P = 3 * u = (3) * (x) = 3*x. Define adult blue jay in South Zoo as k; C = x = x; so k = 3 * C = (3) * (x) = 3*x. Define total number of adult animals in South Zoo as s; so s = P + k = 3*x + 3*x = 6*x. We know s = 24, so we have 6*x = 24 and we solve it through the following steps: Simplifying the equation: 6*x = 24. Move all terms to one side: 6*x - 24 = 0. Isolate the term with x: 6*x = 24. Divide both sides by 6: x = 24 / 6. Solution: x = 4. Answer: 4.", "op": 7, "id": "2_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult parrot in Oakridge Riverside exists, and its number is greater than 0. The number of adult owl in Beverly Forest equals 2 times the number of adult parrot in Oakridge Riverside. The number of adult crow in Beverly Forest equals 1. The total number of adult animals in Maple Creek equals 6. The number of adult parrot in Maple Creek equals 3 plus the difference between the number of adult owl in Beverly Forest and the number of adult parrot in Oakridge Riverside. ", "question": "How many adult parrot does Oakridge Riverside have?", "solution": "The question is difficult, so we use equations to solve it. Define adult parrot in Oakridge Riverside as x; we don't know its value yet but will find it out later. Define adult owl in Beverly Forest as E; s = x = x; so E = 2 * s = (2) * (x) = 2*x. Define adult parrot in Maple Creek as j; D = E - x = (2*x) - (x) = x; so j = 3 + D = 3 + x = x + 3. Define total number of adult animals in Maple Creek as v; so v = j = x + 3. We know v = 6, so we have x + 3 = 6 and we solve it through the following steps: Simplifying the equation: x + 3 = 6. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.", "op": 7, "id": "6_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of futuristic sci-fi movie in West Sahara Movie Festival equals 2 plus the number of upbeat metropolis comedy in West Sahara Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 2. The number of futuristic sci-fi movie in Northwood Movie Festival equals 2. The number of calm road movie in Northwood Movie Festival equals the total number of movies in Golden Banana Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals the number of futuristic sci-fi movie in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Golden Banana Movie Festival exists, and its number is greater than 0. The total number of movies in Golden Banana Movie Festival equals 8. The number of upbeat metropolis comedy in Northwood Movie Festival equals the sum of the number of futuristic sci-fi movie in Golden Banana Movie Festival, the number of upbeat metropolis comedy in Golden Banana Movie Festival, and the number of calm road movie in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the sum of the number of calm road movie in Golden Banana Movie Festival and the number of futuristic sci-fi movie in Golden Banana Movie Festival. The number of calm road movie in West Sahara Movie Festival equals the number of upbeat metropolis comedy in Golden Banana Movie Festival. ", "question": "How many futuristic sci-fi movie does Golden Banana Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Golden Banana Movie Festival as x; we don't know its value yet but will find it out later. Define calm road movie in Golden Banana Movie Festival as H; so H = x = x. Define upbeat metropolis comedy in Golden Banana Movie Festival as S; so S = H + x = x + x = 2*x. Define total number of movies in Golden Banana Movie Festival as y; v = S + x = 2*x + x = 3*x; so y = v + H = 3*x + x = 4*x. We know y = 8, so we have 4*x = 8 and we solve it through the following steps: Simplifying the equation: 4*x = 8. Move all terms to one side: 4*x - 8 = 0. Isolate the term with x: 4*x = 8. Divide both sides by 4: x = 8 / 4. Solution: x = 2. Answer: 2.", "op": 7, "id": "15_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of movies in West Sahara Movie Festival equals 3. The number of intense detective thriller in Northwood Movie Festival equals the number of intense detective thriller in Verdi Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 4. The number of futuristic sci-fi movie in Northwood Movie Festival equals 4. The number of intense detective thriller in Verdi Movie Festival equals 2. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the number of futuristic sci-fi movie in West Sahara Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals the number of intense detective thriller in West Sahara Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals the number of upbeat metropolis comedy in Verdi Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival exists, and its number is greater than 0. ", "question": "How many upbeat metropolis comedy does Verdi Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in Verdi Movie Festival as x; we don't know its value yet but will find it out later. Define intense detective thriller in West Sahara Movie Festival as K; so K = x = x. Define futuristic sci-fi movie in West Sahara Movie Festival as u; so u = K = x. Define upbeat metropolis comedy in West Sahara Movie Festival as i; so i = u = x. Define total number of movies in West Sahara Movie Festival as D; f = i + u = x + x = 2*x; so D = f + K = 2*x + x = 3*x. We know D = 3, so we have 3*x = 3 and we solve it through the following steps: Simplifying the equation: 3*x = 3. Move all terms to one side: 3*x - 3 = 0. Isolate the term with x: 3*x = 3. Divide both sides by 3: x = 3 / 3. Solution: x = 1. Answer: 1.", "op": 7, "id": "6_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult deer in Cedar Valley exists, and its number is greater than 0. The number of adult racoon in Oakridge Riverside equals 3. The number of adult deer in Maple Creek equals 2. The number of adult deer in Oakridge Riverside equals 2 plus the number of adult racoon in Maple Creek. The number of adult wolf in Cedar Valley equals the number of adult deer in Cedar Valley. The number of adult wolf in Oakridge Riverside equals 2 times the number of adult deer in Maple Creek. The number of adult racoon in Maple Creek equals 4 times the sum of the number of adult deer in Cedar Valley, the number of adult wolf in Cedar Valley, and the number of adult racoon in Oakridge Riverside. The number of adult racoon in Cedar Valley equals 3 times the number of adult wolf in Cedar Valley. The number of adult wolf in Maple Creek equals 1 plus the number of adult racoon in Oakridge Riverside. The total number of adult animals in Cedar Valley equals 20. ", "question": "How many adult deer does Cedar Valley have?", "solution": "The question is difficult, so we use equations to solve it. Define adult deer in Cedar Valley as x; we don't know its value yet but will find it out later. Define adult wolf in Cedar Valley as t; so t = x = x. Define adult racoon in Cedar Valley as d; m = t = x; so d = 3 * m = (3) * (x) = 3*x. Define total number of adult animals in Cedar Valley as A; U = t + d = x + 3*x = 4*x; so A = U + x = 4*x + x = 5*x. We know A = 20, so we have 5*x = 20 and we solve it through the following steps: Simplifying the equation: 5*x = 20. Move all terms to one side: 5*x - 20 = 0. Isolate the term with x: 5*x = 20. Divide both sides by 5: x = 20 / 5. Solution: x = 4. Answer: 4.", "op": 7, "id": "9_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of regional medical school in Ruby Bay equals 3. The number of regional medical school in Riverton City exists, and its number is greater than 0. The number of public highschool in Riverton City equals the sum of the total number of schools in Ruby Bay and the number of regional medical school in Ruby Bay. The total number of schools in Riverton City equals 7. ", "question": "How many regional medical school does Riverton City have?", "solution": "The question is difficult, so we use equations to solve it. Define regional medical school in Ruby Bay as Z; so Z = 3. Define total number of schools in Ruby Bay as i; so i = Z = 3. Define public highschool in Riverton City as O; so O = i + Z = 3 + 3 = 6. Define regional medical school in Riverton City as x; we don't know its value yet but will find it out later. Define total number of schools in Riverton City as f; so f = x + O = x + 6 = x + 6. We know f = 7, so we have x + 6 = 7 and we solve it through the following steps: Simplifying the equation: x + 6 = 7. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1.", "op": 7, "id": "11_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of elementary school in Hawkesbury equals the number of culinarian school in Brightford. The number of elementary school in Glenfield City equals 4 times the number of culinarian school in Glenfield City. The number of culinarian school in Hawkesbury equals 2 plus the number of elementary school in Brightford. The number of public highschool in Hawkesbury equals 4. The number of public highschool in Brightford equals 4. The number of culinarian school in Glenfield City exists, and its number is greater than 0. The number of elementary school in Brightford equals 4. The number of public highschool in Glenfield City equals the number of culinarian school in Glenfield City. The number of culinarian school in Brightford equals the number of culinarian school in Hawkesbury. The total number of schools in Glenfield City equals 18. ", "question": "How many culinarian school does Glenfield City have?", "solution": "The question is difficult, so we use equations to solve it. Define culinarian school in Glenfield City as x; we don't know its value yet but will find it out later. Define elementary school in Glenfield City as W; Y = x = x; so W = 4 * Y = (4) * (x) = 4*x. Define public highschool in Glenfield City as B; so B = x = x. Define total number of schools in Glenfield City as k; p = W + B = 4*x + x = 5*x; so k = p + x = 5*x + x = 6*x. We know k = 18, so we have 6*x = 18 and we solve it through the following steps: Simplifying the equation: 6*x = 18. Move all terms to one side: 6*x - 18 = 0. Isolate the term with x: 6*x = 18. Divide both sides by 6: x = 18 / 6. Solution: x = 3. Answer: 3.", "op": 7, "id": "19_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult eagle in Pine Ridge equals 2 plus the sum of the number of adult crow in Beverly Forest and the total number of adult animals in Maple Creek. The number of adult parrot in Pine Ridge equals the difference between the total number of adult animals in Maple Creek and the total number of adult animals in Cedar Valley. The number of adult owl in Maple Creek equals 4. The number of adult crow in Pine Ridge equals the number of adult eagle in Beverly Forest. The number of adult eagle in Oakridge Riverside equals the number of adult crow in Beverly Forest. The number of adult owl in Oakridge Riverside equals 2 plus the sum of the total number of adult animals in Cedar Valley, the number of adult eagle in Cedar Valley, and the total number of adult animals in Beverly Forest. The number of adult eagle in Cedar Valley equals 3. The number of adult blue jay in Oakridge Riverside equals 3 times the difference between the number of adult eagle in Beverly Forest and the number of adult crow in Pine Ridge. The number of adult eagle in Maple Creek equals 4. The number of adult eagle in Beverly Forest equals 3. The number of adult crow in Beverly Forest equals 4 plus the sum of the number of adult parrot in Cedar Valley, the number of adult parrot in Maple Creek, and the total number of adult animals in Maple Creek. The number of adult blue jay in Beverly Forest equals the sum of the total number of adult animals in Maple Creek and the number of adult eagle in Maple Creek. The number of adult parrot in Cedar Valley equals 3 plus the number of adult eagle in Cedar Valley. The number of adult parrot in Maple Creek equals 3 times the total number of adult animals in Cedar Valley. ", "question": "How many adult parrot does Maple Creek have?", "solution": "Define adult eagle in Cedar Valley as e; so e = 3. Define adult parrot in Cedar Valley as H; K = e = 3; so H = 3 + K = 3 + 3 = 6. Define total number of adult animals in Cedar Valley as C; so C = e + H = 3 + 6 = 9. Define adult parrot in Maple Creek as Q; z = C = 9; so Q = 3 * z = 3 * 9 = 27. Answer: 27.", "op": 7, "id": "11_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 1 plus the total number of movies in Cin\u00e9ma de Montreval. The total number of movies in Festival de Saint-Rivage equals 5. The number of calm road movie in Festival de Saint-Rivage equals the number of upbeat metropolis comedy in Cin\u00e9ma de Montreval. The number of upbeat metropolis comedy in Cin\u00e9ma de Montreval exists, and its number is greater than 0. ", "question": "How many upbeat metropolis comedy does Cin\u00e9ma de Montreval have?", "solution": "The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in Cin\u00e9ma de Montreval as x; we don't know its value yet but will find it out later. Define total number of movies in Cin\u00e9ma de Montreval as E; so E = x = x. Define upbeat metropolis comedy in Festival de Saint-Rivage as q; e = E = x; so q = 1 + e = 1 + x = x + 1. Define calm road movie in Festival de Saint-Rivage as C; so C = x = x. Define total number of movies in Festival de Saint-Rivage as c; so c = q + C = x + 1 + x = 2*x + 1. We know c = 5, so we have 2*x + 1 = 5 and we solve it through the following steps: Simplifying the equation: 2*x + 1 = 5. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.", "op": 7, "id": "6_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of intense detective thriller in Verdi Movie Festival equals the sum of the number of calm road movie in Taylor Movie Festival and the number of solemn period drama in Verdi Movie Festival. The number of solemn period drama in West Sahara Movie Festival exists, and its number is greater than 0. The number of calm road movie in Verdi Movie Festival equals 2. The number of intense detective thriller in West Sahara Movie Festival equals 2 times the number of solemn period drama in West Sahara Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 3 times the number of calm road movie in Taylor Movie Festival. The total number of movies in West Sahara Movie Festival equals 8. The number of intense detective thriller in Taylor Movie Festival equals the number of intense detective thriller in West Sahara Movie Festival. The number of solemn period drama in Taylor Movie Festival equals the sum of the number of calm road movie in Taylor Movie Festival, the number of intense detective thriller in West Sahara Movie Festival, and the number of calm road movie in West Sahara Movie Festival. The number of calm road movie in Taylor Movie Festival equals 2. The number of calm road movie in West Sahara Movie Festival equals the number of solemn period drama in West Sahara Movie Festival. ", "question": "How many solemn period drama does West Sahara Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define solemn period drama in West Sahara Movie Festival as x; we don't know its value yet but will find it out later. Define intense detective thriller in West Sahara Movie Festival as m; n = x = x; so m = 2 * n = (2) * (x) = 2*x. Define calm road movie in West Sahara Movie Festival as l; so l = x = x. Define total number of movies in West Sahara Movie Festival as K; v = x + m = x + 2*x = 3*x; so K = v + l = 3*x + x = 4*x. We know K = 8, so we have 4*x = 8 and we solve it through the following steps: Simplifying the equation: 4*x = 8. Move all terms to one side: 4*x - 8 = 0. Isolate the term with x: 4*x = 8. Divide both sides by 4: x = 8 / 4. Solution: x = 2. Answer: 2.", "op": 7, "id": "19_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult blue jay in Maple Creek equals the number of adult owl in Beverly Forest. The number of adult blue jay in Beverly Forest equals 4 times the number of adult owl in Maple Creek. The number of adult eagle in Maple Creek equals 3 plus the sum of the number of adult eagle in Pine Ridge, the total number of adult animals in Pine Ridge, and the number of adult owl in Beverly Forest. The number of adult eagle in Beverly Forest equals 4. The number of adult eagle in Pine Ridge exists, and its number is greater than 0. The number of adult owl in Maple Creek equals 2 times the difference between the number of adult eagle in Beverly Forest and the number of adult owl in Beverly Forest. The number of adult owl in Pine Ridge equals 1 plus the number of adult blue jay in Pine Ridge. The number of adult blue jay in Pine Ridge equals the number of adult eagle in Pine Ridge. The number of adult owl in Beverly Forest equals the number of adult eagle in Beverly Forest. The total number of adult animals in Pine Ridge equals 7. ", "question": "How many adult eagle does Pine Ridge have?", "solution": "The question is difficult, so we use equations to solve it. Define adult eagle in Pine Ridge as x; we don't know its value yet but will find it out later. Define adult blue jay in Pine Ridge as K; so K = x = x. Define adult owl in Pine Ridge as v; y = K = x; so v = 1 + y = 1 + x = x + 1. Define total number of adult animals in Pine Ridge as O; s = v + x = x + 1 + x = 2*x + 1; so O = s + K = 2*x + 1 + x = 3*x + 1. We know O = 7, so we have 3*x + 1 = 7 and we solve it through the following steps: Simplifying the equation: 3*x + 1 = 7. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.", "op": 7, "id": "22_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of intense detective thriller in Cin\u00e9ma de Montreval equals 3 times the total number of movies in R\u00eaves de Belleville. The number of upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont equals the total number of movies in Cin\u00e9ma de Montreval. The total number of movies in Festival Lumi\u00e8re de Valmont equals 12. The number of calm road movie in R\u00eaves de Belleville exists, and its number is greater than 0. ", "question": "How many calm road movie does R\u00eaves de Belleville have?", "solution": "The question is difficult, so we use equations to solve it. Define calm road movie in R\u00eaves de Belleville as x; we don't know its value yet but will find it out later. Define total number of movies in R\u00eaves de Belleville as V; so V = x = x. Define intense detective thriller in Cin\u00e9ma de Montreval as j; G = V = x; so j = 3 * G = (3) * (x) = 3*x. Define total number of movies in Cin\u00e9ma de Montreval as P; so P = j = 3*x. Define upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont as g; so g = P = 3*x. Define total number of movies in Festival Lumi\u00e8re de Valmont as i; so i = g = 3*x. We know i = 12, so we have 3*x = 12 and we solve it through the following steps: Simplifying the equation: 3*x = 12. Move all terms to one side: 3*x - 12 = 0. Isolate the term with x: 3*x = 12. Divide both sides by 3: x = 12 / 3. Solution: x = 4. Answer: 4.", "op": 7, "id": "18_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult wolf in Maple Creek exists, and its number is greater than 0. The number of adult bear in Beverly Forest equals 2 plus the number of adult fox in Beverly Forest. The number of adult fox in Beverly Forest equals 4 times the number of adult wolf in Maple Creek. The total number of adult animals in Beverly Forest equals 26. The number of adult bear in Maple Creek equals 2 times the number of adult fox in Maple Creek. The number of adult wolf in Maple Creek exists, and its number is greater than 0. The number of adult fox in Maple Creek equals 2. ", "question": "How many adult wolf does Maple Creek have?", "solution": "The question is difficult, so we use equations to solve it. Define adult wolf in Maple Creek as x; we don't know its value yet but will find it out later. Define adult fox in Beverly Forest as P; i = x = x; so P = 4 * i = (4) * (x) = 4*x. Define adult bear in Beverly Forest as d; u = P = 4*x; so d = 2 + u = 2 + 4*x = 4*x + 2. Define total number of adult animals in Beverly Forest as C; so C = d + P = 4*x + 2 + 4*x = 8*x + 2. We know C = 26, so we have 8*x + 2 = 26 and we solve it through the following steps: Simplifying the equation: 8*x + 2 = 26. Move all terms to one side: 8*x - 24 = 0. Isolate the term with x: 8*x = 24. Divide both sides by 8: x = 24 / 8. Solution: x = 3. Answer: 3.", "op": 7, "id": "8_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult eagle in Jefferson Circus exists, and its number is greater than 0. The total number of adult animals in Jefferson Circus equals 7. The number of adult eagle in Bundle Ranch equals the number of adult eagle in Jefferson Circus. The number of adult parrot in Bundle Ranch equals 2. The number of adult parrot in Jefferson Circus equals 3 plus the difference between the number of adult eagle in Bundle Ranch and the number of adult eagle in Jefferson Circus. ", "question": "How many adult eagle does Jefferson Circus have?", "solution": "The question is difficult, so we use equations to solve it. Define adult eagle in Jefferson Circus as x; we don't know its value yet but will find it out later. Define adult eagle in Bundle Ranch as t; so t = x = x. Define adult parrot in Jefferson Circus as i; w = t - x = (x) - (x) = 0; so i = 3 + w = 3 + 0 = 3. Define total number of adult animals in Jefferson Circus as L; so L = x + i = x + 3 = x + 3. We know L = 7, so we have x + 3 = 7 and we solve it through the following steps: Simplifying the equation: x + 3 = 7. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.", "op": 7, "id": "2_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of futuristic sci-fi movie in Festival de Saint-Rivage equals the sum of the number of futuristic sci-fi movie in Cin\u00e9ma de Montreval, the number of calm road movie in Festival de Saint-Rivage, and the number of calm road movie in Cin\u00e9ma de Montreval. The number of calm road movie in Festival Lumi\u00e8re de Valmont exists, and its number is greater than 0. The number of solemn period drama in Festival Lumi\u00e8re de Valmont equals 2. The total number of movies in Festival Lumi\u00e8re de Valmont equals 12. The number of futuristic sci-fi movie in Cin\u00e9ma de Montreval equals 2 plus the number of calm road movie in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont equals 4 plus the number of solemn period drama in Festival Lumi\u00e8re de Valmont. The number of calm road movie in Festival de Saint-Rivage equals 1. The number of solemn period drama in Festival de Saint-Rivage equals the sum of the number of calm road movie in Festival de Saint-Rivage, the number of solemn period drama in Festival Lumi\u00e8re de Valmont, and the number of futuristic sci-fi movie in Cin\u00e9ma de Montreval. The number of solemn period drama in Cin\u00e9ma de Montreval equals the number of calm road movie in Festival de Saint-Rivage. The number of calm road movie in Cin\u00e9ma de Montreval equals 3 plus the difference between the number of calm road movie in Festival de Saint-Rivage and the number of futuristic sci-fi movie in Cin\u00e9ma de Montreval. ", "question": "How many calm road movie does Festival Lumi\u00e8re de Valmont have?", "solution": "The question is difficult, so we use equations to solve it. Define solemn period drama in Festival Lumi\u00e8re de Valmont as U; so U = 2. Define futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont as h; E = U = 2; so h = 4 + E = 4 + 2 = 6. Define calm road movie in Festival Lumi\u00e8re de Valmont as x; we don't know its value yet but will find it out later. Define total number of movies in Festival Lumi\u00e8re de Valmont as W; p = h + U = 6 + 2 = 8; so W = p + x = 8 + x = x + 8. We know W = 12, so we have x + 8 = 12 and we solve it through the following steps: Simplifying the equation: x + 8 = 12. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.", "op": 7, "id": "19_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult deer in Oakridge Riverside equals the number of adult bear in Oakridge Riverside. The number of adult fox in Oakridge Riverside exists, and its number is greater than 0. The number of adult bear in Cedar Valley equals 3. The number of adult bear in Oakridge Riverside equals 3 times the number of adult fox in Oakridge Riverside. The number of adult deer in Pine Ridge equals 4. The number of adult fox in Cedar Valley equals 1. The total number of adult animals in Oakridge Riverside equals 14. ", "question": "How many adult fox does Oakridge Riverside have?", "solution": "The question is difficult, so we use equations to solve it. Define adult fox in Oakridge Riverside as x; we don't know its value yet but will find it out later. Define adult bear in Oakridge Riverside as O; a = x = x; so O = 3 * a = (3) * (x) = 3*x. Define adult deer in Oakridge Riverside as j; so j = O = 3*x. Define total number of adult animals in Oakridge Riverside as E; U = x + j = x + 3*x = 4*x; so E = U + O = 4*x + 3*x = 7*x. We know E = 14, so we have 7*x = 14 and we solve it through the following steps: Simplifying the equation: 7*x = 14. Move all terms to one side: 7*x - 14 = 0. Isolate the term with x: 7*x = 14. Divide both sides by 7: x = 14 / 7. Solution: x = 2. Answer: 2.", "op": 7, "id": "15_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in Festival de Saint-Rivage equals 3. The total number of movies in Festival de Saint-Rivage equals 14. The number of calm road movie in R\u00eaves de Belleville equals the number of futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont. The number of calm road movie in Festival Lumi\u00e8re de Valmont equals the number of calm road movie in R\u00eaves de Belleville. The number of futuristic sci-fi movie in Festival de Saint-Rivage exists, and its number is greater than 0. The number of solemn period drama in Festival Lumi\u00e8re de Valmont equals 4 plus the number of solemn period drama in Festival de Saint-Rivage. The number of solemn period drama in R\u00eaves de Belleville equals 4 plus the number of futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont. The number of futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont equals 2. The number of calm road movie in Festival de Saint-Rivage equals 3 times the number of solemn period drama in Festival de Saint-Rivage. The number of futuristic sci-fi movie in R\u00eaves de Belleville equals 4 times the sum of the number of futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont and the number of solemn period drama in R\u00eaves de Belleville. ", "question": "How many futuristic sci-fi movie does Festival de Saint-Rivage have?", "solution": "The question is difficult, so we use equations to solve it. Define solemn period drama in Festival de Saint-Rivage as E; so E = 3. Define calm road movie in Festival de Saint-Rivage as C; u = E = 3; so C = 3 * u = (3) * (3) = 9. Define futuristic sci-fi movie in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define total number of movies in Festival de Saint-Rivage as M; U = x + C = x + 9 = x + 9; so M = U + E = x + 9 + 3 = x + 12. We know M = 14, so we have x + 12 = 14 and we solve it through the following steps: Simplifying the equation: x + 12 = 14. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "12_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult blue jay in Jefferson Circus equals 3. The total number of adult animals in Hamilton Farm equals 11. The number of adult parrot in Hamilton Farm equals the number of adult eagle in Hamilton Farm. The number of adult eagle in Hamilton Farm equals 1 plus the number of adult blue jay in Hamilton Farm. The number of adult eagle in Jefferson Circus equals 4. The number of adult parrot in Mayer Aquarium equals 4 times the number of adult eagle in Jefferson Circus. The number of adult blue jay in Mayer Aquarium equals the number of adult eagle in Jefferson Circus. The number of adult parrot in Jefferson Circus equals the sum of the number of adult blue jay in Mayer Aquarium and the number of adult eagle in Jefferson Circus. The number of adult blue jay in Hamilton Farm exists, and its number is greater than 0. The number of adult eagle in Mayer Aquarium equals 4 plus the number of adult eagle in Jefferson Circus. ", "question": "How many adult blue jay does Hamilton Farm have?", "solution": "The question is difficult, so we use equations to solve it. Define adult blue jay in Hamilton Farm as x; we don't know its value yet but will find it out later. Define adult eagle in Hamilton Farm as Y; i = x = x; so Y = 1 + i = 1 + x = x + 1. Define adult parrot in Hamilton Farm as R; so R = Y = x + 1. Define total number of adult animals in Hamilton Farm as Z; w = x + Y = x + x + 1 = 2*x + 1; so Z = w + R = 2*x + 1 + x + 1 = 3*x + 2. We know Z = 11, so we have 3*x + 2 = 11 and we solve it through the following steps: Simplifying the equation: 3*x + 2 = 11. Move all terms to one side: 3*x - 9 = 0. Isolate the term with x: 3*x = 9. Divide both sides by 3: x = 9 / 3. Solution: x = 3. Answer: 3.", "op": 7, "id": "7_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of private middle school in Ruby Bay equals the number of regional medical school in Oakbridge City. The total number of schools in Ruby Bay equals 12. The number of private middle school in Riverton City equals 4 times the number of elementary school in Riverton City. The number of elementary school in Oakbridge City equals the number of elementary school in Ruby Bay. The number of regional medical school in Riverton City equals the number of private middle school in Ruby Bay. The number of regional medical school in Oakbridge City exists, and its number is greater than 0. The number of elementary school in Ruby Bay equals the number of regional medical school in Oakbridge City. The number of regional medical school in Ruby Bay equals the number of private middle school in Ruby Bay. The number of private middle school in Oakbridge City equals 3. The number of elementary school in Riverton City equals 4. ", "question": "How many regional medical school does Oakbridge City have?", "solution": "The question is difficult, so we use equations to solve it. Define regional medical school in Oakbridge City as x; we don't know its value yet but will find it out later. Define elementary school in Ruby Bay as r; so r = x = x. Define private middle school in Ruby Bay as w; so w = x = x. Define regional medical school in Ruby Bay as Y; so Y = w = x. Define total number of schools in Ruby Bay as V; p = w + r = x + x = 2*x; so V = p + Y = 2*x + x = 3*x. We know V = 12, so we have 3*x = 12 and we solve it through the following steps: Simplifying the equation: 3*x = 12. Move all terms to one side: 3*x - 12 = 0. Isolate the term with x: 3*x = 12. Divide both sides by 3: x = 12 / 3. Solution: x = 4. Answer: 4.", "op": 7, "id": "8_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of calm road movie in R\u00eaves de Belleville equals the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of solemn period drama in Festival de Saint-Rivage equals the number of upbeat metropolis comedy in R\u00eaves de Belleville. The number of upbeat metropolis comedy in R\u00eaves de Belleville exists, and its number is greater than 0. The number of solemn period drama in Festival de Clairmont equals 1. The number of solemn period drama in R\u00eaves de Belleville equals the sum of the number of calm road movie in Festival de Saint-Rivage and the number of solemn period drama in Festival de Saint-Rivage. The number of calm road movie in Festival de Clairmont equals the sum of the total number of movies in Festival de Saint-Rivage, the number of upbeat metropolis comedy in Festival de Saint-Rivage, the number of upbeat metropolis comedy in Festival de Clairmont, and the total number of movies in R\u00eaves de Belleville. The number of calm road movie in Festival de Saint-Rivage equals 2 plus the sum of the number of solemn period drama in Festival de Saint-Rivage and the number of upbeat metropolis comedy in R\u00eaves de Belleville. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 3. The number of upbeat metropolis comedy in Festival de Clairmont equals the difference between the number of upbeat metropolis comedy in R\u00eaves de Belleville and the number of solemn period drama in Festival de Clairmont. The number of solemn period drama in R\u00eaves de Belleville equals 14. ", "question": "How many upbeat metropolis comedy does R\u00eaves de Belleville have?", "solution": "The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in R\u00eaves de Belleville as x; we don't know its value yet but will find it out later. Define solemn period drama in Festival de Saint-Rivage as Q; so Q = x = x. Define calm road movie in Festival de Saint-Rivage as c; K = Q + x = x + x = 2*x; so c = 2 + K = 2 + 2*x = 2*x + 2. Define solemn period drama in R\u00eaves de Belleville as G; so G = c + Q = 2*x + 2 + x = 3*x + 2. We know G = 14, so we have 3*x + 2 = 14 and we solve it through the following steps: Simplifying the equation: 3*x + 2 = 14. Move all terms to one side: 3*x - 12 = 0. Isolate the term with x: 3*x = 12. Divide both sides by 3: x = 12 / 3. Solution: x = 4. Answer: 4.", "op": 7, "id": "14_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of calm road movie in Festival de Clairmont equals 2 times the number of intense detective thriller in Festival de Clairmont. The number of intense detective thriller in Festival de Clairmont equals the number of intense detective thriller in Festival de Saint-Rivage. The number of calm road movie in Festival de Saint-Rivage exists, and its number is greater than 0. The number of intense detective thriller in Festival de Saint-Rivage equals the number of calm road movie in Festival de Saint-Rivage. The total number of movies in Festival de Clairmont equals 9. ", "question": "How many calm road movie does Festival de Saint-Rivage have?", "solution": "The question is difficult, so we use equations to solve it. Define calm road movie in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define intense detective thriller in Festival de Saint-Rivage as G; so G = x = x. Define intense detective thriller in Festival de Clairmont as o; so o = G = x. Define calm road movie in Festival de Clairmont as k; Y = o = x; so k = 2 * Y = (2) * (x) = 2*x. Define total number of movies in Festival de Clairmont as S; so S = o + k = x + 2*x = 3*x. We know S = 9, so we have 3*x = 9 and we solve it through the following steps: Simplifying the equation: 3*x = 9. Move all terms to one side: 3*x - 9 = 0. Isolate the term with x: 3*x = 9. Divide both sides by 3: x = 9 / 3. Solution: x = 3. Answer: 3.", "op": 7, "id": "9_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in R\u00eaves de Belleville equals 2. The number of upbeat metropolis comedy in R\u00eaves de Belleville exists, and its number is greater than 0. The number of upbeat metropolis comedy in R\u00eaves de Belleville exists, and its number is greater than 0. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 4. The number of upbeat metropolis comedy in R\u00eaves de Belleville exists, and its number is greater than 0. The number of calm road movie in Festival de Clairmont equals 3 plus the total number of movies in R\u00eaves de Belleville. The total number of movies in Festival de Clairmont equals 7. ", "question": "How many upbeat metropolis comedy does R\u00eaves de Belleville have?", "solution": "The question is difficult, so we use equations to solve it. Define solemn period drama in R\u00eaves de Belleville as Q; so Q = 2. Define upbeat metropolis comedy in R\u00eaves de Belleville as x; we don't know its value yet but will find it out later. Define total number of movies in R\u00eaves de Belleville as s; so s = Q + x = 2 + x = x + 2. Define calm road movie in Festival de Clairmont as D; R = s = x + 2; so D = 3 + R = 3 + x + 2 = x + 5. Define total number of movies in Festival de Clairmont as z; so z = D = x + 5. We know z = 7, so we have x + 5 = 7 and we solve it through the following steps: Simplifying the equation: x + 5 = 7. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "10_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of movies in Verdi Movie Festival equals 12. The number of futuristic sci-fi movie in West Sahara Movie Festival equals the total number of movies in West Sahara Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals 3 plus the number of calm road movie in Verdi Movie Festival. The number of futuristic sci-fi movie in Taylor Movie Festival equals 4. The number of solemn period drama in West Sahara Movie Festival equals 3. The number of solemn period drama in Taylor Movie Festival equals 3. The number of calm road movie in Verdi Movie Festival exists, and its number is greater than 0. The number of solemn period drama in Verdi Movie Festival equals the number of futuristic sci-fi movie in Verdi Movie Festival. ", "question": "How many calm road movie does Verdi Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define calm road movie in Verdi Movie Festival as x; we don't know its value yet but will find it out later. Define futuristic sci-fi movie in Verdi Movie Festival as q; s = x = x; so q = 3 + s = 3 + x = x + 3. Define solemn period drama in Verdi Movie Festival as S; so S = q = x + 3. Define total number of movies in Verdi Movie Festival as a; V = q + S = x + 3 + x + 3 = 2*x + 6; so a = V + x = 2*x + 6 + x = 3*x + 6. We know a = 12, so we have 3*x + 6 = 12 and we solve it through the following steps: Simplifying the equation: 3*x + 6 = 12. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.", "op": 7, "id": "9_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of calm road movie in Festival de Saint-Rivage equals 2. The number of futuristic sci-fi movie in Cin\u00e9ma de Montreval equals the number of futuristic sci-fi movie in Festival de Clairmont. The number of upbeat metropolis comedy in Festival de Clairmont equals 4. The number of futuristic sci-fi movie in Festival de Clairmont exists, and its number is greater than 0. The number of calm road movie in Cin\u00e9ma de Montreval equals 2 times the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals the number of futuristic sci-fi movie in Festival de Clairmont. The total number of movies in Cin\u00e9ma de Montreval equals 12. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 2. The number of calm road movie in Festival de Clairmont equals 4. ", "question": "How many futuristic sci-fi movie does Festival de Clairmont have?", "solution": "The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Festival de Clairmont as x; we don't know its value yet but will find it out later. Define futuristic sci-fi movie in Festival de Saint-Rivage as l; so l = x = x. Define futuristic sci-fi movie in Cin\u00e9ma de Montreval as u; so u = x = x. Define calm road movie in Cin\u00e9ma de Montreval as Z; G = l = x; so Z = 2 * G = (2) * (x) = 2*x. Define total number of movies in Cin\u00e9ma de Montreval as o; so o = u + Z = x + 2*x = 3*x. We know o = 12, so we have 3*x = 12 and we solve it through the following steps: Simplifying the equation: 3*x = 12. Move all terms to one side: 3*x - 12 = 0. Isolate the term with x: 3*x = 12. Divide both sides by 3: x = 12 / 3. Solution: x = 4. Answer: 4.", "op": 7, "id": "19_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of regional medical school in Clearwater Bay equals the number of elementary school in Oakbridge City. The number of elementary school in Clearwater Bay equals the number of public highschool in Clearwater Bay. The number of public highschool in Oakbridge City equals the number of elementary school in Clearwater Bay. The number of elementary school in Oakbridge City equals 2. The number of public highschool in Clearwater Bay exists, and its number is greater than 0. The number of public highschool in Shoreline City equals 2. The number of regional medical school in Shoreline City equals 4. The number of regional medical school in Oakbridge City equals the number of elementary school in Shoreline City. The number of elementary school in Shoreline City equals 3 times the sum of the number of elementary school in Clearwater Bay, the total number of schools in Shoreline City, and the total number of schools in Clearwater Bay. The total number of schools in Clearwater Bay equals 10. ", "question": "How many public highschool does Clearwater Bay have?", "solution": "The question is difficult, so we use equations to solve it. Define elementary school in Oakbridge City as g; so g = 2. Define regional medical school in Clearwater Bay as G; so G = g = 2. Define public highschool in Clearwater Bay as x; we don't know its value yet but will find it out later. Define elementary school in Clearwater Bay as Q; so Q = x = x. Define total number of schools in Clearwater Bay as S; J = G + Q = 2 + x = x + 2; so S = J + x = x + 2 + x = 2*x + 2. We know S = 10, so we have 2*x + 2 = 10 and we solve it through the following steps: Simplifying the equation: 2*x + 2 = 10. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.", "op": 7, "id": "5_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult racoon in Beverly Forest equals the number of adult deer in Pine Ridge. The number of adult deer in Pine Ridge equals 4 plus the number of adult wolf in Pine Ridge. The number of adult wolf in Pine Ridge exists, and its number is greater than 0. The number of adult deer in Beverly Forest equals the number of adult wolf in Beverly Forest. The number of adult racoon in Cedar Valley equals the number of adult wolf in Beverly Forest. The total number of adult animals in Pine Ridge equals 16. The number of adult wolf in Beverly Forest equals the number of adult deer in Pine Ridge. The number of adult deer in Cedar Valley equals 2. The number of adult racoon in Pine Ridge equals the number of adult wolf in Pine Ridge. The number of adult wolf in Cedar Valley equals 4. ", "question": "How many adult wolf does Pine Ridge have?", "solution": "The question is difficult, so we use equations to solve it. Define adult wolf in Pine Ridge as x; we don't know its value yet but will find it out later. Define adult racoon in Pine Ridge as b; so b = x = x. Define adult deer in Pine Ridge as G; f = x = x; so G = 4 + f = 4 + x = x + 4. Define total number of adult animals in Pine Ridge as M; d = x + b = x + x = 2*x; so M = d + G = 2*x + x + 4 = 3*x + 4. We know M = 16, so we have 3*x + 4 = 16 and we solve it through the following steps: Simplifying the equation: 3*x + 4 = 16. Move all terms to one side: 3*x - 12 = 0. Isolate the term with x: 3*x = 12. Divide both sides by 3: x = 12 / 3. Solution: x = 4. Answer: 4.", "op": 7, "id": "15_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of schools in Hawkesbury equals 8. The number of elementary school in Glenfield City equals the sum of the number of elementary school in Hawkesbury, the number of public highschool in Hawkesbury, and the number of public highschool in Evervale City. The number of culinarian school in Glenfield City equals the sum of the number of culinarian school in Hawkesbury and the total number of schools in Evervale City. The number of culinarian school in Evervale City equals 4. The number of public highschool in Glenfield City equals 1. The number of culinarian school in Hawkesbury equals 2 times the number of elementary school in Hawkesbury. The number of public highschool in Evervale City equals 2. The number of elementary school in Evervale City equals the difference between the number of public highschool in Hawkesbury and the total number of schools in Hawkesbury. The number of elementary school in Hawkesbury exists, and its number is greater than 0. The number of public highschool in Hawkesbury equals the number of elementary school in Hawkesbury. ", "question": "How many elementary school does Hawkesbury have?", "solution": "The question is difficult, so we use equations to solve it. Define elementary school in Hawkesbury as x; we don't know its value yet but will find it out later. Define culinarian school in Hawkesbury as V; J = x = x; so V = 2 * J = (2) * (x) = 2*x. Define public highschool in Hawkesbury as G; so G = x = x. Define total number of schools in Hawkesbury as L; C = x + V = x + 2*x = 3*x; so L = C + G = 3*x + x = 4*x. We know L = 8, so we have 4*x = 8 and we solve it through the following steps: Simplifying the equation: 4*x = 8. Move all terms to one side: 4*x - 8 = 0. Isolate the term with x: 4*x = 8. Divide both sides by 4: x = 8 / 4. Solution: x = 2. Answer: 2.", "op": 7, "id": "0_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in Festival de Clairmont equals 2. The number of calm road movie in Cin\u00e9ma de Montreval equals 2 plus the number of intense detective thriller in Festival Lumi\u00e8re de Valmont. The number of intense detective thriller in Cin\u00e9ma de Montreval equals 3 times the sum of the number of calm road movie in Cin\u00e9ma de Montreval, the number of calm road movie in Festival de Clairmont, and the number of solemn period drama in Cin\u00e9ma de Montreval. The number of calm road movie in Festival de Clairmont equals 3 plus the number of calm road movie in Festival Lumi\u00e8re de Valmont. The number of intense detective thriller in Festival Lumi\u00e8re de Valmont exists, and its number is greater than 0. The total number of movies in Festival Lumi\u00e8re de Valmont equals 19. The number of solemn period drama in Festival Lumi\u00e8re de Valmont equals 4 times the number of calm road movie in Festival Lumi\u00e8re de Valmont. The number of solemn period drama in Cin\u00e9ma de Montreval equals the number of calm road movie in Cin\u00e9ma de Montreval. The number of intense detective thriller in Festival de Clairmont equals 3 times the number of intense detective thriller in Festival Lumi\u00e8re de Valmont. The number of calm road movie in Festival Lumi\u00e8re de Valmont equals 3. ", "question": "How many intense detective thriller does Festival Lumi\u00e8re de Valmont have?", "solution": "The question is difficult, so we use equations to solve it. Define calm road movie in Festival Lumi\u00e8re de Valmont as M; so M = 3. Define intense detective thriller in Festival Lumi\u00e8re de Valmont as x; we don't know its value yet but will find it out later. Define solemn period drama in Festival Lumi\u00e8re de Valmont as z; L = M = 3; so z = 4 * L = (4) * (3) = 12. Define total number of movies in Festival Lumi\u00e8re de Valmont as y; t = x + M = x + 3 = x + 3; so y = t + z = x + 3 + 12 = x + 15. We know y = 19, so we have x + 15 = 19 and we solve it through the following steps: Simplifying the equation: x + 15 = 19. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.", "op": 7, "id": "17_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of movies in Taylor Movie Festival equals 15. The number of calm road movie in Taylor Movie Festival equals 3 plus the number of upbeat metropolis comedy in Taylor Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival exists, and its number is greater than 0. The number of upbeat metropolis comedy in Taylor Movie Festival equals 2 times the number of upbeat metropolis comedy in Northwood Movie Festival. ", "question": "How many upbeat metropolis comedy does Northwood Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in Northwood Movie Festival as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in Taylor Movie Festival as t; k = x = x; so t = 2 * k = (2) * (x) = 2*x. Define calm road movie in Taylor Movie Festival as Y; m = t = 2*x; so Y = 3 + m = 3 + 2*x = 2*x + 3. Define total number of movies in Taylor Movie Festival as g; so g = Y + t = 2*x + 3 + 2*x = 4*x + 3. We know g = 15, so we have 4*x + 3 = 15 and we solve it through the following steps: Simplifying the equation: 4*x + 3 = 15. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.", "op": 7, "id": "17_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of private middle school in Glenfield City exists, and its number is greater than 0. The number of private middle school in Hawkesbury equals 1. The number of elementary school in Westhaven City equals the difference between the total number of schools in Glenfield City and the number of culinarian school in Glenfield City. The total number of schools in Westhaven City equals 3. The number of culinarian school in Glenfield City equals 1. ", "question": "How many private middle school does Glenfield City have?", "solution": "The question is difficult, so we use equations to solve it. Define culinarian school in Glenfield City as z; so z = 1. Define private middle school in Glenfield City as x; we don't know its value yet but will find it out later. Define total number of schools in Glenfield City as Z; so Z = x + z = x + 1 = x + 1. Define elementary school in Westhaven City as Q; so Q = Z - z = (x + 1) - (1) = x. Define total number of schools in Westhaven City as p; so p = Q = x. We know p = 3, so we have x = 3 and we solve it through the following steps: Simplifying the equation: x = 3. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.", "op": 7, "id": "13_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of regional medical school in Hawkesbury equals 2 times the sum of the total number of schools in Hawkesbury, the number of culinarian school in Glenfield City, and the total number of schools in Glenfield City. The number of culinarian school in Hawkesbury equals 1. The number of culinarian school in Evervale City exists, and its number is greater than 0. The number of culinarian school in Glenfield City equals the number of culinarian school in Evervale City. The number of regional medical school in Glenfield City equals the number of culinarian school in Evervale City. The number of public highschool in Hawkesbury equals 2. The number of regional medical school in Evervale City equals 1 plus the sum of the number of public highschool in Evervale City, the number of public highschool in Glenfield City, and the total number of schools in Hawkesbury. The total number of schools in Glenfield City equals 6. The number of public highschool in Evervale City equals 2. The number of public highschool in Glenfield City equals the number of culinarian school in Evervale City. ", "question": "How many culinarian school does Evervale City have?", "solution": "The question is difficult, so we use equations to solve it. Define culinarian school in Evervale City as x; we don't know its value yet but will find it out later. Define public highschool in Glenfield City as w; so w = x = x. Define regional medical school in Glenfield City as k; so k = x = x. Define culinarian school in Glenfield City as P; so P = x = x. Define total number of schools in Glenfield City as a; T = k + P = x + x = 2*x; so a = T + w = 2*x + x = 3*x. We know a = 6, so we have 3*x = 6 and we solve it through the following steps: Simplifying the equation: 3*x = 6. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.", "op": 7, "id": "15_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult owl in South Zoo equals 2 plus the total number of adult animals in Bundle Ranch. The number of adult parrot in South Zoo equals the number of adult parrot in Bundle Ranch. The total number of adult animals in South Zoo equals 10. The number of adult parrot in Bundle Ranch exists, and its number is greater than 0. ", "question": "How many adult parrot does Bundle Ranch have?", "solution": "The question is difficult, so we use equations to solve it. Define adult parrot in Bundle Ranch as x; we don't know its value yet but will find it out later. Define adult parrot in South Zoo as A; so A = x = x. Define total number of adult animals in Bundle Ranch as N; so N = x = x. Define adult owl in South Zoo as y; P = N = x; so y = 2 + P = 2 + x = x + 2. Define total number of adult animals in South Zoo as d; so d = A + y = x + x + 2 = 2*x + 2. We know d = 10, so we have 2*x + 2 = 10 and we solve it through the following steps: Simplifying the equation: 2*x + 2 = 10. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.", "op": 7, "id": "7_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of regional medical school in Brightford equals 2 times the number of private middle school in Glenfield City. The number of private middle school in Brightford equals the sum of the total number of schools in Glenfield City and the number of public highschool in Brightford. The number of public highschool in Brightford equals 2. The number of private middle school in Glenfield City exists, and its number is greater than 0. The total number of schools in Glenfield City equals 4. The number of public highschool in Glenfield City equals the number of private middle school in Glenfield City. The number of regional medical school in Glenfield City equals the sum of the number of private middle school in Glenfield City and the number of public highschool in Glenfield City. ", "question": "How many private middle school does Glenfield City have?", "solution": "The question is difficult, so we use equations to solve it. Define private middle school in Glenfield City as x; we don't know its value yet but will find it out later. Define public highschool in Glenfield City as P; so P = x = x. Define regional medical school in Glenfield City as q; so q = x + P = x + x = 2*x. Define total number of schools in Glenfield City as z; n = P + q = x + 2*x = 3*x; so z = n + x = 3*x + x = 4*x. We know z = 4, so we have 4*x = 4 and we solve it through the following steps: Simplifying the equation: 4*x = 4. Move all terms to one side: 4*x - 4 = 0. Isolate the term with x: 4*x = 4. Divide both sides by 4: x = 4 / 4. Solution: x = 1. Answer: 1.", "op": 7, "id": "7_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult crow in Beverly Forest exists, and its number is greater than 0. The total number of adult animals in Oakridge Riverside equals 23. The number of adult crow in Beverly Forest exists, and its number is greater than 0. The number of adult owl in Cedar Valley equals 4 plus the number of adult owl in Beverly Forest. The number of adult eagle in Beverly Forest equals 3. The number of adult eagle in Oakridge Riverside equals 3 plus the number of adult crow in Beverly Forest. The number of adult crow in Oakridge Riverside equals 4 times the number of adult crow in Beverly Forest. ", "question": "How many adult crow does Beverly Forest have?", "solution": "The question is difficult, so we use equations to solve it. Define adult crow in Beverly Forest as x; we don't know its value yet but will find it out later. Define adult eagle in Oakridge Riverside as M; k = x = x; so M = 3 + k = 3 + x = x + 3. Define adult crow in Oakridge Riverside as D; h = x = x; so D = 4 * h = (4) * (x) = 4*x. Define total number of adult animals in Oakridge Riverside as z; so z = M + D = x + 3 + 4*x = 5*x + 3. We know z = 23, so we have 5*x + 3 = 23 and we solve it through the following steps: Simplifying the equation: 5*x + 3 = 23. Move all terms to one side: 5*x - 20 = 0. Isolate the term with x: 5*x = 20. Divide both sides by 5: x = 20 / 5. Solution: x = 4. Answer: 4.", "op": 7, "id": "2_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in Verdi Movie Festival equals 4 times the number of upbeat metropolis comedy in Verdi Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 4. The number of upbeat metropolis comedy in Northwood Movie Festival equals the number of intense detective thriller in West Sahara Movie Festival. The total number of movies in West Sahara Movie Festival equals 6. The number of intense detective thriller in West Sahara Movie Festival equals 1 plus the number of solemn period drama in West Sahara Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals 2. The number of intense detective thriller in Verdi Movie Festival equals the number of intense detective thriller in Northwood Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals the number of intense detective thriller in West Sahara Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 2. The number of upbeat metropolis comedy in West Sahara Movie Festival exists, and its number is greater than 0. ", "question": "How many upbeat metropolis comedy does West Sahara Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define solemn period drama in West Sahara Movie Festival as u; so u = 2. Define upbeat metropolis comedy in West Sahara Movie Festival as x; we don't know its value yet but will find it out later. Define intense detective thriller in West Sahara Movie Festival as P; L = u = 2; so P = 1 + L = 1 + 2 = 3. Define total number of movies in West Sahara Movie Festival as j; q = P + u = 3 + 2 = 5; so j = q + x = 5 + x = x + 5. We know j = 6, so we have x + 5 = 6 and we solve it through the following steps: Simplifying the equation: x + 5 = 6. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1.", "op": 7, "id": "2_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of calm road movie in R\u00eaves de Belleville equals 1. The number of calm road movie in Festival de Saint-Rivage equals 4 times the number of intense detective thriller in Festival de Saint-Rivage. The number of intense detective thriller in Festival de Clairmont equals 1 plus the number of calm road movie in R\u00eaves de Belleville. The number of solemn period drama in Festival de Saint-Rivage exists, and its number is greater than 0. The number of intense detective thriller in Festival de Saint-Rivage equals the number of solemn period drama in Festival de Saint-Rivage. The total number of movies in Festival de Saint-Rivage equals 12. ", "question": "How many solemn period drama does Festival de Saint-Rivage have?", "solution": "The question is difficult, so we use equations to solve it. Define solemn period drama in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define intense detective thriller in Festival de Saint-Rivage as r; so r = x = x. Define calm road movie in Festival de Saint-Rivage as g; W = r = x; so g = 4 * W = (4) * (x) = 4*x. Define total number of movies in Festival de Saint-Rivage as C; Q = x + r = x + x = 2*x; so C = Q + g = 2*x + 4*x = 6*x. We know C = 12, so we have 6*x = 12 and we solve it through the following steps: Simplifying the equation: 6*x = 12. Move all terms to one side: 6*x - 12 = 0. Isolate the term with x: 6*x = 12. Divide both sides by 6: x = 12 / 6. Solution: x = 2. Answer: 2.", "op": 7, "id": "9_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of intense detective thriller in Verdi Movie Festival equals the number of solemn period drama in Golden Banana Movie Festival. The number of calm road movie in Verdi Movie Festival equals the number of intense detective thriller in Verdi Movie Festival. The total number of movies in Verdi Movie Festival equals 6. The number of calm road movie in Golden Banana Movie Festival equals the number of intense detective thriller in Verdi Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals 4. The number of solemn period drama in West Sahara Movie Festival equals the sum of the total number of movies in Verdi Movie Festival and the number of calm road movie in Verdi Movie Festival. The number of solemn period drama in Verdi Movie Festival equals the number of solemn period drama in Golden Banana Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 3. The number of solemn period drama in Golden Banana Movie Festival exists, and its number is greater than 0. The number of intense detective thriller in Golden Banana Movie Festival equals 3 times the sum of the number of intense detective thriller in Verdi Movie Festival and the number of solemn period drama in Verdi Movie Festival. ", "question": "How many solemn period drama does Golden Banana Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define solemn period drama in Golden Banana Movie Festival as x; we don't know its value yet but will find it out later. Define solemn period drama in Verdi Movie Festival as J; so J = x = x. Define intense detective thriller in Verdi Movie Festival as f; so f = x = x. Define calm road movie in Verdi Movie Festival as c; so c = f = x. Define total number of movies in Verdi Movie Festival as W; M = J + c = x + x = 2*x; so W = M + f = 2*x + x = 3*x. We know W = 6, so we have 3*x = 6 and we solve it through the following steps: Simplifying the equation: 3*x = 6. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.", "op": 7, "id": "15_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of public highschool in Ruby Bay equals 2. The number of elementary school in Ruby Bay equals 4 plus the sum of the number of elementary school in Shoreline City and the number of public highschool in Ruby Bay. The number of elementary school in Shoreline City exists, and its number is greater than 0. The total number of schools in Ruby Bay equals 12. The number of public highschool in Shoreline City equals 3. ", "question": "How many elementary school does Shoreline City have?", "solution": "The question is difficult, so we use equations to solve it. Define public highschool in Ruby Bay as C; so C = 2. Define elementary school in Shoreline City as x; we don't know its value yet but will find it out later. Define elementary school in Ruby Bay as f; g = x + C = x + 2 = x + 2; so f = 4 + g = 4 + x + 2 = x + 6. Define total number of schools in Ruby Bay as y; so y = C + f = 2 + x + 6 = x + 8. We know y = 12, so we have x + 8 = 12 and we solve it through the following steps: Simplifying the equation: x + 8 = 12. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.", "op": 7, "id": "18_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult wolf in South Zoo equals 1 plus the sum of the number of adult bear in Mayer Aquarium, the total number of adult animals in Mayer Aquarium, and the number of adult bear in Jefferson Circus. The number of adult bear in South Zoo equals the number of adult wolf in Jefferson Circus. The number of adult fox in South Zoo equals 2 plus the sum of the number of adult wolf in Jefferson Circus, the number of adult bear in South Zoo, and the number of adult fox in Jefferson Circus. The number of adult wolf in Mayer Aquarium exists, and its number is greater than 0. The number of adult wolf in Mayer Aquarium exists, and its number is greater than 0. The number of adult fox in Mayer Aquarium equals the number of adult bear in Mayer Aquarium. The number of adult bear in Mayer Aquarium equals 3 times the number of adult wolf in Mayer Aquarium. The number of adult fox in Jefferson Circus equals 3 times the difference between the number of adult wolf in Jefferson Circus and the number of adult bear in South Zoo. The total number of adult animals in Mayer Aquarium equals 14. The number of adult wolf in Jefferson Circus equals 3. ", "question": "How many adult wolf does Mayer Aquarium have?", "solution": "The question is difficult, so we use equations to solve it. Define adult wolf in Mayer Aquarium as x; we don't know its value yet but will find it out later. Define adult bear in Mayer Aquarium as d; G = x = x; so d = 3 * G = (3) * (x) = 3*x. Define adult fox in Mayer Aquarium as D; so D = d = 3*x. Define total number of adult animals in Mayer Aquarium as l; U = D + d = 3*x + 3*x = 6*x; so l = U + x = 6*x + x = 7*x. We know l = 14, so we have 7*x = 14 and we solve it through the following steps: Simplifying the equation: 7*x = 14. Move all terms to one side: 7*x - 14 = 0. Isolate the term with x: 7*x = 14. Divide both sides by 7: x = 14 / 7. Solution: x = 2. Answer: 2.", "op": 7, "id": "17_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 2. The total number of movies in Verdi Movie Festival equals 6. The number of futuristic sci-fi movie in Verdi Movie Festival equals the sum of the total number of movies in West Sahara Movie Festival and the number of upbeat metropolis comedy in West Sahara Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival exists, and its number is greater than 0. The number of calm road movie in Golden Banana Movie Festival equals 3 plus the number of futuristic sci-fi movie in Golden Banana Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 2. ", "question": "How many upbeat metropolis comedy does Verdi Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in West Sahara Movie Festival as G; so G = 2. Define total number of movies in West Sahara Movie Festival as J; so J = G = 2. Define upbeat metropolis comedy in Verdi Movie Festival as x; we don't know its value yet but will find it out later. Define futuristic sci-fi movie in Verdi Movie Festival as m; so m = J + G = 2 + 2 = 4. Define total number of movies in Verdi Movie Festival as Q; so Q = m + x = 4 + x = x + 4. We know Q = 6, so we have x + 4 = 6 and we solve it through the following steps: Simplifying the equation: x + 4 = 6. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "11_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of schools in Clearwater Bay equals 9. The number of regional medical school in Clearwater Bay equals 3 plus the number of elementary school in Clearwater Bay. The number of elementary school in Oakbridge City equals the difference between the number of elementary school in Shoreline City and the number of regional medical school in Oakbridge City. The number of elementary school in Shoreline City equals 1. The number of regional medical school in Oakbridge City equals 3. The number of elementary school in Clearwater Bay equals the number of culinarian school in Clearwater Bay. The number of regional medical school in Shoreline City equals the number of regional medical school in Clearwater Bay. The number of culinarian school in Clearwater Bay exists, and its number is greater than 0. The number of culinarian school in Oakbridge City equals 3. ", "question": "How many culinarian school does Clearwater Bay have?", "solution": "The question is difficult, so we use equations to solve it. Define culinarian school in Clearwater Bay as x; we don't know its value yet but will find it out later. Define elementary school in Clearwater Bay as v; so v = x = x. Define regional medical school in Clearwater Bay as B; Y = v = x; so B = 3 + Y = 3 + x = x + 3. Define total number of schools in Clearwater Bay as c; R = B + x = x + 3 + x = 2*x + 3; so c = R + v = 2*x + 3 + x = 3*x + 3. We know c = 9, so we have 3*x + 3 = 9 and we solve it through the following steps: Simplifying the equation: 3*x + 3 = 9. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.", "op": 7, "id": "1_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult racoon in South Zoo equals 4. The number of adult deer in Bundle Ranch equals the total number of adult animals in Jefferson Circus. The number of adult deer in Jefferson Circus equals 2 times the number of adult racoon in Jefferson Circus. The number of adult deer in South Zoo equals the difference between the number of adult fox in Bundle Ranch and the number of adult deer in Jefferson Circus. The number of adult fox in South Zoo equals 4 times the number of adult racoon in South Zoo. The number of adult racoon in Bundle Ranch equals 1. The number of adult fox in Bundle Ranch equals 2 times the sum of the number of adult deer in Jefferson Circus, the number of adult racoon in Jefferson Circus, and the total number of adult animals in Jefferson Circus. The number of adult racoon in Jefferson Circus equals 1. The number of adult fox in Jefferson Circus equals 3. ", "question": "What is the total number of adult animals in Jefferson Circus?", "solution": "Define adult racoon in Jefferson Circus as j; so j = 1. Define adult deer in Jefferson Circus as a; G = j = 1; so a = 2 * G = 2 * 1 = 2. Define adult fox in Jefferson Circus as e; so e = 3. Define total number of adult animals in Jefferson Circus as X; T = j + a = 1 + 2 = 3; so X = T + e = 3 + 3 = 6. Answer: 6.", "op": 7, "id": "19_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of upbeat metropolis comedy in West Sahara Movie Festival equals 2. The number of futuristic sci-fi movie in Northwood Movie Festival equals 3 times the number of solemn period drama in Northwood Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 2. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals the sum of the number of futuristic sci-fi movie in Northwood Movie Festival and the number of solemn period drama in Northwood Movie Festival. The total number of movies in West Sahara Movie Festival equals 6. The number of solemn period drama in West Sahara Movie Festival equals the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 4. The number of futuristic sci-fi movie in West Sahara Movie Festival exists, and its number is greater than 0. ", "question": "How many futuristic sci-fi movie does West Sahara Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in Golden Banana Movie Festival as z; so z = 2. Define solemn period drama in West Sahara Movie Festival as i; so i = z = 2. Define upbeat metropolis comedy in West Sahara Movie Festival as J; so J = 2. Define futuristic sci-fi movie in West Sahara Movie Festival as x; we don't know its value yet but will find it out later. Define total number of movies in West Sahara Movie Festival as s; Y = x + J = x + 2 = x + 2; so s = Y + i = x + 2 + 2 = x + 4. We know s = 6, so we have x + 4 = 6 and we solve it through the following steps: Simplifying the equation: x + 4 = 6. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "16_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of movies in Festival Lumi\u00e8re de Valmont equals 6. The number of intense detective thriller in Festival de Saint-Rivage equals 3. The number of solemn period drama in Festival de Saint-Rivage equals the difference between the number of intense detective thriller in Festival Lumi\u00e8re de Valmont and the total number of movies in Festival de Clairmont. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 4. The number of futuristic sci-fi movie in Festival de Clairmont equals the number of solemn period drama in Festival Lumi\u00e8re de Valmont. The number of intense detective thriller in Festival Lumi\u00e8re de Valmont equals the sum of the total number of movies in Festival de Clairmont and the number of solemn period drama in Festival Lumi\u00e8re de Valmont. The number of solemn period drama in Festival Lumi\u00e8re de Valmont exists, and its number is greater than 0. ", "question": "How many solemn period drama does Festival Lumi\u00e8re de Valmont have?", "solution": "The question is difficult, so we use equations to solve it. Define solemn period drama in Festival Lumi\u00e8re de Valmont as x; we don't know its value yet but will find it out later. Define futuristic sci-fi movie in Festival de Clairmont as J; so J = x = x. Define total number of movies in Festival de Clairmont as E; so E = J = x. Define intense detective thriller in Festival Lumi\u00e8re de Valmont as K; so K = E + x = x + x = 2*x. Define total number of movies in Festival Lumi\u00e8re de Valmont as F; so F = x + K = x + 2*x = 3*x. We know F = 6, so we have 3*x = 6 and we solve it through the following steps: Simplifying the equation: 3*x = 6. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.", "op": 7, "id": "10_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of culinarian school in Hawkesbury equals the sum of the total number of schools in Evervale City, the total number of schools in Hawkesbury, and the number of regional medical school in Hawkesbury. The number of culinarian school in Brightford equals the number of regional medical school in Evervale City. The number of private middle school in Brightford equals 3. The number of culinarian school in Evervale City equals 3. The number of private middle school in Hawkesbury equals 4. The total number of schools in Evervale City equals 12. The number of private middle school in Evervale City exists, and its number is greater than 0. The number of regional medical school in Evervale City equals 4 plus the number of culinarian school in Evervale City. The number of regional medical school in Hawkesbury equals 1. The number of regional medical school in Brightford equals 4 times the number of private middle school in Hawkesbury. ", "question": "How many private middle school does Evervale City have?", "solution": "The question is difficult, so we use equations to solve it. Define culinarian school in Evervale City as O; so O = 3. Define regional medical school in Evervale City as h; i = O = 3; so h = 4 + i = 4 + 3 = 7. Define private middle school in Evervale City as x; we don't know its value yet but will find it out later. Define total number of schools in Evervale City as A; c = O + h = 3 + 7 = 10; so A = c + x = 10 + x = x + 10. We know A = 12, so we have x + 10 = 12 and we solve it through the following steps: Simplifying the equation: x + 10 = 12. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "2_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of private middle school in Glenfield City equals the difference between the number of private middle school in Brightford and the number of regional medical school in Brightford. The number of private middle school in Brightford equals 2. The number of regional medical school in Brightford equals 2. The total number of schools in Westhaven City equals 14. The number of culinarian school in Westhaven City equals 3 times the sum of the number of culinarian school in Brightford and the number of regional medical school in Westhaven City. The number of regional medical school in Glenfield City equals 2 plus the sum of the number of regional medical school in Brightford and the number of private middle school in Brightford. The number of regional medical school in Westhaven City equals the number of culinarian school in Brightford. The number of culinarian school in Brightford exists, and its number is greater than 0. The number of culinarian school in Glenfield City equals 2 times the total number of schools in Westhaven City. ", "question": "How many culinarian school does Brightford have?", "solution": "The question is difficult, so we use equations to solve it. Define culinarian school in Brightford as x; we don't know its value yet but will find it out later. Define regional medical school in Westhaven City as Z; so Z = x = x. Define culinarian school in Westhaven City as Y; R = x + Z = x + x = 2*x; so Y = 3 * R = (3) * (2*x) = 6*x. Define total number of schools in Westhaven City as P; so P = Z + Y = x + 6*x = 7*x. We know P = 14, so we have 7*x = 14 and we solve it through the following steps: Simplifying the equation: 7*x = 14. Move all terms to one side: 7*x - 14 = 0. Isolate the term with x: 7*x = 14. Divide both sides by 7: x = 14 / 7. Solution: x = 2. Answer: 2.", "op": 7, "id": "0_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of elementary school in Clearwater Bay equals the difference between the number of private middle school in Shoreline City and the number of elementary school in Shoreline City. The number of culinarian school in Shoreline City exists, and its number is greater than 0. The number of private middle school in Shoreline City equals the sum of the number of elementary school in Shoreline City and the number of culinarian school in Shoreline City. The total number of schools in Shoreline City equals 12. The number of culinarian school in Ruby Bay equals 2. The number of elementary school in Shoreline City equals the number of culinarian school in Shoreline City. The number of private middle school in Ruby Bay equals 4 times the sum of the total number of schools in Clearwater Bay, the number of private middle school in Shoreline City, and the number of elementary school in Clearwater Bay. ", "question": "How many culinarian school does Shoreline City have?", "solution": "The question is difficult, so we use equations to solve it. Define culinarian school in Shoreline City as x; we don't know its value yet but will find it out later. Define elementary school in Shoreline City as t; so t = x = x. Define private middle school in Shoreline City as p; so p = t + x = x + x = 2*x. Define total number of schools in Shoreline City as Y; G = t + x = x + x = 2*x; so Y = G + p = 2*x + 2*x = 4*x. We know Y = 12, so we have 4*x = 12 and we solve it through the following steps: Simplifying the equation: 4*x = 12. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.", "op": 7, "id": "12_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of adult animals in Oakridge Riverside equals 14. The number of adult blue jay in Oakridge Riverside exists, and its number is greater than 0. The number of adult eagle in Oakridge Riverside equals 4 plus the number of adult crow in Oakridge Riverside. The number of adult crow in Oakridge Riverside equals 4. The number of adult crow in Pine Ridge equals the difference between the number of adult blue jay in Pine Ridge and the number of adult eagle in Pine Ridge. The number of adult eagle in Pine Ridge equals 1. The number of adult eagle in Cedar Valley equals 2. The number of adult blue jay in Cedar Valley equals 4 times the sum of the number of adult eagle in Pine Ridge, the number of adult blue jay in Pine Ridge, and the number of adult crow in Pine Ridge. The number of adult blue jay in Pine Ridge equals 3 times the number of adult eagle in Pine Ridge. ", "question": "How many adult blue jay does Oakridge Riverside have?", "solution": "The question is difficult, so we use equations to solve it. Define adult crow in Oakridge Riverside as T; so T = 4. Define adult blue jay in Oakridge Riverside as x; we don't know its value yet but will find it out later. Define adult eagle in Oakridge Riverside as n; A = T = 4; so n = 4 + A = 4 + 4 = 8. Define total number of adult animals in Oakridge Riverside as s; o = x + n = x + 8 = x + 8; so s = o + T = x + 8 + 4 = x + 12. We know s = 14, so we have x + 12 = 14 and we solve it through the following steps: Simplifying the equation: x + 12 = 14. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "3_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in Taylor Movie Festival equals 1. The total number of movies in West Sahara Movie Festival equals 8. The number of solemn period drama in Verdi Movie Festival equals 4. The number of intense detective thriller in West Sahara Movie Festival exists, and its number is greater than 0. The number of solemn period drama in West Sahara Movie Festival equals the number of intense detective thriller in West Sahara Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals 4. The number of upbeat metropolis comedy in Taylor Movie Festival equals 2 times the number of intense detective thriller in West Sahara Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 2 times the number of intense detective thriller in Verdi Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the sum of the number of solemn period drama in West Sahara Movie Festival and the number of intense detective thriller in West Sahara Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 2. ", "question": "How many intense detective thriller does West Sahara Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define intense detective thriller in West Sahara Movie Festival as x; we don't know its value yet but will find it out later. Define solemn period drama in West Sahara Movie Festival as L; so L = x = x. Define upbeat metropolis comedy in West Sahara Movie Festival as r; so r = L + x = x + x = 2*x. Define total number of movies in West Sahara Movie Festival as K; b = r + x = 2*x + x = 3*x; so K = b + L = 3*x + x = 4*x. We know K = 8, so we have 4*x = 8 and we solve it through the following steps: Simplifying the equation: 4*x = 8. Move all terms to one side: 4*x - 8 = 0. Isolate the term with x: 4*x = 8. Divide both sides by 4: x = 8 / 4. Solution: x = 2. Answer: 2.", "op": 7, "id": "22_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in R\u00eaves de Belleville equals 3 plus the number of upbeat metropolis comedy in R\u00eaves de Belleville. The number of upbeat metropolis comedy in R\u00eaves de Belleville exists, and its number is greater than 0. The number of futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont equals the number of upbeat metropolis comedy in R\u00eaves de Belleville. The number of upbeat metropolis comedy in Festival de Clairmont equals 4. The number of upbeat metropolis comedy in R\u00eaves de Belleville exists, and its number is greater than 0. The number of futuristic sci-fi movie in Festival de Clairmont equals 2. The number of solemn period drama in Festival Lumi\u00e8re de Valmont equals 1. The number of solemn period drama in Festival de Clairmont equals 4. The number of futuristic sci-fi movie in R\u00eaves de Belleville equals 3. The total number of movies in R\u00eaves de Belleville equals 12. ", "question": "How many upbeat metropolis comedy does R\u00eaves de Belleville have?", "solution": "The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in R\u00eaves de Belleville as l; so l = 3. Define upbeat metropolis comedy in R\u00eaves de Belleville as x; we don't know its value yet but will find it out later. Define solemn period drama in R\u00eaves de Belleville as Q; i = x = x; so Q = 3 + i = 3 + x = x + 3. Define total number of movies in R\u00eaves de Belleville as Z; w = Q + l = x + 3 + 3 = x + 6; so Z = w + x = x + 6 + x = 2*x + 6. We know Z = 12, so we have 2*x + 6 = 12 and we solve it through the following steps: Simplifying the equation: 2*x + 6 = 12. Move all terms to one side: 2*x - 6 = 0. Isolate the term with x: 2*x = 6. Divide both sides by 2: x = 6 / 2. Solution: x = 3. Answer: 3.", "op": 7, "id": "0_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult wolf in Jefferson Circus equals the number of adult fox in Jefferson Circus. The total number of adult animals in Bundle Ranch equals 6. The number of adult deer in Hamilton Farm exists, and its number is greater than 0. The number of adult fox in Jefferson Circus equals 2. The number of adult fox in Hamilton Farm equals the number of adult deer in Hamilton Farm. The number of adult deer in Bundle Ranch equals the sum of the total number of adult animals in Hamilton Farm and the number of adult deer in Hamilton Farm. ", "question": "How many adult deer does Hamilton Farm have?", "solution": "The question is difficult, so we use equations to solve it. Define adult deer in Hamilton Farm as x; we don't know its value yet but will find it out later. Define adult fox in Hamilton Farm as B; so B = x = x. Define total number of adult animals in Hamilton Farm as c; so c = B + x = x + x = 2*x. Define adult deer in Bundle Ranch as t; so t = c + x = 2*x + x = 3*x. Define total number of adult animals in Bundle Ranch as M; so M = t = 3*x. We know M = 6, so we have 3*x = 6 and we solve it through the following steps: Simplifying the equation: 3*x = 6. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.", "op": 7, "id": "6_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of culinarian school in Hawkesbury exists, and its number is greater than 0. The number of private middle school in Hawkesbury equals 3. The number of culinarian school in Evervale City equals the number of elementary school in Evervale City. The number of elementary school in Glenfield City equals 3 times the sum of the number of private middle school in Glenfield City and the number of culinarian school in Glenfield City. The number of private middle school in Evervale City equals 2 plus the number of culinarian school in Hawkesbury. The number of culinarian school in Evervale City equals 18. The number of culinarian school in Glenfield City equals the number of private middle school in Glenfield City. The number of elementary school in Evervale City equals 3 times the sum of the number of private middle school in Evervale City and the number of culinarian school in Hawkesbury. The number of elementary school in Hawkesbury equals the sum of the number of private middle school in Evervale City and the total number of schools in Evervale City. The number of private middle school in Glenfield City equals 1. ", "question": "How many culinarian school does Hawkesbury have?", "solution": "The question is difficult, so we use equations to solve it. Define culinarian school in Hawkesbury as x; we don't know its value yet but will find it out later. Define private middle school in Evervale City as a; H = x = x; so a = 2 + H = 2 + x = x + 2. Define elementary school in Evervale City as w; y = a + x = x + 2 + x = 2*x + 2; so w = 3 * y = (3) * (2*x + 2) = 6*x + 6. Define culinarian school in Evervale City as R; so R = w = 6*x + 6. We know R = 18, so we have 6*x + 6 = 18 and we solve it through the following steps: Simplifying the equation: 6*x + 6 = 18. Move all terms to one side: 6*x - 12 = 0. Isolate the term with x: 6*x = 12. Divide both sides by 6: x = 12 / 6. Solution: x = 2. Answer: 2.", "op": 7, "id": "18_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult fox in Bundle Ranch equals the sum of the number of adult bear in Jefferson Circus and the number of adult deer in Jefferson Circus. The number of adult bear in Hamilton Farm exists, and its number is greater than 0. The number of adult bear in Bundle Ranch equals the difference between the number of adult deer in Jefferson Circus and the number of adult fox in Bundle Ranch. The number of adult fox in Jefferson Circus equals 1 plus the total number of adult animals in Jefferson Circus. The number of adult deer in Hamilton Farm equals 4. The number of adult deer in Bundle Ranch equals the sum of the number of adult bear in Jefferson Circus, the number of adult deer in Jefferson Circus, the number of adult fox in Hamilton Farm, and the number of adult bear in Hamilton Farm. The number of adult fox in Hamilton Farm equals 2 times the number of adult deer in Hamilton Farm. The number of adult deer in Jefferson Circus equals 4 plus the number of adult bear in Jefferson Circus. The number of adult bear in Jefferson Circus equals 3. The total number of adult animals in Hamilton Farm equals 14. ", "question": "How many adult bear does Hamilton Farm have?", "solution": "The question is difficult, so we use equations to solve it. Define adult deer in Hamilton Farm as H; so H = 4. Define adult bear in Hamilton Farm as x; we don't know its value yet but will find it out later. Define adult fox in Hamilton Farm as B; v = H = 4; so B = 2 * v = (2) * (4) = 8. Define total number of adult animals in Hamilton Farm as f; q = H + B = 4 + 8 = 12; so f = q + x = 12 + x = x + 12. We know f = 14, so we have x + 12 = 14 and we solve it through the following steps: Simplifying the equation: x + 12 = 14. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "5_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult wolf in Mayer Aquarium exists, and its number is greater than 0. The number of adult racoon in Mayer Aquarium equals the number of adult fox in Mayer Aquarium. The total number of adult animals in Mayer Aquarium equals 6. The number of adult wolf in Bundle Ranch equals 3 plus the number of adult fox in Bundle Ranch. The number of adult racoon in Bundle Ranch equals 3. The number of adult racoon in Jefferson Circus equals 2 plus the sum of the total number of adult animals in Bundle Ranch, the number of adult racoon in Mayer Aquarium, and the number of adult wolf in Mayer Aquarium. The number of adult wolf in Jefferson Circus equals 4 times the number of adult fox in Jefferson Circus. The number of adult fox in Jefferson Circus equals 2. The number of adult fox in Mayer Aquarium equals the number of adult fox in Jefferson Circus. The number of adult fox in Bundle Ranch equals the number of adult racoon in Bundle Ranch. ", "question": "How many adult wolf does Mayer Aquarium have?", "solution": "The question is difficult, so we use equations to solve it. Define adult fox in Jefferson Circus as V; so V = 2. Define adult fox in Mayer Aquarium as i; so i = V = 2. Define adult wolf in Mayer Aquarium as x; we don't know its value yet but will find it out later. Define adult racoon in Mayer Aquarium as U; so U = i = 2. Define total number of adult animals in Mayer Aquarium as s; b = x + i = x + 2 = x + 2; so s = b + U = x + 2 + 2 = x + 4. We know s = 6, so we have x + 4 = 6 and we solve it through the following steps: Simplifying the equation: x + 4 = 6. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "13_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in Festival de Clairmont equals the number of futuristic sci-fi movie in Festival de Clairmont. The number of futuristic sci-fi movie in R\u00eaves de Belleville equals the number of solemn period drama in R\u00eaves de Belleville. The number of solemn period drama in R\u00eaves de Belleville equals 3. The number of futuristic sci-fi movie in Cin\u00e9ma de Montreval equals 2 plus the total number of movies in Festival de Clairmont. The number of futuristic sci-fi movie in Festival de Clairmont exists, and its number is greater than 0. The total number of movies in Cin\u00e9ma de Montreval equals 10. ", "question": "How many futuristic sci-fi movie does Festival de Clairmont have?", "solution": "The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Festival de Clairmont as x; we don't know its value yet but will find it out later. Define solemn period drama in Festival de Clairmont as j; so j = x = x. Define total number of movies in Festival de Clairmont as T; so T = j + x = x + x = 2*x. Define futuristic sci-fi movie in Cin\u00e9ma de Montreval as Y; P = T = 2*x; so Y = 2 + P = 2 + 2*x = 2*x + 2. Define total number of movies in Cin\u00e9ma de Montreval as d; so d = Y = 2*x + 2. We know d = 10, so we have 2*x + 2 = 10 and we solve it through the following steps: Simplifying the equation: 2*x + 2 = 10. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.", "op": 7, "id": "18_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of private middle school in Shoreline City equals 3 times the number of elementary school in Shoreline City. The number of elementary school in Shoreline City equals the total number of schools in Clearwater Bay. The number of elementary school in Clearwater Bay exists, and its number is greater than 0. The total number of schools in Shoreline City equals 4. ", "question": "How many elementary school does Clearwater Bay have?", "solution": "The question is difficult, so we use equations to solve it. Define elementary school in Clearwater Bay as x; we don't know its value yet but will find it out later. Define total number of schools in Clearwater Bay as r; so r = x = x. Define elementary school in Shoreline City as g; so g = r = x. Define private middle school in Shoreline City as O; k = g = x; so O = 3 * k = (3) * (x) = 3*x. Define total number of schools in Shoreline City as h; so h = O + g = 3*x + x = 4*x. We know h = 4, so we have 4*x = 4 and we solve it through the following steps: Simplifying the equation: 4*x = 4. Move all terms to one side: 4*x - 4 = 0. Isolate the term with x: 4*x = 4. Divide both sides by 4: x = 4 / 4. Solution: x = 1. Answer: 1.", "op": 7, "id": "19_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult eagle in Hamilton Farm equals 1. The number of adult eagle in Bundle Ranch equals 3. The number of adult crow in Jefferson Circus equals the number of adult eagle in Bundle Ranch. The number of adult blue jay in Jefferson Circus equals the sum of the total number of adult animals in Hamilton Farm, the number of adult eagle in Hamilton Farm, and the number of adult blue jay in Hamilton Farm. The number of adult blue jay in Bundle Ranch equals 1. The number of adult crow in Hamilton Farm equals 2 plus the number of adult blue jay in Hamilton Farm. The number of adult crow in Bundle Ranch equals 2. The number of adult blue jay in Hamilton Farm equals 4. The number of adult eagle in Jefferson Circus equals 3. ", "question": "What is the total number of adult animals in Hamilton Farm?", "solution": "Define adult blue jay in Hamilton Farm as t; so t = 4. Define adult crow in Hamilton Farm as j; G = t = 4; so j = 2 + G = 2 + 4 = 6. Define adult eagle in Hamilton Farm as O; so O = 1. Define total number of adult animals in Hamilton Farm as V; P = t + O = 4 + 1 = 5; so V = P + j = 5 + 6 = 11. Answer: 11.", "op": 7, "id": "0_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of calm road movie in Golden Banana Movie Festival exists, and its number is greater than 0. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 1 plus the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 2. The total number of movies in Golden Banana Movie Festival equals 9. ", "question": "How many calm road movie does Golden Banana Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in Golden Banana Movie Festival as T; so T = 2. Define futuristic sci-fi movie in Golden Banana Movie Festival as e; V = T = 2; so e = 1 + V = 1 + 2 = 3. Define calm road movie in Golden Banana Movie Festival as x; we don't know its value yet but will find it out later. Define total number of movies in Golden Banana Movie Festival as m; z = x + T = x + 2 = x + 2; so m = z + e = x + 2 + 3 = x + 5. We know m = 9, so we have x + 5 = 9 and we solve it through the following steps: Simplifying the equation: x + 5 = 9. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.", "op": 7, "id": "16_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of regional medical school in Brightford equals 4 plus the number of culinarian school in Brightford. The number of culinarian school in Evervale City exists, and its number is greater than 0. The number of regional medical school in Evervale City equals the number of regional medical school in Brightford. The total number of schools in Evervale City equals 8. The number of culinarian school in Brightford equals 2. ", "question": "How many culinarian school does Evervale City have?", "solution": "The question is difficult, so we use equations to solve it. Define culinarian school in Brightford as W; so W = 2. Define regional medical school in Brightford as C; u = W = 2; so C = 4 + u = 4 + 2 = 6. Define regional medical school in Evervale City as E; so E = C = 6. Define culinarian school in Evervale City as x; we don't know its value yet but will find it out later. Define total number of schools in Evervale City as V; so V = x + E = x + 6 = x + 6. We know V = 8, so we have x + 6 = 8 and we solve it through the following steps: Simplifying the equation: x + 6 = 8. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "11_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of culinarian school in Evervale City equals 3. The number of public highschool in Hawkesbury equals 3. The number of regional medical school in Glenfield City equals 3 times the number of public highschool in Glenfield City. The number of public highschool in Evervale City equals 4. The number of regional medical school in Hawkesbury equals 1. The number of public highschool in Glenfield City equals the number of culinarian school in Glenfield City. The number of culinarian school in Glenfield City equals 4. ", "question": "What is the total number of schools in Glenfield City?", "solution": "Define culinarian school in Glenfield City as V; so V = 4. Define public highschool in Glenfield City as R; so R = V = 4. Define regional medical school in Glenfield City as q; n = R = 4; so q = 3 * n = 3 * 4 = 12. Define total number of schools in Glenfield City as w; J = V + R = 4 + 4 = 8; so w = J + q = 8 + 12 = 20. Answer: 20.", "op": 7, "id": "18_p5", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult racoon in Cedar Valley equals 4 times the number of adult bear in Pine Ridge. The total number of adult animals in Cedar Valley equals 16. The number of adult bear in Cedar Valley equals the number of adult racoon in Cedar Valley. The number of adult bear in Pine Ridge equals the number of adult racoon in Oakridge Riverside. The number of adult racoon in Oakridge Riverside exists, and its number is greater than 0. The number of adult deer in Oakridge Riverside equals 2. ", "question": "How many adult racoon does Oakridge Riverside have?", "solution": "The question is difficult, so we use equations to solve it. Define adult racoon in Oakridge Riverside as x; we don't know its value yet but will find it out later. Define adult bear in Pine Ridge as w; so w = x = x. Define adult racoon in Cedar Valley as f; U = w = x; so f = 4 * U = (4) * (x) = 4*x. Define adult bear in Cedar Valley as B; so B = f = 4*x. Define total number of adult animals in Cedar Valley as p; so p = B + f = 4*x + 4*x = 8*x. We know p = 16, so we have 8*x = 16 and we solve it through the following steps: Simplifying the equation: 8*x = 16. Move all terms to one side: 8*x - 16 = 0. Isolate the term with x: 8*x = 16. Divide both sides by 8: x = 16 / 8. Solution: x = 2. Answer: 2.", "op": 7, "id": "19_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult fox in Hamilton Farm equals 2 times the number of adult racoon in Hamilton Farm. The number of adult wolf in Jefferson Circus equals 4. The number of adult racoon in Bundle Ranch equals 4 plus the difference between the number of adult wolf in Hamilton Farm and the total number of adult animals in Bundle Ranch. The number of adult wolf in Hamilton Farm equals the number of adult fox in Hamilton Farm. The total number of adult animals in Hamilton Farm equals 10. The number of adult fox in Jefferson Circus equals 1. The number of adult racoon in Hamilton Farm exists, and its number is greater than 0. The number of adult wolf in Bundle Ranch equals the number of adult wolf in Hamilton Farm. The number of adult fox in Bundle Ranch equals 2. ", "question": "How many adult racoon does Hamilton Farm have?", "solution": "The question is difficult, so we use equations to solve it. Define adult racoon in Hamilton Farm as x; we don't know its value yet but will find it out later. Define adult fox in Hamilton Farm as v; o = x = x; so v = 2 * o = (2) * (x) = 2*x. Define adult wolf in Hamilton Farm as c; so c = v = 2*x. Define total number of adult animals in Hamilton Farm as q; B = c + x = 2*x + x = 3*x; so q = B + v = 3*x + 2*x = 5*x. We know q = 10, so we have 5*x = 10 and we solve it through the following steps: Simplifying the equation: 5*x = 10. Move all terms to one side: 5*x - 10 = 0. Isolate the term with x: 5*x = 10. Divide both sides by 5: x = 10 / 5. Solution: x = 2. Answer: 2.", "op": 7, "id": "7_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult deer in South Zoo equals 2. The number of adult deer in Mayer Aquarium equals the difference between the total number of adult animals in South Zoo and the number of adult wolf in South Zoo. The number of adult wolf in Mayer Aquarium equals the sum of the number of adult wolf in South Zoo, the total number of adult animals in South Zoo, and the number of adult wolf in Jefferson Circus. The total number of adult animals in South Zoo equals 8. The number of adult bear in South Zoo equals 2 times the number of adult wolf in South Zoo. The number of adult wolf in South Zoo exists, and its number is greater than 0. The number of adult bear in Mayer Aquarium equals the number of adult deer in Jefferson Circus. The number of adult deer in Jefferson Circus equals 3. The number of adult bear in Jefferson Circus equals 2. The number of adult wolf in Jefferson Circus equals 2. ", "question": "How many adult wolf does South Zoo have?", "solution": "The question is difficult, so we use equations to solve it. Define adult deer in South Zoo as b; so b = 2. Define adult wolf in South Zoo as x; we don't know its value yet but will find it out later. Define adult bear in South Zoo as O; I = x = x; so O = 2 * I = (2) * (x) = 2*x. Define total number of adult animals in South Zoo as Q; F = b + x = 2 + x = x + 2; so Q = F + O = x + 2 + 2*x = 3*x + 2. We know Q = 8, so we have 3*x + 2 = 8 and we solve it through the following steps: Simplifying the equation: 3*x + 2 = 8. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.", "op": 7, "id": "17_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of adult animals in Hamilton Farm equals 5. The number of adult blue jay in Hamilton Farm equals 1. The number of adult owl in Hamilton Farm exists, and its number is greater than 0. The number of adult blue jay in South Zoo equals 4. The number of adult owl in Bundle Ranch equals 4. The number of adult eagle in Hamilton Farm equals the number of adult blue jay in Bundle Ranch. The number of adult eagle in Bundle Ranch equals 2. The number of adult blue jay in Bundle Ranch equals 3. The number of adult eagle in South Zoo equals 1 plus the total number of adult animals in Bundle Ranch. The number of adult owl in South Zoo equals 3 times the sum of the number of adult eagle in Bundle Ranch, the number of adult eagle in South Zoo, and the number of adult blue jay in South Zoo. ", "question": "How many adult owl does Hamilton Farm have?", "solution": "The question is difficult, so we use equations to solve it. Define adult blue jay in Bundle Ranch as A; so A = 3. Define adult eagle in Hamilton Farm as o; so o = A = 3. Define adult blue jay in Hamilton Farm as M; so M = 1. Define adult owl in Hamilton Farm as x; we don't know its value yet but will find it out later. Define total number of adult animals in Hamilton Farm as V; c = M + o = 1 + 3 = 4; so V = c + x = 4 + x = x + 4. We know V = 5, so we have x + 4 = 5 and we solve it through the following steps: Simplifying the equation: x + 4 = 5. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1.", "op": 7, "id": "19_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult bear in Beverly Forest exists, and its number is greater than 0. The total number of adult animals in Maple Creek equals 9. The number of adult bear in Maple Creek equals 3 plus the sum of the number of adult wolf in Beverly Forest and the number of adult bear in Beverly Forest. The number of adult wolf in Beverly Forest equals 2 plus the number of adult bear in Beverly Forest. ", "question": "How many adult bear does Beverly Forest have?", "solution": "The question is difficult, so we use equations to solve it. Define adult bear in Beverly Forest as x; we don't know its value yet but will find it out later. Define adult wolf in Beverly Forest as m; L = x = x; so m = 2 + L = 2 + x = x + 2. Define adult bear in Maple Creek as a; A = m + x = x + 2 + x = 2*x + 2; so a = 3 + A = 3 + 2*x + 2 = 2*x + 5. Define total number of adult animals in Maple Creek as n; so n = a = 2*x + 5. We know n = 9, so we have 2*x + 5 = 9 and we solve it through the following steps: Simplifying the equation: 2*x + 5 = 9. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.", "op": 7, "id": "11_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in Cin\u00e9ma de Montreval equals 3. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 4. The number of solemn period drama in Festival de Saint-Rivage equals 2. The number of upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont equals 3. The number of upbeat metropolis comedy in Cin\u00e9ma de Montreval equals 2 times the number of solemn period drama in Festival de Saint-Rivage. The number of calm road movie in Cin\u00e9ma de Montreval equals 4 times the number of calm road movie in Festival Lumi\u00e8re de Valmont. The total number of movies in Festival Lumi\u00e8re de Valmont equals 11. The number of calm road movie in Festival Lumi\u00e8re de Valmont equals the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of solemn period drama in Festival Lumi\u00e8re de Valmont exists, and its number is greater than 0. The number of calm road movie in Festival de Saint-Rivage equals 2 plus the number of upbeat metropolis comedy in Festival de Saint-Rivage. ", "question": "How many solemn period drama does Festival Lumi\u00e8re de Valmont have?", "solution": "The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont as w; so w = 3. Define upbeat metropolis comedy in Festival de Saint-Rivage as l; so l = 4. Define solemn period drama in Festival Lumi\u00e8re de Valmont as x; we don't know its value yet but will find it out later. Define calm road movie in Festival Lumi\u00e8re de Valmont as K; so K = l = 4. Define total number of movies in Festival Lumi\u00e8re de Valmont as W; n = K + x = 4 + x = x + 4; so W = n + w = x + 4 + 3 = x + 7. We know W = 11, so we have x + 7 = 11 and we solve it through the following steps: Simplifying the equation: x + 7 = 11. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.", "op": 7, "id": "11_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of calm road movie in Northwood Movie Festival exists, and its number is greater than 0. The number of intense detective thriller in Golden Banana Movie Festival equals 1. The number of upbeat metropolis comedy in Verdi Movie Festival equals 3 times the number of calm road movie in Golden Banana Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals the number of calm road movie in Northwood Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 3. The number of upbeat metropolis comedy in Northwood Movie Festival equals 3 times the number of calm road movie in Northwood Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals the sum of the number of intense detective thriller in Golden Banana Movie Festival, the number of calm road movie in Northwood Movie Festival, the number of intense detective thriller in Northwood Movie Festival, and the total number of movies in Northwood Movie Festival. The total number of movies in Northwood Movie Festival equals 10. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 3 times the number of calm road movie in Verdi Movie Festival. The number of calm road movie in Verdi Movie Festival equals 2. ", "question": "How many calm road movie does Northwood Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define calm road movie in Northwood Movie Festival as x; we don't know its value yet but will find it out later. Define intense detective thriller in Northwood Movie Festival as O; so O = x = x. Define upbeat metropolis comedy in Northwood Movie Festival as d; f = x = x; so d = 3 * f = (3) * (x) = 3*x. Define total number of movies in Northwood Movie Festival as R; e = x + d = x + 3*x = 4*x; so R = e + O = 4*x + x = 5*x. We know R = 10, so we have 5*x = 10 and we solve it through the following steps: Simplifying the equation: 5*x = 10. Move all terms to one side: 5*x - 10 = 0. Isolate the term with x: 5*x = 10. Divide both sides by 5: x = 10 / 5. Solution: x = 2. Answer: 2.", "op": 7, "id": "20_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of upbeat metropolis comedy in Cin\u00e9ma de Montreval equals the sum of the number of upbeat metropolis comedy in Festival de Saint-Rivage, the total number of movies in Festival de Clairmont, the number of intense detective thriller in Festival de Clairmont, and the number of futuristic sci-fi movie in Festival de Clairmont. The number of upbeat metropolis comedy in Festival de Clairmont equals the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Cin\u00e9ma de Montreval equals 2 plus the number of intense detective thriller in Festival de Clairmont. The number of upbeat metropolis comedy in Festival de Saint-Rivage exists, and its number is greater than 0. The number of intense detective thriller in Festival de Saint-Rivage equals 4. The number of futuristic sci-fi movie in Festival de Clairmont equals the sum of the total number of movies in Festival de Saint-Rivage, the number of futuristic sci-fi movie in Festival de Saint-Rivage, and the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of intense detective thriller in Festival de Clairmont equals 4. The total number of movies in Festival de Saint-Rivage equals 18. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 3 times the number of intense detective thriller in Festival de Saint-Rivage. ", "question": "How many upbeat metropolis comedy does Festival de Saint-Rivage have?", "solution": "The question is difficult, so we use equations to solve it. Define intense detective thriller in Festival de Saint-Rivage as D; so D = 4. Define futuristic sci-fi movie in Festival de Saint-Rivage as y; h = D = 4; so y = 3 * h = (3) * (4) = 12. Define upbeat metropolis comedy in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define total number of movies in Festival de Saint-Rivage as Y; T = x + y = x + 12 = x + 12; so Y = T + D = x + 12 + 4 = x + 16. We know Y = 18, so we have x + 16 = 18 and we solve it through the following steps: Simplifying the equation: x + 16 = 18. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "7_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of movies in West Sahara Movie Festival equals 8. The number of calm road movie in West Sahara Movie Festival equals 2 times the number of intense detective thriller in West Sahara Movie Festival. The number of solemn period drama in Taylor Movie Festival equals the number of solemn period drama in West Sahara Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals the number of intense detective thriller in West Sahara Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 4. The number of calm road movie in Golden Banana Movie Festival equals the number of calm road movie in West Sahara Movie Festival. The number of intense detective thriller in West Sahara Movie Festival exists, and its number is greater than 0. The number of intense detective thriller in Golden Banana Movie Festival equals 2 plus the number of solemn period drama in Golden Banana Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 2 times the number of intense detective thriller in Taylor Movie Festival. The number of calm road movie in Taylor Movie Festival equals the number of solemn period drama in West Sahara Movie Festival. ", "question": "How many intense detective thriller does West Sahara Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define intense detective thriller in West Sahara Movie Festival as x; we don't know its value yet but will find it out later. Define solemn period drama in West Sahara Movie Festival as a; so a = x = x. Define calm road movie in West Sahara Movie Festival as T; B = x = x; so T = 2 * B = (2) * (x) = 2*x. Define total number of movies in West Sahara Movie Festival as u; k = a + x = x + x = 2*x; so u = k + T = 2*x + 2*x = 4*x. We know u = 8, so we have 4*x = 8 and we solve it through the following steps: Simplifying the equation: 4*x = 8. Move all terms to one side: 4*x - 8 = 0. Isolate the term with x: 4*x = 8. Divide both sides by 4: x = 8 / 4. Solution: x = 2. Answer: 2.", "op": 7, "id": "2_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of movies in Festival de Saint-Rivage equals 8. The number of calm road movie in Cin\u00e9ma de Montreval equals 2. The number of solemn period drama in Festival de Saint-Rivage exists, and its number is greater than 0. The number of calm road movie in Festival de Saint-Rivage equals 2 times the number of solemn period drama in Festival de Saint-Rivage. The number of calm road movie in R\u00eaves de Belleville equals 3. The number of solemn period drama in R\u00eaves de Belleville equals the sum of the number of upbeat metropolis comedy in R\u00eaves de Belleville and the number of solemn period drama in Cin\u00e9ma de Montreval. The number of upbeat metropolis comedy in Cin\u00e9ma de Montreval equals the sum of the total number of movies in Festival de Saint-Rivage, the number of calm road movie in Festival de Saint-Rivage, the number of upbeat metropolis comedy in Festival de Saint-Rivage, and the number of solemn period drama in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the number of solemn period drama in Festival de Saint-Rivage. The number of upbeat metropolis comedy in R\u00eaves de Belleville equals the number of calm road movie in R\u00eaves de Belleville. The number of solemn period drama in Cin\u00e9ma de Montreval equals the number of calm road movie in R\u00eaves de Belleville. ", "question": "How many solemn period drama does Festival de Saint-Rivage have?", "solution": "The question is difficult, so we use equations to solve it. Define solemn period drama in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in Festival de Saint-Rivage as i; so i = x = x. Define calm road movie in Festival de Saint-Rivage as s; E = x = x; so s = 2 * E = (2) * (x) = 2*x. Define total number of movies in Festival de Saint-Rivage as V; a = s + x = 2*x + x = 3*x; so V = a + i = 3*x + x = 4*x. We know V = 8, so we have 4*x = 8 and we solve it through the following steps: Simplifying the equation: 4*x = 8. Move all terms to one side: 4*x - 8 = 0. Isolate the term with x: 4*x = 8. Divide both sides by 4: x = 8 / 4. Solution: x = 2. Answer: 2.", "op": 7, "id": "17_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of intense detective thriller in West Sahara Movie Festival equals the number of calm road movie in Golden Banana Movie Festival. The number of solemn period drama in Taylor Movie Festival equals the sum of the number of calm road movie in West Sahara Movie Festival, the total number of movies in Taylor Movie Festival, the total number of movies in West Sahara Movie Festival, and the number of solemn period drama in Golden Banana Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 3. The total number of movies in West Sahara Movie Festival equals 8. The number of solemn period drama in West Sahara Movie Festival equals 4. The number of intense detective thriller in Taylor Movie Festival equals 2. The number of calm road movie in West Sahara Movie Festival exists, and its number is greater than 0. The number of calm road movie in Taylor Movie Festival equals 2. The number of intense detective thriller in Golden Banana Movie Festival equals the total number of movies in Taylor Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals the number of calm road movie in West Sahara Movie Festival. ", "question": "How many calm road movie does West Sahara Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define solemn period drama in West Sahara Movie Festival as m; so m = 4. Define calm road movie in West Sahara Movie Festival as x; we don't know its value yet but will find it out later. Define calm road movie in Golden Banana Movie Festival as e; so e = x = x. Define intense detective thriller in West Sahara Movie Festival as D; so D = e = x. Define total number of movies in West Sahara Movie Festival as O; p = x + D = x + x = 2*x; so O = p + m = 2*x + 4 = 2*x + 4. We know O = 8, so we have 2*x + 4 = 8 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 8. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.", "op": 7, "id": "22_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult fox in Cedar Valley equals the number of adult wolf in Cedar Valley. The number of adult racoon in Cedar Valley equals the number of adult fox in Oakridge Riverside. The number of adult wolf in Oakridge Riverside equals 3. The number of adult fox in Pine Ridge equals 4 times the number of adult wolf in Pine Ridge. The number of adult fox in Oakridge Riverside equals 4. The number of adult wolf in Pine Ridge exists, and its number is greater than 0. The number of adult racoon in Pine Ridge equals the number of adult wolf in Pine Ridge. The total number of adult animals in Pine Ridge equals 12. The number of adult racoon in Oakridge Riverside equals 4. The number of adult wolf in Cedar Valley equals 1. ", "question": "How many adult wolf does Pine Ridge have?", "solution": "The question is difficult, so we use equations to solve it. Define adult wolf in Pine Ridge as x; we don't know its value yet but will find it out later. Define adult fox in Pine Ridge as P; i = x = x; so P = 4 * i = (4) * (x) = 4*x. Define adult racoon in Pine Ridge as d; so d = x = x. Define total number of adult animals in Pine Ridge as B; u = P + x = 4*x + x = 5*x; so B = u + d = 5*x + x = 6*x. We know B = 12, so we have 6*x = 12 and we solve it through the following steps: Simplifying the equation: 6*x = 12. Move all terms to one side: 6*x - 12 = 0. Isolate the term with x: 6*x = 12. Divide both sides by 6: x = 12 / 6. Solution: x = 2. Answer: 2.", "op": 7, "id": "2_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult eagle in Bundle Ranch equals 3. The number of adult eagle in Jefferson Circus equals 3 plus the difference between the number of adult owl in Bundle Ranch and the number of adult crow in Jefferson Circus. The number of adult owl in Mayer Aquarium equals 4 plus the total number of adult animals in Bundle Ranch. The number of adult eagle in Mayer Aquarium equals the sum of the number of adult crow in Jefferson Circus, the number of adult owl in Mayer Aquarium, and the number of adult crow in Bundle Ranch. The total number of adult animals in Jefferson Circus equals 4. The number of adult crow in Mayer Aquarium equals 1. The number of adult owl in Bundle Ranch equals the number of adult crow in Jefferson Circus. The number of adult crow in Bundle Ranch equals 4. The number of adult crow in Jefferson Circus exists, and its number is greater than 0. ", "question": "How many adult crow does Jefferson Circus have?", "solution": "The question is difficult, so we use equations to solve it. Define adult crow in Jefferson Circus as x; we don't know its value yet but will find it out later. Define adult owl in Bundle Ranch as b; so b = x = x. Define adult eagle in Jefferson Circus as r; D = b - x = (x) - (x) = 0; so r = 3 + D = 3 + 0 = 3. Define total number of adult animals in Jefferson Circus as B; so B = r + x = 3 + x = x + 3. We know B = 4, so we have x + 3 = 4 and we solve it through the following steps: Simplifying the equation: x + 3 = 4. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1.", "op": 7, "id": "3_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of elementary school in Westhaven City exists, and its number is greater than 0. The number of elementary school in Hawkesbury equals the number of public highschool in Evervale City. The total number of schools in Hawkesbury equals 8. The number of public highschool in Westhaven City equals 4. The number of private middle school in Westhaven City equals the total number of schools in Westhaven City. The number of private middle school in Evervale City equals the number of private middle school in Westhaven City. The number of public highschool in Evervale City equals the number of elementary school in Westhaven City. The number of elementary school in Evervale City equals 1. The number of public highschool in Hawkesbury equals 4 plus the number of elementary school in Hawkesbury. ", "question": "How many elementary school does Westhaven City have?", "solution": "The question is difficult, so we use equations to solve it. Define elementary school in Westhaven City as x; we don't know its value yet but will find it out later. Define public highschool in Evervale City as N; so N = x = x. Define elementary school in Hawkesbury as c; so c = N = x. Define public highschool in Hawkesbury as W; M = c = x; so W = 4 + M = 4 + x = x + 4. Define total number of schools in Hawkesbury as k; so k = W + c = x + 4 + x = 2*x + 4. We know k = 8, so we have 2*x + 4 = 8 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 8. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.", "op": 7, "id": "17_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in Festival de Saint-Rivage equals 1. The number of calm road movie in R\u00eaves de Belleville exists, and its number is greater than 0. The number of solemn period drama in Festival Lumi\u00e8re de Valmont equals 4 times the sum of the number of calm road movie in Festival de Saint-Rivage, the number of solemn period drama in Festival de Saint-Rivage, and the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of calm road movie in Festival Lumi\u00e8re de Valmont equals 3. The number of calm road movie in Festival de Saint-Rivage equals 4. The number of futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont equals 3. The number of solemn period drama in R\u00eaves de Belleville equals 3. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals the difference between the number of calm road movie in Festival de Saint-Rivage and the number of solemn period drama in Festival de Saint-Rivage. The total number of movies in R\u00eaves de Belleville equals 13. The number of futuristic sci-fi movie in R\u00eaves de Belleville equals 2 times the number of solemn period drama in R\u00eaves de Belleville. ", "question": "How many calm road movie does R\u00eaves de Belleville have?", "solution": "The question is difficult, so we use equations to solve it. Define solemn period drama in R\u00eaves de Belleville as Q; so Q = 3. Define futuristic sci-fi movie in R\u00eaves de Belleville as w; n = Q = 3; so w = 2 * n = (2) * (3) = 6. Define calm road movie in R\u00eaves de Belleville as x; we don't know its value yet but will find it out later. Define total number of movies in R\u00eaves de Belleville as q; W = Q + w = 3 + 6 = 9; so q = W + x = 9 + x = x + 9. We know q = 13, so we have x + 9 = 13 and we solve it through the following steps: Simplifying the equation: x + 9 = 13. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.", "op": 7, "id": "8_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult fox in Jefferson Circus equals 3. The number of adult wolf in Bundle Ranch equals 2 plus the sum of the number of adult fox in Jefferson Circus and the total number of adult animals in Hamilton Farm. The number of adult fox in South Zoo equals 4. The number of adult deer in Hamilton Farm equals 2 times the number of adult fox in Jefferson Circus. The number of adult deer in Bundle Ranch equals the sum of the total number of adult animals in Hamilton Farm, the number of adult deer in Hamilton Farm, and the number of adult fox in Jefferson Circus. The number of adult bear in South Zoo equals 3 times the difference between the number of adult deer in Hamilton Farm and the number of adult fox in Jefferson Circus. ", "question": "How many adult deer does Bundle Ranch have?", "solution": "Define adult fox in Jefferson Circus as Q; so Q = 3. Define adult deer in Hamilton Farm as k; e = Q = 3; so k = 2 * e = 2 * 3 = 6. Define total number of adult animals in Hamilton Farm as V; so V = k = 6. Define adult deer in Bundle Ranch as X; M = V + k = 6 + 6 = 12; so X = M + Q = 12 + 3 = 15. Answer: 15.", "op": 7, "id": "3_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The total number of schools in Riverton City equals 15. The number of public highschool in Riverton City exists, and its number is greater than 0. The number of regional medical school in Shoreline City equals 4. The number of regional medical school in Riverton City equals 3 times the number of public highschool in Riverton City. The number of public highschool in Shoreline City equals 3. The number of regional medical school in Ruby Bay equals 3 times the difference between the number of public highschool in Shoreline City and the number of private middle school in Riverton City. The number of public highschool in Ruby Bay equals the number of public highschool in Riverton City. The number of private middle school in Riverton City equals the number of public highschool in Riverton City. The number of private middle school in Shoreline City equals 3 plus the total number of schools in Riverton City. The number of private middle school in Ruby Bay equals 3. ", "question": "How many public highschool does Riverton City have?", "solution": "The question is difficult, so we use equations to solve it. Define public highschool in Riverton City as x; we don't know its value yet but will find it out later. Define private middle school in Riverton City as F; so F = x = x. Define regional medical school in Riverton City as U; K = x = x; so U = 3 * K = (3) * (x) = 3*x. Define total number of schools in Riverton City as n; w = F + U = x + 3*x = 4*x; so n = w + x = 4*x + x = 5*x. We know n = 15, so we have 5*x = 15 and we solve it through the following steps: Simplifying the equation: 5*x = 15. Move all terms to one side: 5*x - 15 = 0. Isolate the term with x: 5*x = 15. Divide both sides by 5: x = 15 / 5. Solution: x = 3. Answer: 3.", "op": 7, "id": "16_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of schools in Brightford equals 4. The number of private middle school in Evervale City equals 2 times the total number of schools in Westhaven City. The number of regional medical school in Westhaven City exists, and its number is greater than 0. The number of elementary school in Brightford equals the total number of schools in Evervale City. ", "question": "How many regional medical school does Westhaven City have?", "solution": "The question is difficult, so we use equations to solve it. Define regional medical school in Westhaven City as x; we don't know its value yet but will find it out later. Define total number of schools in Westhaven City as w; so w = x = x. Define private middle school in Evervale City as Q; T = w = x; so Q = 2 * T = (2) * (x) = 2*x. Define total number of schools in Evervale City as r; so r = Q = 2*x. Define elementary school in Brightford as t; so t = r = 2*x. Define total number of schools in Brightford as v; so v = t = 2*x. We know v = 4, so we have 2*x = 4 and we solve it through the following steps: Simplifying the equation: 2*x = 4. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.", "op": 7, "id": "7_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of schools in Riverton City equals 7. The number of elementary school in Shoreline City equals the difference between the number of public highschool in Ruby Bay and the number of culinarian school in Ruby Bay. The number of public highschool in Ruby Bay equals 2. The number of elementary school in Riverton City equals 3 times the number of public highschool in Riverton City. The number of culinarian school in Riverton City exists, and its number is greater than 0. The number of public highschool in Riverton City equals 1. The number of culinarian school in Ruby Bay equals 1 plus the number of public highschool in Ruby Bay. The number of elementary school in Ruby Bay equals 3 times the difference between the total number of schools in Riverton City and the number of culinarian school in Riverton City. ", "question": "How many culinarian school does Riverton City have?", "solution": "The question is difficult, so we use equations to solve it. Define public highschool in Riverton City as P; so P = 1. Define culinarian school in Riverton City as x; we don't know its value yet but will find it out later. Define elementary school in Riverton City as n; Q = P = 1; so n = 3 * Q = (3) * (1) = 3. Define total number of schools in Riverton City as I; N = P + n = 1 + 3 = 4; so I = N + x = 4 + x = x + 4. We know I = 7, so we have x + 4 = 7 and we solve it through the following steps: Simplifying the equation: x + 4 = 7. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.", "op": 7, "id": "10_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of elementary school in Shoreline City equals the number of private middle school in Clearwater Bay. The number of public highschool in Riverton City equals 2. The number of public highschool in Shoreline City equals the sum of the total number of schools in Clearwater Bay and the number of private middle school in Clearwater Bay. The number of private middle school in Clearwater Bay exists, and its number is greater than 0. The total number of schools in Shoreline City equals 9. ", "question": "How many private middle school does Clearwater Bay have?", "solution": "The question is difficult, so we use equations to solve it. Define private middle school in Clearwater Bay as x; we don't know its value yet but will find it out later. Define total number of schools in Clearwater Bay as v; so v = x = x. Define public highschool in Shoreline City as q; so q = v + x = x + x = 2*x. Define elementary school in Shoreline City as U; so U = x = x. Define total number of schools in Shoreline City as K; so K = U + q = x + 2*x = 3*x. We know K = 9, so we have 3*x = 9 and we solve it through the following steps: Simplifying the equation: 3*x = 9. Move all terms to one side: 3*x - 9 = 0. Isolate the term with x: 3*x = 9. Divide both sides by 3: x = 9 / 3. Solution: x = 3. Answer: 3.", "op": 7, "id": "20_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of schools in Brightford equals 11. The number of private middle school in Westhaven City exists, and its number is greater than 0. The number of public highschool in Westhaven City equals 3 plus the number of private middle school in Westhaven City. The number of public highschool in Brightford equals the total number of schools in Westhaven City. ", "question": "How many private middle school does Westhaven City have?", "solution": "The question is difficult, so we use equations to solve it. Define private middle school in Westhaven City as x; we don't know its value yet but will find it out later. Define public highschool in Westhaven City as J; O = x = x; so J = 3 + O = 3 + x = x + 3. Define total number of schools in Westhaven City as N; so N = J + x = x + 3 + x = 2*x + 3. Define public highschool in Brightford as k; so k = N = 2*x + 3. Define total number of schools in Brightford as M; so M = k = 2*x + 3. We know M = 11, so we have 2*x + 3 = 11 and we solve it through the following steps: Simplifying the equation: 2*x + 3 = 11. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.", "op": 7, "id": "14_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult bear in Oakridge Riverside equals the number of adult deer in Beverly Forest. The number of adult racoon in Beverly Forest equals the sum of the number of adult racoon in Pine Ridge and the number of adult deer in Beverly Forest. The number of adult bear in Pine Ridge equals 1 plus the number of adult deer in Oakridge Riverside. The number of adult deer in Oakridge Riverside equals 2. The total number of adult animals in Beverly Forest equals 36. The number of adult deer in Beverly Forest equals 4 times the number of adult racoon in Pine Ridge. The number of adult deer in Pine Ridge equals 2 times the total number of adult animals in Oakridge Riverside. The number of adult racoon in Pine Ridge exists, and its number is greater than 0. The number of adult racoon in Oakridge Riverside equals the sum of the total number of adult animals in Oakridge Riverside and the number of adult racoon in Beverly Forest. ", "question": "How many adult racoon does Pine Ridge have?", "solution": "The question is difficult, so we use equations to solve it. Define adult racoon in Pine Ridge as x; we don't know its value yet but will find it out later. Define adult deer in Beverly Forest as n; M = x = x; so n = 4 * M = (4) * (x) = 4*x. Define adult racoon in Beverly Forest as c; so c = x + n = x + 4*x = 5*x. Define total number of adult animals in Beverly Forest as v; so v = n + c = 4*x + 5*x = 9*x. We know v = 36, so we have 9*x = 36 and we solve it through the following steps: Simplifying the equation: 9*x = 36. Move all terms to one side: 9*x - 36 = 0. Isolate the term with x: 9*x = 36. Divide both sides by 9: x = 36 / 9. Solution: x = 4. Answer: 4.", "op": 7, "id": "14_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of regional medical school in Glenfield City equals 3 times the difference between the number of public highschool in Glenfield City and the total number of schools in Glenfield City. The number of culinarian school in Westhaven City equals 4 plus the number of public highschool in Brightford. The total number of schools in Brightford equals 22. The number of culinarian school in Brightford exists, and its number is greater than 0. The number of public highschool in Brightford equals 4. The number of public highschool in Westhaven City equals 3. The number of public highschool in Glenfield City equals the sum of the number of public highschool in Brightford, the number of culinarian school in Brightford, the number of regional medical school in Brightford, and the total number of schools in Brightford. The number of regional medical school in Brightford equals 4 times the number of public highschool in Brightford. The number of regional medical school in Westhaven City equals the difference between the number of regional medical school in Brightford and the number of culinarian school in Glenfield City. The number of culinarian school in Glenfield City equals 3. ", "question": "How many culinarian school does Brightford have?", "solution": "The question is difficult, so we use equations to solve it. Define public highschool in Brightford as y; so y = 4. Define regional medical school in Brightford as u; a = y = 4; so u = 4 * a = (4) * (4) = 16. Define culinarian school in Brightford as x; we don't know its value yet but will find it out later. Define total number of schools in Brightford as s; D = x + y = x + 4 = x + 4; so s = D + u = x + 4 + 16 = x + 20. We know s = 22, so we have x + 20 = 22 and we solve it through the following steps: Simplifying the equation: x + 20 = 22. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "21_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult racoon in Oakridge Riverside equals 3 times the number of adult racoon in Pine Ridge. The number of adult deer in Pine Ridge equals the sum of the total number of adult animals in Oakridge Riverside and the number of adult wolf in Oakridge Riverside. The number of adult racoon in Pine Ridge exists, and its number is greater than 0. The number of adult wolf in Oakridge Riverside equals 2 plus the number of adult racoon in Oakridge Riverside. The total number of adult animals in Oakridge Riverside equals 20. The number of adult wolf in Pine Ridge equals 3. ", "question": "How many adult racoon does Pine Ridge have?", "solution": "The question is difficult, so we use equations to solve it. Define adult racoon in Pine Ridge as x; we don't know its value yet but will find it out later. Define adult racoon in Oakridge Riverside as t; F = x = x; so t = 3 * F = (3) * (x) = 3*x. Define adult wolf in Oakridge Riverside as G; Y = t = 3*x; so G = 2 + Y = 2 + 3*x = 3*x + 2. Define total number of adult animals in Oakridge Riverside as m; so m = G + t = 3*x + 2 + 3*x = 6*x + 2. We know m = 20, so we have 6*x + 2 = 20 and we solve it through the following steps: Simplifying the equation: 6*x + 2 = 20. Move all terms to one side: 6*x - 18 = 0. Isolate the term with x: 6*x = 18. Divide both sides by 6: x = 18 / 6. Solution: x = 3. Answer: 3.", "op": 7, "id": "16_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in Festival de Clairmont equals 4. The number of intense detective thriller in Festival de Clairmont equals 2. The number of upbeat metropolis comedy in Festival de Clairmont equals 3 times the difference between the number of upbeat metropolis comedy in R\u00eaves de Belleville and the total number of movies in R\u00eaves de Belleville. The number of upbeat metropolis comedy in Cin\u00e9ma de Montreval equals the number of intense detective thriller in Cin\u00e9ma de Montreval. The number of solemn period drama in Cin\u00e9ma de Montreval equals 1. The number of intense detective thriller in R\u00eaves de Belleville equals 3. The number of upbeat metropolis comedy in R\u00eaves de Belleville exists, and its number is greater than 0. The number of solemn period drama in R\u00eaves de Belleville equals 2 times the number of intense detective thriller in R\u00eaves de Belleville. The number of intense detective thriller in Cin\u00e9ma de Montreval equals 3 plus the number of solemn period drama in Cin\u00e9ma de Montreval. The total number of movies in R\u00eaves de Belleville equals 13. ", "question": "How many upbeat metropolis comedy does R\u00eaves de Belleville have?", "solution": "The question is difficult, so we use equations to solve it. Define intense detective thriller in R\u00eaves de Belleville as l; so l = 3. Define upbeat metropolis comedy in R\u00eaves de Belleville as x; we don't know its value yet but will find it out later. Define solemn period drama in R\u00eaves de Belleville as b; j = l = 3; so b = 2 * j = (2) * (3) = 6. Define total number of movies in R\u00eaves de Belleville as f; Q = l + x = 3 + x = x + 3; so f = Q + b = x + 3 + 6 = x + 9. We know f = 13, so we have x + 9 = 13 and we solve it through the following steps: Simplifying the equation: x + 9 = 13. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.", "op": 7, "id": "11_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont equals 1. The number of calm road movie in Festival de Clairmont equals 4. The number of calm road movie in Festival Lumi\u00e8re de Valmont equals 4 times the sum of the number of calm road movie in Festival de Saint-Rivage, the total number of movies in Festival de Saint-Rivage, and the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival de Clairmont equals 4. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 2. The number of upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont equals the number of futuristic sci-fi movie in Festival de Clairmont. The total number of movies in Festival de Saint-Rivage equals 10. The number of futuristic sci-fi movie in Festival de Saint-Rivage exists, and its number is greater than 0. The number of calm road movie in Festival de Saint-Rivage equals 2 times the number of upbeat metropolis comedy in Festival de Saint-Rivage. ", "question": "How many futuristic sci-fi movie does Festival de Saint-Rivage have?", "solution": "The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in Festival de Saint-Rivage as m; so m = 2. Define calm road movie in Festival de Saint-Rivage as q; L = m = 2; so q = 2 * L = (2) * (2) = 4. Define futuristic sci-fi movie in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define total number of movies in Festival de Saint-Rivage as k; p = m + q = 2 + 4 = 6; so k = p + x = 6 + x = x + 6. We know k = 10, so we have x + 6 = 10 and we solve it through the following steps: Simplifying the equation: x + 6 = 10. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.", "op": 7, "id": "10_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of intense detective thriller in Golden Banana Movie Festival equals the number of intense detective thriller in Northwood Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals the number of upbeat metropolis comedy in West Sahara Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the number of intense detective thriller in Golden Banana Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 3. The number of calm road movie in Golden Banana Movie Festival equals 2. The number of upbeat metropolis comedy in Northwood Movie Festival equals 1. The number of calm road movie in Northwood Movie Festival equals 16. The number of upbeat metropolis comedy in West Sahara Movie Festival exists, and its number is greater than 0. The number of calm road movie in West Sahara Movie Festival equals 4 plus the number of intense detective thriller in West Sahara Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival exists, and its number is greater than 0. ", "question": "How many upbeat metropolis comedy does West Sahara Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in West Sahara Movie Festival as x; we don't know its value yet but will find it out later. Define intense detective thriller in West Sahara Movie Festival as o; so o = x = x. Define calm road movie in West Sahara Movie Festival as e; t = o = x; so e = 4 + t = 4 + x = x + 4. Define calm road movie in Northwood Movie Festival as M; z = e + x = x + 4 + x = 2*x + 4; so M = z + o = 2*x + 4 + x = 3*x + 4. We know M = 16, so we have 3*x + 4 = 16 and we solve it through the following steps: Simplifying the equation: 3*x + 4 = 16. Move all terms to one side: 3*x - 12 = 0. Isolate the term with x: 3*x = 12. Divide both sides by 3: x = 12 / 3. Solution: x = 4. Answer: 4.", "op": 7, "id": "10_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of adult animals in Hamilton Farm equals 12. The number of adult deer in Hamilton Farm equals 2 plus the number of adult fox in Hamilton Farm. The number of adult racoon in Mayer Aquarium equals the number of adult fox in Jefferson Circus. The number of adult fox in Jefferson Circus equals 3. The number of adult fox in Hamilton Farm equals 4. The number of adult racoon in Jefferson Circus equals 4. The number of adult deer in Mayer Aquarium equals the number of adult fox in Hamilton Farm. The number of adult racoon in Hamilton Farm exists, and its number is greater than 0. The number of adult fox in Mayer Aquarium equals 3 plus the number of adult racoon in Jefferson Circus. The number of adult deer in Jefferson Circus equals the number of adult racoon in Hamilton Farm. ", "question": "How many adult racoon does Hamilton Farm have?", "solution": "The question is difficult, so we use equations to solve it. Define adult fox in Hamilton Farm as a; so a = 4. Define adult deer in Hamilton Farm as F; V = a = 4; so F = 2 + V = 2 + 4 = 6. Define adult racoon in Hamilton Farm as x; we don't know its value yet but will find it out later. Define total number of adult animals in Hamilton Farm as r; o = F + a = 6 + 4 = 10; so r = o + x = 10 + x = x + 10. We know r = 12, so we have x + 10 = 12 and we solve it through the following steps: Simplifying the equation: x + 10 = 12. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "8_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in Taylor Movie Festival exists, and its number is greater than 0. The number of intense detective thriller in Verdi Movie Festival equals 2. The number of upbeat metropolis comedy in Taylor Movie Festival equals 4. The total number of movies in Taylor Movie Festival equals 22. The number of solemn period drama in Verdi Movie Festival equals 3. The number of upbeat metropolis comedy in Verdi Movie Festival equals 3 plus the sum of the number of upbeat metropolis comedy in Taylor Movie Festival, the total number of movies in Taylor Movie Festival, and the number of intense detective thriller in Taylor Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 3 times the number of solemn period drama in Verdi Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 4 times the number of upbeat metropolis comedy in Taylor Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals 3 times the difference between the number of solemn period drama in Verdi Movie Festival and the number of solemn period drama in West Sahara Movie Festival. ", "question": "How many solemn period drama does Taylor Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in Taylor Movie Festival as M; so M = 4. Define intense detective thriller in Taylor Movie Festival as u; m = M = 4; so u = 4 * m = (4) * (4) = 16. Define solemn period drama in Taylor Movie Festival as x; we don't know its value yet but will find it out later. Define total number of movies in Taylor Movie Festival as s; Q = u + x = 16 + x = x + 16; so s = Q + M = x + 16 + 4 = x + 20. We know s = 22, so we have x + 20 = 22 and we solve it through the following steps: Simplifying the equation: x + 20 = 22. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "0_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of calm road movie in Cin\u00e9ma de Montreval equals 3. The number of calm road movie in Festival de Saint-Rivage equals 4. The number of intense detective thriller in R\u00eaves de Belleville equals the number of calm road movie in R\u00eaves de Belleville. The number of upbeat metropolis comedy in Festival de Clairmont equals the number of upbeat metropolis comedy in Cin\u00e9ma de Montreval. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 4. The number of futuristic sci-fi movie in Cin\u00e9ma de Montreval equals the total number of movies in Festival de Saint-Rivage. The number of intense detective thriller in Festival de Saint-Rivage equals 2. The number of upbeat metropolis comedy in Cin\u00e9ma de Montreval equals the number of calm road movie in Festival de Saint-Rivage. The number of intense detective thriller in Cin\u00e9ma de Montreval equals the number of upbeat metropolis comedy in Cin\u00e9ma de Montreval. The number of futuristic sci-fi movie in R\u00eaves de Belleville equals 2. The number of intense detective thriller in Festival de Clairmont equals 4 times the number of calm road movie in Festival de Saint-Rivage. The number of calm road movie in R\u00eaves de Belleville equals 2. The number of upbeat metropolis comedy in R\u00eaves de Belleville equals 2. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the number of futuristic sci-fi movie in R\u00eaves de Belleville. ", "question": "What is the total number of movies in Festival de Clairmont?", "solution": "Define calm road movie in Festival de Saint-Rivage as m; so m = 4. Define upbeat metropolis comedy in Cin\u00e9ma de Montreval as g; so g = m = 4. Define intense detective thriller in Festival de Clairmont as p; e = m = 4; so p = 4 * e = 4 * 4 = 16. Define upbeat metropolis comedy in Festival de Clairmont as q; so q = g = 4. Define total number of movies in Festival de Clairmont as K; so K = q + p = 4 + 16 = 20. Answer: 20.", "op": 7, "id": "22_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of public highschool in Hawkesbury equals the number of regional medical school in Hawkesbury. The number of culinarian school in Evervale City equals 1. The number of culinarian school in Hawkesbury equals the sum of the number of regional medical school in Hawkesbury and the number of public highschool in Hawkesbury. The number of culinarian school in Westhaven City equals 1 plus the sum of the total number of schools in Hawkesbury and the total number of schools in Evervale City. The number of regional medical school in Hawkesbury exists, and its number is greater than 0. The number of public highschool in Westhaven City equals 3. The number of regional medical school in Evervale City equals 1 plus the number of public highschool in Evervale City. The number of regional medical school in Westhaven City equals the number of regional medical school in Evervale City. The number of public highschool in Evervale City equals 2. The total number of schools in Hawkesbury equals 12. ", "question": "How many regional medical school does Hawkesbury have?", "solution": "The question is difficult, so we use equations to solve it. Define regional medical school in Hawkesbury as x; we don't know its value yet but will find it out later. Define public highschool in Hawkesbury as P; so P = x = x. Define culinarian school in Hawkesbury as o; so o = x + P = x + x = 2*x. Define total number of schools in Hawkesbury as c; j = o + x = 2*x + x = 3*x; so c = j + P = 3*x + x = 4*x. We know c = 12, so we have 4*x = 12 and we solve it through the following steps: Simplifying the equation: 4*x = 12. Move all terms to one side: 4*x - 12 = 0. Isolate the term with x: 4*x = 12. Divide both sides by 4: x = 12 / 4. Solution: x = 3. Answer: 3.", "op": 7, "id": "10_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of private middle school in Glenfield City equals 4. The number of public highschool in Glenfield City equals the number of private middle school in Brightford. The number of private middle school in Brightford equals the number of elementary school in Evervale City. The number of elementary school in Brightford equals 2. The number of elementary school in Evervale City equals the number of private middle school in Evervale City. The number of public highschool in Brightford equals the sum of the number of elementary school in Glenfield City, the number of public highschool in Glenfield City, and the number of private middle school in Glenfield City. The total number of schools in Evervale City equals 5. The number of private middle school in Evervale City exists, and its number is greater than 0. The number of elementary school in Glenfield City equals the number of private middle school in Glenfield City. The number of public highschool in Evervale City equals 2 plus the number of private middle school in Evervale City. ", "question": "How many private middle school does Evervale City have?", "solution": "The question is difficult, so we use equations to solve it. Define private middle school in Evervale City as x; we don't know its value yet but will find it out later. Define elementary school in Evervale City as M; so M = x = x. Define public highschool in Evervale City as T; n = x = x; so T = 2 + n = 2 + x = x + 2. Define total number of schools in Evervale City as u; R = x + M = x + x = 2*x; so u = R + T = 2*x + x + 2 = 3*x + 2. We know u = 5, so we have 3*x + 2 = 5 and we solve it through the following steps: Simplifying the equation: 3*x + 2 = 5. Move all terms to one side: 3*x - 3 = 0. Isolate the term with x: 3*x = 3. Divide both sides by 3: x = 3 / 3. Solution: x = 1. Answer: 1.", "op": 7, "id": "20_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult racoon in Beverly Forest equals 2 plus the number of adult wolf in Beverly Forest. The number of adult racoon in Cedar Valley equals 2 plus the number of adult wolf in Cedar Valley. The number of adult fox in Cedar Valley exists, and its number is greater than 0. The number of adult racoon in Maple Creek equals the sum of the number of adult racoon in Cedar Valley, the number of adult fox in Cedar Valley, the total number of adult animals in Cedar Valley, and the number of adult wolf in Cedar Valley. The total number of adult animals in Cedar Valley equals 12. The number of adult wolf in Maple Creek equals 2. The number of adult wolf in Cedar Valley equals 4. The number of adult fox in Beverly Forest equals the number of adult wolf in Maple Creek. The number of adult fox in Maple Creek equals the difference between the number of adult wolf in Beverly Forest and the number of adult racoon in Beverly Forest. The number of adult wolf in Beverly Forest equals 4. ", "question": "How many adult fox does Cedar Valley have?", "solution": "The question is difficult, so we use equations to solve it. Define adult wolf in Cedar Valley as E; so E = 4. Define adult racoon in Cedar Valley as j; C = E = 4; so j = 2 + C = 2 + 4 = 6. Define adult fox in Cedar Valley as x; we don't know its value yet but will find it out later. Define total number of adult animals in Cedar Valley as V; d = x + E = x + 4 = x + 4; so V = d + j = x + 4 + 6 = x + 10. We know V = 12, so we have x + 10 = 12 and we solve it through the following steps: Simplifying the equation: x + 10 = 12. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "19_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont equals 1. The number of futuristic sci-fi movie in Festival de Clairmont equals 4. The number of futuristic sci-fi movie in Cin\u00e9ma de Montreval equals 2 plus the number of calm road movie in Cin\u00e9ma de Montreval. The number of solemn period drama in Festival Lumi\u00e8re de Valmont equals 2 times the number of futuristic sci-fi movie in Festival de Clairmont. The number of calm road movie in Festival Lumi\u00e8re de Valmont equals 4. The number of calm road movie in Festival de Clairmont equals 1. The number of solemn period drama in Cin\u00e9ma de Montreval equals 4. The number of calm road movie in Cin\u00e9ma de Montreval exists, and its number is greater than 0. The number of solemn period drama in Festival de Clairmont equals 2. The total number of movies in Cin\u00e9ma de Montreval equals 14. ", "question": "How many calm road movie does Cin\u00e9ma de Montreval have?", "solution": "The question is difficult, so we use equations to solve it. Define solemn period drama in Cin\u00e9ma de Montreval as B; so B = 4. Define calm road movie in Cin\u00e9ma de Montreval as x; we don't know its value yet but will find it out later. Define futuristic sci-fi movie in Cin\u00e9ma de Montreval as K; a = x = x; so K = 2 + a = 2 + x = x + 2. Define total number of movies in Cin\u00e9ma de Montreval as H; E = B + K = 4 + x + 2 = x + 6; so H = E + x = x + 6 + x = 2*x + 6. We know H = 14, so we have 2*x + 6 = 14 and we solve it through the following steps: Simplifying the equation: 2*x + 6 = 14. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.", "op": 7, "id": "8_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult racoon in Maple Creek equals the sum of the number of adult fox in Cedar Valley, the number of adult bear in Pine Ridge, the number of adult racoon in Cedar Valley, and the total number of adult animals in Pine Ridge. The number of adult fox in Pine Ridge equals the number of adult bear in Pine Ridge. The number of adult racoon in Cedar Valley equals the number of adult fox in Cedar Valley. The number of adult fox in Cedar Valley exists, and its number is greater than 0. The number of adult racoon in Pine Ridge equals the number of adult bear in Pine Ridge. The number of adult bear in Maple Creek equals the number of adult racoon in Pine Ridge. The number of adult fox in Maple Creek equals 3 times the number of adult bear in Cedar Valley. The number of adult bear in Cedar Valley equals 1. The total number of adult animals in Pine Ridge equals 9. The number of adult bear in Pine Ridge equals the number of adult fox in Cedar Valley. ", "question": "How many adult fox does Cedar Valley have?", "solution": "The question is difficult, so we use equations to solve it. Define adult fox in Cedar Valley as x; we don't know its value yet but will find it out later. Define adult bear in Pine Ridge as p; so p = x = x. Define adult fox in Pine Ridge as q; so q = p = x. Define adult racoon in Pine Ridge as r; so r = p = x. Define total number of adult animals in Pine Ridge as n; U = q + r = x + x = 2*x; so n = U + p = 2*x + x = 3*x. We know n = 9, so we have 3*x = 9 and we solve it through the following steps: Simplifying the equation: 3*x = 9. Move all terms to one side: 3*x - 9 = 0. Isolate the term with x: 3*x = 9. Divide both sides by 3: x = 9 / 3. Solution: x = 3. Answer: 3.", "op": 7, "id": "14_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult deer in Bundle Ranch exists, and its number is greater than 0. The total number of adult animals in Mayer Aquarium equals 7. The number of adult fox in Bundle Ranch equals 2 times the number of adult deer in Bundle Ranch. The number of adult fox in Mayer Aquarium equals 1 plus the sum of the number of adult fox in Bundle Ranch and the number of adult deer in Bundle Ranch. The number of adult bear in South Zoo equals 4. ", "question": "How many adult deer does Bundle Ranch have?", "solution": "The question is difficult, so we use equations to solve it. Define adult deer in Bundle Ranch as x; we don't know its value yet but will find it out later. Define adult fox in Bundle Ranch as f; h = x = x; so f = 2 * h = (2) * (x) = 2*x. Define adult fox in Mayer Aquarium as y; H = f + x = 2*x + x = 3*x; so y = 1 + H = 1 + 3*x = 3*x + 1. Define total number of adult animals in Mayer Aquarium as V; so V = y = 3*x + 1. We know V = 7, so we have 3*x + 1 = 7 and we solve it through the following steps: Simplifying the equation: 3*x + 1 = 7. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.", "op": 7, "id": "6_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of intense detective thriller in Cin\u00e9ma de Montreval equals the number of futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont. The number of upbeat metropolis comedy in Cin\u00e9ma de Montreval equals 3 times the number of upbeat metropolis comedy in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Cin\u00e9ma de Montreval equals 2. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 3. The number of intense detective thriller in Festival Lumi\u00e8re de Valmont equals the number of intense detective thriller in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 2. The number of upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont equals 2. The number of intense detective thriller in Festival de Saint-Rivage equals 3. The total number of movies in Festival Lumi\u00e8re de Valmont equals 7. The number of futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont exists, and its number is greater than 0. ", "question": "How many futuristic sci-fi movie does Festival Lumi\u00e8re de Valmont have?", "solution": "The question is difficult, so we use equations to solve it. Define intense detective thriller in Festival de Saint-Rivage as J; so J = 3. Define intense detective thriller in Festival Lumi\u00e8re de Valmont as B; so B = J = 3. Define upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont as s; so s = 2. Define futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont as x; we don't know its value yet but will find it out later. Define total number of movies in Festival Lumi\u00e8re de Valmont as l; T = s + B = 2 + 3 = 5; so l = T + x = 5 + x = x + 5. We know l = 7, so we have x + 5 = 7 and we solve it through the following steps: Simplifying the equation: x + 5 = 7. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "22_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of public highschool in Westhaven City equals the number of public highschool in Evervale City. The total number of schools in Evervale City equals 7. The number of culinarian school in Westhaven City equals 2 times the number of culinarian school in Hawkesbury. The number of culinarian school in Hawkesbury equals 3. The number of culinarian school in Evervale City exists, and its number is greater than 0. The number of public highschool in Evervale City equals 2. The number of private middle school in Hawkesbury equals 3. The number of private middle school in Westhaven City equals the sum of the number of private middle school in Evervale City, the number of culinarian school in Hawkesbury, the total number of schools in Hawkesbury, and the total number of schools in Evervale City. The number of public highschool in Hawkesbury equals 3. The number of private middle school in Evervale City equals 4 times the number of culinarian school in Evervale City. ", "question": "How many culinarian school does Evervale City have?", "solution": "The question is difficult, so we use equations to solve it. Define public highschool in Evervale City as e; so e = 2. Define culinarian school in Evervale City as x; we don't know its value yet but will find it out later. Define private middle school in Evervale City as B; a = x = x; so B = 4 * a = (4) * (x) = 4*x. Define total number of schools in Evervale City as Q; t = e + B = 2 + 4*x = 4*x + 2; so Q = t + x = 4*x + 2 + x = 5*x + 2. We know Q = 7, so we have 5*x + 2 = 7 and we solve it through the following steps: Simplifying the equation: 5*x + 2 = 7. Move all terms to one side: 5*x - 5 = 0. Isolate the term with x: 5*x = 5. Divide both sides by 5: x = 5 / 5. Solution: x = 1. Answer: 1.", "op": 7, "id": "16_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in West Sahara Movie Festival exists, and its number is greater than 0. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the number of calm road movie in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 2 plus the number of solemn period drama in West Sahara Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 1. The number of calm road movie in West Sahara Movie Festival equals 2. The number of upbeat metropolis comedy in Taylor Movie Festival equals the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of solemn period drama in Taylor Movie Festival equals the number of solemn period drama in West Sahara Movie Festival. The total number of movies in Taylor Movie Festival equals 8. ", "question": "How many solemn period drama does West Sahara Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define solemn period drama in West Sahara Movie Festival as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in Golden Banana Movie Festival as d; T = x = x; so d = 2 + T = 2 + x = x + 2. Define solemn period drama in Taylor Movie Festival as t; so t = x = x. Define upbeat metropolis comedy in Taylor Movie Festival as G; so G = d = x + 2. Define total number of movies in Taylor Movie Festival as a; so a = t + G = x + x + 2 = 2*x + 2. We know a = 8, so we have 2*x + 2 = 8 and we solve it through the following steps: Simplifying the equation: 2*x + 2 = 8. Move all terms to one side: 2*x - 6 = 0. Isolate the term with x: 2*x = 6. Divide both sides by 2: x = 6 / 2. Solution: x = 3. Answer: 3.", "op": 7, "id": "19_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of regional medical school in Evervale City equals 3. The number of private middle school in Brightford exists, and its number is greater than 0. The total number of schools in Brightford equals 9. The number of private middle school in Evervale City equals 4 times the number of regional medical school in Evervale City. The number of public highschool in Hawkesbury equals 4. The number of public highschool in Brightford equals the number of public highschool in Hawkesbury. The number of regional medical school in Brightford equals the number of public highschool in Brightford. The number of private middle school in Hawkesbury equals the number of private middle school in Brightford. The number of public highschool in Evervale City equals 4. The number of private middle school in Brightford exists, and its number is greater than 0. ", "question": "How many private middle school does Brightford have?", "solution": "The question is difficult, so we use equations to solve it. Define public highschool in Hawkesbury as r; so r = 4. Define public highschool in Brightford as u; so u = r = 4. Define regional medical school in Brightford as t; so t = u = 4. Define private middle school in Brightford as x; we don't know its value yet but will find it out later. Define total number of schools in Brightford as a; v = t + x = 4 + x = x + 4; so a = v + u = x + 4 + 4 = x + 8. We know a = 9, so we have x + 8 = 9 and we solve it through the following steps: Simplifying the equation: x + 8 = 9. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1.", "op": 7, "id": "8_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of movies in Northwood Movie Festival equals 13. The number of solemn period drama in Taylor Movie Festival equals 2. The number of intense detective thriller in Northwood Movie Festival equals 3. The number of intense detective thriller in West Sahara Movie Festival equals 2. The number of calm road movie in Taylor Movie Festival equals 2. The number of calm road movie in Northwood Movie Festival equals 3 times the number of intense detective thriller in Northwood Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals the difference between the total number of movies in Northwood Movie Festival and the number of intense detective thriller in West Sahara Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 3. The number of intense detective thriller in Taylor Movie Festival equals the number of intense detective thriller in West Sahara Movie Festival. The number of solemn period drama in Northwood Movie Festival exists, and its number is greater than 0. ", "question": "How many solemn period drama does Northwood Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define intense detective thriller in Northwood Movie Festival as P; so P = 3. Define solemn period drama in Northwood Movie Festival as x; we don't know its value yet but will find it out later. Define calm road movie in Northwood Movie Festival as V; u = P = 3; so V = 3 * u = (3) * (3) = 9. Define total number of movies in Northwood Movie Festival as k; N = V + x = 9 + x = x + 9; so k = N + P = x + 9 + 3 = x + 12. We know k = 13, so we have x + 12 = 13 and we solve it through the following steps: Simplifying the equation: x + 12 = 13. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1.", "op": 7, "id": "1_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of adult animals in Bundle Ranch equals 7. The number of adult owl in Hamilton Farm exists, and its number is greater than 0. The number of adult owl in Bundle Ranch equals the total number of adult animals in Hamilton Farm. The number of adult parrot in Bundle Ranch equals 3 plus the total number of adult animals in Hamilton Farm. ", "question": "How many adult owl does Hamilton Farm have?", "solution": "The question is difficult, so we use equations to solve it. Define adult owl in Hamilton Farm as x; we don't know its value yet but will find it out later. Define total number of adult animals in Hamilton Farm as v; so v = x = x. Define adult parrot in Bundle Ranch as J; Q = v = x; so J = 3 + Q = 3 + x = x + 3. Define adult owl in Bundle Ranch as k; so k = v = x. Define total number of adult animals in Bundle Ranch as V; so V = J + k = x + 3 + x = 2*x + 3. We know V = 7, so we have 2*x + 3 = 7 and we solve it through the following steps: Simplifying the equation: 2*x + 3 = 7. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.", "op": 7, "id": "8_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult fox in Jefferson Circus equals 1. The number of adult fox in Bundle Ranch equals the number of adult wolf in Hamilton Farm. The number of adult wolf in Bundle Ranch equals 2 plus the total number of adult animals in Jefferson Circus. The number of adult deer in Jefferson Circus exists, and its number is greater than 0. The number of adult fox in Hamilton Farm equals the number of adult deer in Jefferson Circus. The number of adult wolf in Hamilton Farm equals the number of adult deer in Hamilton Farm. The number of adult deer in Hamilton Farm equals the number of adult deer in Jefferson Circus. The number of adult wolf in Jefferson Circus equals 3. The total number of adult animals in Hamilton Farm equals 12. The number of adult deer in Bundle Ranch equals the total number of adult animals in Jefferson Circus. ", "question": "How many adult deer does Jefferson Circus have?", "solution": "The question is difficult, so we use equations to solve it. Define adult deer in Jefferson Circus as x; we don't know its value yet but will find it out later. Define adult deer in Hamilton Farm as P; so P = x = x. Define adult wolf in Hamilton Farm as j; so j = P = x. Define adult fox in Hamilton Farm as Y; so Y = x = x. Define total number of adult animals in Hamilton Farm as Q; H = Y + j = x + x = 2*x; so Q = H + P = 2*x + x = 3*x. We know Q = 12, so we have 3*x = 12 and we solve it through the following steps: Simplifying the equation: 3*x = 12. Move all terms to one side: 3*x - 12 = 0. Isolate the term with x: 3*x = 12. Divide both sides by 3: x = 12 / 3. Solution: x = 4. Answer: 4.", "op": 7, "id": "10_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult owl in Hamilton Farm equals 1 plus the number of adult owl in Jefferson Circus. The total number of adult animals in Hamilton Farm equals 6. The number of adult parrot in Hamilton Farm equals 3 plus the number of adult owl in Jefferson Circus. The number of adult owl in Jefferson Circus exists, and its number is greater than 0. The number of adult parrot in Jefferson Circus equals 3. ", "question": "How many adult owl does Jefferson Circus have?", "solution": "The question is difficult, so we use equations to solve it. Define adult owl in Jefferson Circus as x; we don't know its value yet but will find it out later. Define adult parrot in Hamilton Farm as G; y = x = x; so G = 3 + y = 3 + x = x + 3. Define adult owl in Hamilton Farm as C; w = x = x; so C = 1 + w = 1 + x = x + 1. Define total number of adult animals in Hamilton Farm as W; so W = G + C = x + 3 + x + 1 = 2*x + 4. We know W = 6, so we have 2*x + 4 = 6 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 6. Move all terms to one side: 2*x - 2 = 0. Isolate the term with x: 2*x = 2. Divide both sides by 2: x = 2 / 2. Solution: x = 1. Answer: 1.", "op": 7, "id": "2_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of culinarian school in Brightford equals 4 times the difference between the total number of schools in Westhaven City and the number of public highschool in Brightford. The total number of schools in Westhaven City equals 6. The number of public highschool in Westhaven City equals 4 times the number of public highschool in Brightford. The number of public highschool in Brightford exists, and its number is greater than 0. The number of culinarian school in Westhaven City equals 1 plus the number of public highschool in Brightford. ", "question": "How many public highschool does Brightford have?", "solution": "The question is difficult, so we use equations to solve it. Define public highschool in Brightford as x; we don't know its value yet but will find it out later. Define culinarian school in Westhaven City as O; W = x = x; so O = 1 + W = 1 + x = x + 1. Define public highschool in Westhaven City as J; h = x = x; so J = 4 * h = (4) * (x) = 4*x. Define total number of schools in Westhaven City as Y; so Y = O + J = x + 1 + 4*x = 5*x + 1. We know Y = 6, so we have 5*x + 1 = 6 and we solve it through the following steps: Simplifying the equation: 5*x + 1 = 6. Move all terms to one side: 5*x - 5 = 0. Isolate the term with x: 5*x = 5. Divide both sides by 5: x = 5 / 5. Solution: x = 1. Answer: 1.", "op": 7, "id": "11_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of adult animals in Jefferson Circus equals 8. The number of adult blue jay in Mayer Aquarium equals 4 plus the total number of adult animals in Hamilton Farm. The number of adult blue jay in Hamilton Farm exists, and its number is greater than 0. The number of adult blue jay in Jefferson Circus equals the total number of adult animals in Mayer Aquarium. ", "question": "How many adult blue jay does Hamilton Farm have?", "solution": "The question is difficult, so we use equations to solve it. Define adult blue jay in Hamilton Farm as x; we don't know its value yet but will find it out later. Define total number of adult animals in Hamilton Farm as D; so D = x = x. Define adult blue jay in Mayer Aquarium as H; W = D = x; so H = 4 + W = 4 + x = x + 4. Define total number of adult animals in Mayer Aquarium as w; so w = H = x + 4. Define adult blue jay in Jefferson Circus as P; so P = w = x + 4. Define total number of adult animals in Jefferson Circus as v; so v = P = x + 4. We know v = 8, so we have x + 4 = 8 and we solve it through the following steps: Simplifying the equation: x + 4 = 8. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.", "op": 7, "id": "15_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of movies in West Sahara Movie Festival equals 10. The number of solemn period drama in West Sahara Movie Festival equals 3 times the number of upbeat metropolis comedy in West Sahara Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals the number of solemn period drama in Verdi Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 4. The number of upbeat metropolis comedy in West Sahara Movie Festival exists, and its number is greater than 0. The number of upbeat metropolis comedy in West Sahara Movie Festival exists, and its number is greater than 0. The number of solemn period drama in Northwood Movie Festival equals 1 plus the number of upbeat metropolis comedy in West Sahara Movie Festival. The number of calm road movie in Verdi Movie Festival equals 4. The number of solemn period drama in Verdi Movie Festival equals 3. The number of calm road movie in West Sahara Movie Festival equals the number of upbeat metropolis comedy in West Sahara Movie Festival. ", "question": "How many upbeat metropolis comedy does West Sahara Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in West Sahara Movie Festival as x; we don't know its value yet but will find it out later. Define solemn period drama in West Sahara Movie Festival as C; Q = x = x; so C = 3 * Q = (3) * (x) = 3*x. Define calm road movie in West Sahara Movie Festival as R; so R = x = x. Define total number of movies in West Sahara Movie Festival as u; e = x + R = x + x = 2*x; so u = e + C = 2*x + 3*x = 5*x. We know u = 10, so we have 5*x = 10 and we solve it through the following steps: Simplifying the equation: 5*x = 10. Move all terms to one side: 5*x - 10 = 0. Isolate the term with x: 5*x = 10. Divide both sides by 5: x = 10 / 5. Solution: x = 2. Answer: 2.", "op": 7, "id": "10_p5", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of culinarian school in Glenfield City equals the number of private middle school in Westhaven City. The number of private middle school in Brightford equals 4 times the number of culinarian school in Brightford. The number of regional medical school in Westhaven City equals 2 plus the number of culinarian school in Brightford. The number of private middle school in Westhaven City equals 2. The number of culinarian school in Brightford equals 2. The number of private middle school in Glenfield City equals the number of private middle school in Brightford. The number of regional medical school in Brightford equals the number of culinarian school in Brightford. ", "question": "What is the total number of schools in Brightford?", "solution": "Define culinarian school in Brightford as C; so C = 2. Define regional medical school in Brightford as e; so e = C = 2. Define private middle school in Brightford as D; F = C = 2; so D = 4 * F = 4 * 2 = 8. Define total number of schools in Brightford as Y; K = D + C = 8 + 2 = 10; so Y = K + e = 10 + 2 = 12. Answer: 12.", "op": 7, "id": "18_p5", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult blue jay in South Zoo equals 2 times the number of adult eagle in South Zoo. The number of adult crow in Mayer Aquarium equals 4. The number of adult eagle in South Zoo equals 2. The total number of adult animals in Mayer Aquarium equals 18. The number of adult blue jay in Mayer Aquarium exists, and its number is greater than 0. The number of adult crow in South Zoo equals 2 plus the difference between the number of adult eagle in South Zoo and the number of adult blue jay in South Zoo. The number of adult crow in Bundle Ranch equals the sum of the number of adult eagle in Mayer Aquarium, the total number of adult animals in South Zoo, and the number of adult blue jay in Bundle Ranch. The number of adult blue jay in Bundle Ranch equals the sum of the number of adult eagle in South Zoo, the number of adult crow in South Zoo, and the number of adult blue jay in South Zoo. The number of adult eagle in Mayer Aquarium equals 3 times the number of adult crow in Mayer Aquarium. The number of adult eagle in Bundle Ranch equals 2 plus the total number of adult animals in South Zoo. ", "question": "How many adult blue jay does Mayer Aquarium have?", "solution": "The question is difficult, so we use equations to solve it. Define adult crow in Mayer Aquarium as H; so H = 4. Define adult eagle in Mayer Aquarium as z; b = H = 4; so z = 3 * b = (3) * (4) = 12. Define adult blue jay in Mayer Aquarium as x; we don't know its value yet but will find it out later. Define total number of adult animals in Mayer Aquarium as w; K = z + x = 12 + x = x + 12; so w = K + H = x + 12 + 4 = x + 16. We know w = 18, so we have x + 16 = 18 and we solve it through the following steps: Simplifying the equation: x + 16 = 18. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 7, "id": "15_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult fox in Cedar Valley equals the sum of the number of adult deer in Cedar Valley and the number of adult racoon in Pine Ridge. The number of adult deer in Pine Ridge equals 2 times the number of adult deer in Cedar Valley. The number of adult racoon in Pine Ridge equals 4 times the number of adult deer in Pine Ridge. The number of adult deer in Cedar Valley equals 2. The number of adult racoon in Cedar Valley equals the difference between the number of adult deer in Cedar Valley and the number of adult deer in Pine Ridge. The number of adult fox in Maple Creek equals the number of adult deer in Maple Creek. The number of adult deer in Maple Creek exists, and its number is greater than 0. The number of adult racoon in Maple Creek equals 3 plus the number of adult deer in Maple Creek. The number of adult fox in Pine Ridge equals 2. The total number of adult animals in Maple Creek equals 15. ", "question": "How many adult deer does Maple Creek have?", "solution": "The question is difficult, so we use equations to solve it. Define adult deer in Maple Creek as x; we don't know its value yet but will find it out later. Define adult racoon in Maple Creek as y; d = x = x; so y = 3 + d = 3 + x = x + 3. Define adult fox in Maple Creek as B; so B = x = x. Define total number of adult animals in Maple Creek as w; u = B + x = x + x = 2*x; so w = u + y = 2*x + x + 3 = 3*x + 3. We know w = 15, so we have 3*x + 3 = 15 and we solve it through the following steps: Simplifying the equation: 3*x + 3 = 15. Move all terms to one side: 3*x - 12 = 0. Isolate the term with x: 3*x = 12. Divide both sides by 3: x = 12 / 3. Solution: x = 4. Answer: 4.", "op": 7, "id": "20_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The total number of schools in Brightford equals 20. The number of public highschool in Brightford equals the number of regional medical school in Brightford. The number of regional medical school in Westhaven City equals 2. The number of public highschool in Hawkesbury equals 4 times the number of regional medical school in Westhaven City. The number of private middle school in Brightford equals 3 times the number of public highschool in Brightford. The number of regional medical school in Brightford exists, and its number is greater than 0. ", "question": "How many regional medical school does Brightford have?", "solution": "The question is difficult, so we use equations to solve it. Define regional medical school in Brightford as x; we don't know its value yet but will find it out later. Define public highschool in Brightford as M; so M = x = x. Define private middle school in Brightford as j; D = M = x; so j = 3 * D = (3) * (x) = 3*x. Define total number of schools in Brightford as w; L = M + x = x + x = 2*x; so w = L + j = 2*x + 3*x = 5*x. We know w = 20, so we have 5*x = 20 and we solve it through the following steps: Simplifying the equation: 5*x = 20. Move all terms to one side: 5*x - 20 = 0. Isolate the term with x: 5*x = 20. Divide both sides by 5: x = 20 / 5. Solution: x = 4. Answer: 4.", "op": 7, "id": "20_p5", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult parrot in Mayer Aquarium equals 4 plus the total number of adult animals in Jefferson Circus. The total number of adult animals in Mayer Aquarium equals 8. The number of adult owl in Mayer Aquarium equals the number of adult parrot in Jefferson Circus. The number of adult parrot in Jefferson Circus exists, and its number is greater than 0. ", "question": "How many adult parrot does Jefferson Circus have?", "solution": "The question is difficult, so we use equations to solve it. Define adult parrot in Jefferson Circus as x; we don't know its value yet but will find it out later. Define total number of adult animals in Jefferson Circus as B; so B = x = x. Define adult parrot in Mayer Aquarium as Z; J = B = x; so Z = 4 + J = 4 + x = x + 4. Define adult owl in Mayer Aquarium as F; so F = x = x. Define total number of adult animals in Mayer Aquarium as T; so T = Z + F = x + 4 + x = 2*x + 4. We know T = 8, so we have 2*x + 4 = 8 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 8. Move all terms to one side: 2*x - 4 = 0. Isolate the term with x: 2*x = 4. Divide both sides by 2: x = 4 / 2. Solution: x = 2. Answer: 2.", "op": 7, "id": "15_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult fox in Cedar Valley equals 2. The number of adult fox in Beverly Forest equals 4 times the number of adult bear in Cedar Valley. The number of adult bear in Cedar Valley equals the sum of the number of adult wolf in Cedar Valley and the number of adult fox in Cedar Valley. The total number of adult animals in Cedar Valley equals 12. The number of adult bear in Pine Ridge equals 2. The number of adult wolf in Beverly Forest equals 3. The number of adult fox in Pine Ridge equals the number of adult bear in Pine Ridge. The number of adult wolf in Cedar Valley exists, and its number is greater than 0. The number of adult wolf in Pine Ridge equals 3 plus the number of adult bear in Pine Ridge. The number of adult bear in Beverly Forest equals the sum of the number of adult wolf in Pine Ridge, the number of adult bear in Pine Ridge, the total number of adult animals in Beverly Forest, and the number of adult fox in Cedar Valley. ", "question": "How many adult wolf does Cedar Valley have?", "solution": "The question is difficult, so we use equations to solve it. Define adult fox in Cedar Valley as t; so t = 2. Define adult wolf in Cedar Valley as x; we don't know its value yet but will find it out later. Define adult bear in Cedar Valley as s; so s = x + t = x + 2 = x + 2. Define total number of adult animals in Cedar Valley as b; r = s + t = x + 2 + 2 = x + 4; so b = r + x = x + 4 + x = 2*x + 4. We know b = 12, so we have 2*x + 4 = 12 and we solve it through the following steps: Simplifying the equation: 2*x + 4 = 12. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.", "op": 7, "id": "15_p5", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult wolf in Jefferson Circus equals the number of adult fox in Jefferson Circus. The number of adult fox in Jefferson Circus equals 3. The number of adult wolf in Hamilton Farm equals 1 plus the sum of the number of adult fox in Jefferson Circus, the total number of adult animals in Jefferson Circus, and the number of adult fox in Bundle Ranch. The number of adult fox in Hamilton Farm equals the total number of adult animals in Jefferson Circus. The number of adult wolf in Bundle Ranch equals 4. The number of adult deer in Bundle Ranch equals the number of adult wolf in Bundle Ranch. The number of adult fox in Bundle Ranch equals 1. The number of adult deer in Jefferson Circus equals the number of adult fox in Bundle Ranch. The number of adult deer in Hamilton Farm equals the number of adult deer in Bundle Ranch. ", "question": "What is the total number of adult animals in Jefferson Circus?", "solution": "Define adult fox in Bundle Ranch as q; so q = 1. Define adult deer in Jefferson Circus as O; so O = q = 1. Define adult fox in Jefferson Circus as z; so z = 3. Define adult wolf in Jefferson Circus as e; so e = z = 3. Define total number of adult animals in Jefferson Circus as P; D = O + e = 1 + 3 = 4; so P = D + z = 4 + 3 = 7. Answer: 7.", "op": 7, "id": "8_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of futuristic sci-fi movie in Golden Banana Movie Festival equals the number of upbeat metropolis comedy in West Sahara Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 2 times the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the sum of the total number of movies in Verdi Movie Festival, the number of futuristic sci-fi movie in Verdi Movie Festival, the number of solemn period drama in Northwood Movie Festival, and the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of calm road movie in Northwood Movie Festival equals 2. The number of futuristic sci-fi movie in Verdi Movie Festival equals the number of solemn period drama in Northwood Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 1. The number of calm road movie in Taylor Movie Festival equals 4. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 2. ", "question": "What is the total number of movies in Verdi Movie Festival?", "solution": "Define upbeat metropolis comedy in Golden Banana Movie Festival as m; so m = 2. Define solemn period drama in Northwood Movie Festival as b; z = m = 2; so b = 2 * z = 2 * 2 = 4. Define intense detective thriller in Verdi Movie Festival as q; so q = 1. Define futuristic sci-fi movie in Verdi Movie Festival as Y; so Y = b = 4. Define total number of movies in Verdi Movie Festival as w; so w = q + Y = 1 + 4 = 5. Answer: 5.", "op": 7, "id": "17_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of culinarian school in Evervale City equals the number of regional medical school in Evervale City. The number of elementary school in Evervale City equals the total number of schools in Brightford. The number of regional medical school in Evervale City equals 4. The number of elementary school in Hawkesbury equals 1 plus the total number of schools in Brightford. The number of regional medical school in Hawkesbury equals 2. The number of elementary school in Brightford equals 3. ", "question": "What is the total number of schools in Hawkesbury?", "solution": "Define elementary school in Brightford as H; so H = 3. Define total number of schools in Brightford as c; so c = H = 3. Define elementary school in Hawkesbury as h; O = c = 3; so h = 1 + O = 1 + 3 = 4. Define regional medical school in Hawkesbury as K; so K = 2. Define total number of schools in Hawkesbury as W; so W = K + h = 2 + 4 = 6. Answer: 6.", "op": 7, "id": "10_p5", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of private middle school in Riverton City equals 4 times the total number of schools in Oakbridge City. The number of private middle school in Oakbridge City equals 2. The number of public highschool in Oakbridge City equals the number of private middle school in Oakbridge City. ", "question": "What is the total number of schools in Riverton City?", "solution": "Define private middle school in Oakbridge City as P; so P = 2. Define public highschool in Oakbridge City as b; so b = P = 2. Define total number of schools in Oakbridge City as p; so p = P + b = 2 + 2 = 4. Define private middle school in Riverton City as f; c = p = 4; so f = 4 * c = 4 * 4 = 16. Define total number of schools in Riverton City as B; so B = f = 16. Answer: 16.", "op": 7, "id": "1_p5", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of calm road movie in Festival de Clairmont equals 2. The number of solemn period drama in Festival de Clairmont equals 2. The number of upbeat metropolis comedy in Cin\u00e9ma de Montreval equals 2. The number of solemn period drama in Cin\u00e9ma de Montreval equals the sum of the total number of movies in Festival de Clairmont, the total number of movies in Cin\u00e9ma de Montreval, the number of calm road movie in Cin\u00e9ma de Montreval, and the number of calm road movie in Festival de Clairmont. The number of solemn period drama in Festival de Saint-Rivage equals the number of calm road movie in Festival Lumi\u00e8re de Valmont. The number of calm road movie in Festival de Saint-Rivage equals the number of calm road movie in Cin\u00e9ma de Montreval. The number of upbeat metropolis comedy in Festival de Clairmont equals 4. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 3. The number of calm road movie in Cin\u00e9ma de Montreval equals the sum of the number of calm road movie in Festival de Clairmont, the number of solemn period drama in Festival de Clairmont, and the number of upbeat metropolis comedy in Festival de Clairmont. The number of upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont equals 2 times the sum of the number of calm road movie in Festival Lumi\u00e8re de Valmont and the number of solemn period drama in Festival de Saint-Rivage. The number of calm road movie in Festival Lumi\u00e8re de Valmont equals 3. The number of solemn period drama in Festival Lumi\u00e8re de Valmont equals the total number of movies in Festival de Clairmont. ", "question": "How many solemn period drama does Festival Lumi\u00e8re de Valmont have?", "solution": "Define solemn period drama in Festival de Clairmont as Q; so Q = 2. Define upbeat metropolis comedy in Festival de Clairmont as U; so U = 4. Define calm road movie in Festival de Clairmont as g; so g = 2. Define total number of movies in Festival de Clairmont as v; C = U + g = 4 + 2 = 6; so v = C + Q = 6 + 2 = 8. Define solemn period drama in Festival Lumi\u00e8re de Valmont as H; so H = v = 8. Answer: 8.", "op": 7, "id": "15_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult bear in Jefferson Circus equals 2 times the total number of adult animals in Bundle Ranch. The number of adult racoon in Mayer Aquarium equals the number of adult deer in Mayer Aquarium. The number of adult deer in Mayer Aquarium equals 3. The number of adult racoon in Bundle Ranch equals the sum of the number of adult deer in South Zoo and the total number of adult animals in Hamilton Farm. The number of adult deer in Bundle Ranch equals 1. The number of adult deer in South Zoo equals 2. The number of adult bear in South Zoo equals 3 plus the number of adult deer in Bundle Ranch. The number of adult fox in Mayer Aquarium equals the sum of the number of adult racoon in Mayer Aquarium and the number of adult deer in Mayer Aquarium. The number of adult racoon in Hamilton Farm equals 3. The number of adult wolf in Bundle Ranch equals the number of adult deer in Bundle Ranch. The number of adult fox in Hamilton Farm equals 3. The number of adult bear in Bundle Ranch equals 4 times the sum of the number of adult racoon in Mayer Aquarium, the total number of adult animals in Mayer Aquarium, and the number of adult deer in Bundle Ranch. ", "question": "What is the total number of adult animals in Mayer Aquarium?", "solution": "Define adult deer in Mayer Aquarium as n; so n = 3. Define adult racoon in Mayer Aquarium as r; so r = n = 3. Define adult fox in Mayer Aquarium as G; so G = r + n = 3 + 3 = 6. Define total number of adult animals in Mayer Aquarium as O; L = n + r = 3 + 3 = 6; so O = L + G = 6 + 6 = 12. Answer: 12.", "op": 7, "id": "0_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The total number of schools in Clearwater Bay equals 24. The number of culinarian school in Shoreline City equals the number of private middle school in Shoreline City. The number of private middle school in Clearwater Bay equals 4 times the total number of schools in Shoreline City. The number of private middle school in Shoreline City exists, and its number is greater than 0. ", "question": "How many private middle school does Shoreline City have?", "solution": "The question is difficult, so we use equations to solve it. Define private middle school in Shoreline City as x; we don't know its value yet but will find it out later. Define culinarian school in Shoreline City as k; so k = x = x. Define total number of schools in Shoreline City as w; so w = k + x = x + x = 2*x. Define private middle school in Clearwater Bay as E; U = w = 2*x; so E = 4 * U = (4) * (2*x) = 8*x. Define total number of schools in Clearwater Bay as Q; so Q = E = 8*x. We know Q = 24, so we have 8*x = 24 and we solve it through the following steps: Simplifying the equation: 8*x = 24. Move all terms to one side: 8*x - 24 = 0. Isolate the term with x: 8*x = 24. Divide both sides by 8: x = 24 / 8. Solution: x = 3. Answer: 3.", "op": 7, "id": "18_p2", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
{"problem": "The number of adult fox in Mayer Aquarium equals the sum of the number of adult fox in Hamilton Farm, the number of adult bear in Mayer Aquarium, and the number of adult deer in Mayer Aquarium. The number of adult bear in Mayer Aquarium equals 1 plus the number of adult deer in Mayer Aquarium. The number of adult deer in Jefferson Circus equals 1. The number of adult fox in Hamilton Farm equals the number of adult bear in Mayer Aquarium. The number of adult fox in Jefferson Circus equals the sum of the number of adult deer in Jefferson Circus, the number of adult bear in Mayer Aquarium, the total number of adult animals in Hamilton Farm, and the number of adult fox in Hamilton Farm. The number of adult bear in Hamilton Farm equals 2. The number of adult deer in Hamilton Farm equals 2. The number of adult bear in Jefferson Circus equals 2. The number of adult deer in Mayer Aquarium equals 3. ", "question": "How many adult fox does Mayer Aquarium have?", "solution": "Define adult deer in Mayer Aquarium as u; so u = 3. Define adult bear in Mayer Aquarium as X; q = u = 3; so X = 1 + q = 1 + 3 = 4. Define adult fox in Hamilton Farm as c; so c = X = 4. Define adult fox in Mayer Aquarium as l; L = c + X = 4 + 4 = 8; so l = L + u = 8 + 3 = 11. Answer: 11.", "op": 7, "id": "12_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of culinarian school in Shoreline City equals 2. The number of culinarian school in Ruby Bay equals 2. The number of private middle school in Shoreline City equals 2 times the number of elementary school in Shoreline City. The number of regional medical school in Oakbridge City equals the sum of the number of culinarian school in Ruby Bay, the number of private middle school in Ruby Bay, and the number of elementary school in Clearwater Bay. The number of regional medical school in Clearwater Bay equals 2. The number of private middle school in Clearwater Bay equals 4 plus the sum of the number of elementary school in Clearwater Bay, the number of private middle school in Ruby Bay, and the total number of schools in Shoreline City. The number of private middle school in Oakbridge City equals 2 plus the sum of the number of culinarian school in Ruby Bay, the number of elementary school in Clearwater Bay, and the number of culinarian school in Shoreline City. The number of culinarian school in Oakbridge City equals the sum of the number of elementary school in Shoreline City, the number of private middle school in Shoreline City, and the number of regional medical school in Clearwater Bay. The number of regional medical school in Ruby Bay equals the number of private middle school in Shoreline City. The number of elementary school in Shoreline City equals 4. The number of private middle school in Ruby Bay equals 4 times the number of culinarian school in Ruby Bay. The number of elementary school in Clearwater Bay equals 3 times the sum of the number of culinarian school in Ruby Bay and the number of private middle school in Ruby Bay. ", "question": "What is the total number of schools in Shoreline City?", "solution": "Define elementary school in Shoreline City as N; so N = 4. Define private middle school in Shoreline City as A; u = N = 4; so A = 2 * u = 2 * 4 = 8. Define culinarian school in Shoreline City as n; so n = 2. Define total number of schools in Shoreline City as z; v = A + n = 8 + 2 = 10; so z = v + N = 10 + 4 = 14. Answer: 14.", "op": 7, "id": "19_p5", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult crow in Jefferson Circus equals 1. The number of adult eagle in Bundle Ranch equals 4 times the sum of the total number of adult animals in South Zoo, the number of adult parrot in Jefferson Circus, and the number of adult crow in Jefferson Circus. The number of adult crow in Bundle Ranch equals the number of adult eagle in South Zoo. The number of adult parrot in Jefferson Circus equals 3 plus the number of adult eagle in Jefferson Circus. The number of adult parrot in Bundle Ranch equals 2. The number of adult eagle in South Zoo equals the sum of the total number of adult animals in Jefferson Circus, the number of adult eagle in Jefferson Circus, the number of adult parrot in Jefferson Circus, and the number of adult crow in Jefferson Circus. The number of adult eagle in Jefferson Circus equals the number of adult crow in Jefferson Circus. ", "question": "What is the total number of adult animals in Jefferson Circus?", "solution": "Define adult crow in Jefferson Circus as G; so G = 1. Define adult eagle in Jefferson Circus as x; so x = G = 1. Define adult parrot in Jefferson Circus as M; L = x = 1; so M = 3 + L = 3 + 1 = 4. Define total number of adult animals in Jefferson Circus as Q; p = x + G = 1 + 1 = 2; so Q = p + M = 2 + 4 = 6. Answer: 6.", "op": 7, "id": "21_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the number of upbeat metropolis comedy in Festival de Clairmont. The number of upbeat metropolis comedy in Festival de Clairmont equals 4 plus the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Cin\u00e9ma de Montreval equals 4. The number of futuristic sci-fi movie in Cin\u00e9ma de Montreval equals 1 plus the number of upbeat metropolis comedy in Cin\u00e9ma de Montreval. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 1. The number of solemn period drama in Cin\u00e9ma de Montreval equals the number of futuristic sci-fi movie in Cin\u00e9ma de Montreval. The number of solemn period drama in Festival de Clairmont equals the number of futuristic sci-fi movie in Cin\u00e9ma de Montreval. The number of futuristic sci-fi movie in Festival de Clairmont equals the number of solemn period drama in Festival de Clairmont. The number of solemn period drama in Festival de Saint-Rivage equals 2. ", "question": "What is the total number of movies in Cin\u00e9ma de Montreval?", "solution": "Define upbeat metropolis comedy in Cin\u00e9ma de Montreval as k; so k = 4. Define futuristic sci-fi movie in Cin\u00e9ma de Montreval as e; g = k = 4; so e = 1 + g = 1 + 4 = 5. Define solemn period drama in Cin\u00e9ma de Montreval as C; so C = e = 5. Define total number of movies in Cin\u00e9ma de Montreval as x; b = C + k = 5 + 4 = 9; so x = b + e = 9 + 5 = 14. Answer: 14.", "op": 7, "id": "8_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult blue jay in Maple Creek equals 3 times the number of adult owl in Maple Creek. The number of adult blue jay in Beverly Forest equals 1. The number of adult eagle in Pine Ridge equals the number of adult owl in Beverly Forest. The number of adult owl in Beverly Forest equals 1. The number of adult owl in Pine Ridge equals 3. The number of adult owl in Maple Creek equals 4. The number of adult eagle in Maple Creek equals the number of adult owl in Maple Creek. The number of adult eagle in Beverly Forest equals the number of adult owl in Beverly Forest. The number of adult blue jay in Pine Ridge equals 3. ", "question": "What is the total number of adult animals in Maple Creek?", "solution": "Define adult owl in Maple Creek as T; so T = 4. Define adult eagle in Maple Creek as q; so q = T = 4. Define adult blue jay in Maple Creek as i; l = T = 4; so i = 3 * l = 3 * 4 = 12. Define total number of adult animals in Maple Creek as t; e = T + q = 4 + 4 = 8; so t = e + i = 8 + 12 = 20. Answer: 20.", "op": 7, "id": "5_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in Northwood Movie Festival equals 3. The number of calm road movie in Northwood Movie Festival equals the number of solemn period drama in West Sahara Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 4. The number of calm road movie in West Sahara Movie Festival equals 1 plus the sum of the number of futuristic sci-fi movie in Northwood Movie Festival and the number of solemn period drama in West Sahara Movie Festival. The number of calm road movie in Verdi Movie Festival equals 3. The number of solemn period drama in West Sahara Movie Festival equals 2. The number of futuristic sci-fi movie in Northwood Movie Festival equals 2 plus the number of calm road movie in Northwood Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals 4 times the number of solemn period drama in West Sahara Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals the difference between the total number of movies in Northwood Movie Festival and the number of futuristic sci-fi movie in Northwood Movie Festival. ", "question": "How many calm road movie does West Sahara Movie Festival have?", "solution": "Define solemn period drama in West Sahara Movie Festival as G; so G = 2. Define calm road movie in Northwood Movie Festival as F; so F = G = 2. Define futuristic sci-fi movie in Northwood Movie Festival as r; u = F = 2; so r = 2 + u = 2 + 2 = 4. Define calm road movie in West Sahara Movie Festival as c; I = r + G = 4 + 2 = 6; so c = 1 + I = 1 + 6 = 7. Answer: 7.", "op": 7, "id": "3_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult deer in Bundle Ranch equals 4 plus the total number of adult animals in South Zoo. The number of adult fox in Hamilton Farm equals 2. The number of adult wolf in Jefferson Circus equals 4 plus the number of adult bear in Jefferson Circus. The number of adult bear in Mayer Aquarium equals 3. The number of adult deer in Hamilton Farm equals the sum of the number of adult wolf in Mayer Aquarium, the total number of adult animals in South Zoo, and the number of adult bear in Mayer Aquarium. The number of adult bear in Jefferson Circus equals 2. The number of adult wolf in Mayer Aquarium equals 4 plus the number of adult bear in Mayer Aquarium. The number of adult racoon in Hamilton Farm equals 4 plus the number of adult wolf in Jefferson Circus. The number of adult fox in South Zoo equals the total number of adult animals in Mayer Aquarium. The number of adult bear in Hamilton Farm equals 2 plus the number of adult wolf in Jefferson Circus. ", "question": "What is the total number of adult animals in South Zoo?", "solution": "Define adult bear in Mayer Aquarium as A; so A = 3. Define adult wolf in Mayer Aquarium as m; y = A = 3; so m = 4 + y = 4 + 3 = 7. Define total number of adult animals in Mayer Aquarium as r; so r = m + A = 7 + 3 = 10. Define adult fox in South Zoo as z; so z = r = 10. Define total number of adult animals in South Zoo as v; so v = z = 10. Answer: 10.", "op": 7, "id": "15_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of upbeat metropolis comedy in Festival de Clairmont equals 3. The number of solemn period drama in R\u00eaves de Belleville equals the total number of movies in Cin\u00e9ma de Montreval. The number of intense detective thriller in Festival Lumi\u00e8re de Valmont equals 1. The number of futuristic sci-fi movie in Cin\u00e9ma de Montreval equals 4 plus the number of calm road movie in Cin\u00e9ma de Montreval. The number of intense detective thriller in Festival de Clairmont equals 2. The number of calm road movie in Cin\u00e9ma de Montreval equals 3. The number of solemn period drama in Festival de Clairmont equals 1 plus the number of intense detective thriller in Festival Lumi\u00e8re de Valmont. The number of calm road movie in Festival de Saint-Rivage equals the number of futuristic sci-fi movie in Cin\u00e9ma de Montreval. ", "question": "What is the total number of movies in R\u00eaves de Belleville?", "solution": "Define calm road movie in Cin\u00e9ma de Montreval as Q; so Q = 3. Define futuristic sci-fi movie in Cin\u00e9ma de Montreval as l; R = Q = 3; so l = 4 + R = 4 + 3 = 7. Define total number of movies in Cin\u00e9ma de Montreval as S; so S = Q + l = 3 + 7 = 10. Define solemn period drama in R\u00eaves de Belleville as n; so n = S = 10. Define total number of movies in R\u00eaves de Belleville as h; so h = n = 10. Answer: 10.", "op": 7, "id": "21_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult deer in Oakridge Riverside equals 4. The number of adult fox in Oakridge Riverside equals 4. The number of adult racoon in Cedar Valley equals 3. The number of adult fox in Cedar Valley equals 3. The number of adult deer in Cedar Valley equals 1. The number of adult racoon in Maple Creek equals 2 times the number of adult fox in Maple Creek. The number of adult fox in Maple Creek equals 2. The number of adult deer in Maple Creek equals the number of adult fox in Maple Creek. The number of adult racoon in Oakridge Riverside equals 2 times the number of adult fox in Cedar Valley. ", "question": "What is the total number of adult animals in Maple Creek?", "solution": "Define adult fox in Maple Creek as G; so G = 2. Define adult racoon in Maple Creek as f; a = G = 2; so f = 2 * a = 2 * 2 = 4. Define adult deer in Maple Creek as Z; so Z = G = 2. Define total number of adult animals in Maple Creek as Y; H = Z + G = 2 + 2 = 4; so Y = H + f = 4 + 4 = 8. Answer: 8.", "op": 7, "id": "12_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult owl in Hamilton Farm equals the total number of adult animals in South Zoo. The number of adult eagle in South Zoo equals 3. The number of adult parrot in Hamilton Farm equals 4. The number of adult owl in South Zoo equals 1 plus the number of adult eagle in South Zoo. The number of adult eagle in Jefferson Circus equals the sum of the number of adult parrot in South Zoo, the number of adult eagle in South Zoo, and the number of adult eagle in Hamilton Farm. The number of adult owl in Jefferson Circus equals the total number of adult animals in Hamilton Farm. The number of adult eagle in Hamilton Farm equals 4. The number of adult parrot in South Zoo equals 4. ", "question": "What is the total number of adult animals in South Zoo?", "solution": "Define adult eagle in South Zoo as Q; so Q = 3. Define adult owl in South Zoo as v; J = Q = 3; so v = 1 + J = 1 + 3 = 4. Define adult parrot in South Zoo as n; so n = 4. Define total number of adult animals in South Zoo as I; M = n + Q = 4 + 3 = 7; so I = M + v = 7 + 4 = 11. Answer: 11.", "op": 7, "id": "16_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult owl in Maple Creek equals 4. The number of adult parrot in Cedar Valley equals 4 times the number of adult crow in Cedar Valley. The number of adult owl in Oakridge Riverside equals 3. The number of adult parrot in Maple Creek equals the sum of the total number of adult animals in Cedar Valley, the number of adult parrot in Cedar Valley, the number of adult crow in Cedar Valley, and the number of adult owl in Cedar Valley. The number of adult crow in Cedar Valley equals 3. The number of adult parrot in Oakridge Riverside equals 4 plus the number of adult crow in Maple Creek. The number of adult crow in Maple Creek equals 3. The number of adult owl in Cedar Valley equals 4. ", "question": "What is the total number of adult animals in Cedar Valley?", "solution": "Define adult crow in Cedar Valley as K; so K = 3. Define adult parrot in Cedar Valley as d; u = K = 3; so d = 4 * u = 4 * 3 = 12. Define adult owl in Cedar Valley as g; so g = 4. Define total number of adult animals in Cedar Valley as U; P = g + K = 4 + 3 = 7; so U = P + d = 7 + 12 = 19. Answer: 19.", "op": 7, "id": "5_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of calm road movie in Cin\u00e9ma de Montreval equals 4. The number of calm road movie in R\u00eaves de Belleville equals 4. The number of futuristic sci-fi movie in Festival de Clairmont equals 4. The number of futuristic sci-fi movie in R\u00eaves de Belleville equals the total number of movies in Cin\u00e9ma de Montreval. The number of futuristic sci-fi movie in Cin\u00e9ma de Montreval equals 3 times the number of solemn period drama in Cin\u00e9ma de Montreval. The number of solemn period drama in Festival de Clairmont equals 4. The number of solemn period drama in R\u00eaves de Belleville equals 4. The number of calm road movie in Festival de Clairmont equals 4. The number of solemn period drama in Cin\u00e9ma de Montreval equals 2. ", "question": "What is the total number of movies in Cin\u00e9ma de Montreval?", "solution": "Define solemn period drama in Cin\u00e9ma de Montreval as x; so x = 2. Define futuristic sci-fi movie in Cin\u00e9ma de Montreval as y; n = x = 2; so y = 3 * n = 3 * 2 = 6. Define calm road movie in Cin\u00e9ma de Montreval as X; so X = 4. Define total number of movies in Cin\u00e9ma de Montreval as V; Z = x + y = 2 + 6 = 8; so V = Z + X = 8 + 4 = 12. Answer: 12.", "op": 7, "id": "11_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of calm road movie in West Sahara Movie Festival equals 2 plus the difference between the number of upbeat metropolis comedy in Taylor Movie Festival and the number of calm road movie in Taylor Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 1 plus the number of calm road movie in Taylor Movie Festival. The number of calm road movie in Taylor Movie Festival equals 2. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the number of calm road movie in West Sahara Movie Festival. ", "question": "How many upbeat metropolis comedy does West Sahara Movie Festival have?", "solution": "Define calm road movie in Taylor Movie Festival as x; so x = 2. Define upbeat metropolis comedy in Taylor Movie Festival as A; d = x = 2; so A = 1 + d = 1 + 2 = 3. Define calm road movie in West Sahara Movie Festival as V; T = A - x = 3 - 2 = 1; so V = 2 + T = 2 + 1 = 3. Define upbeat metropolis comedy in West Sahara Movie Festival as u; so u = V = 3. Answer: 3.", "op": 7, "id": "22_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of regional medical school in Oakbridge City equals the number of culinarian school in Ruby Bay. The number of culinarian school in Ruby Bay equals 2. The number of elementary school in Oakbridge City equals 2. The number of elementary school in Ruby Bay equals 3. The number of culinarian school in Oakbridge City equals the number of regional medical school in Oakbridge City. The number of regional medical school in Ruby Bay equals 1 plus the sum of the total number of schools in Oakbridge City, the number of regional medical school in Oakbridge City, and the number of culinarian school in Oakbridge City. ", "question": "What is the total number of schools in Oakbridge City?", "solution": "Define culinarian school in Ruby Bay as V; so V = 2. Define regional medical school in Oakbridge City as r; so r = V = 2. Define culinarian school in Oakbridge City as v; so v = r = 2. Define elementary school in Oakbridge City as t; so t = 2. Define total number of schools in Oakbridge City as H; Q = t + v = 2 + 2 = 4; so H = Q + r = 4 + 2 = 6. Answer: 6.", "op": 7, "id": "11_p5", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of culinarian school in Oakbridge City equals 1. The number of public highschool in Riverton City equals the number of regional medical school in Shoreline City. The number of elementary school in Ruby Bay equals the sum of the total number of schools in Oakbridge City, the number of regional medical school in Oakbridge City, and the number of culinarian school in Oakbridge City. The number of public highschool in Shoreline City equals the difference between the number of regional medical school in Ruby Bay and the number of regional medical school in Riverton City. The number of regional medical school in Oakbridge City equals 3. The number of regional medical school in Riverton City equals 3 plus the difference between the number of regional medical school in Shoreline City and the number of regional medical school in Ruby Bay. The number of public highschool in Ruby Bay equals the number of public highschool in Shoreline City. The number of regional medical school in Ruby Bay equals 3. The number of regional medical school in Shoreline City equals 2. ", "question": "How many elementary school does Ruby Bay have?", "solution": "Define regional medical school in Oakbridge City as b; so b = 3. Define culinarian school in Oakbridge City as k; so k = 1. Define total number of schools in Oakbridge City as v; so v = b + k = 3 + 1 = 4. Define elementary school in Ruby Bay as w; R = v + b = 4 + 3 = 7; so w = R + k = 7 + 1 = 8. Answer: 8.", "op": 7, "id": "16_p5", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult eagle in Mayer Aquarium equals 4 plus the number of adult crow in Mayer Aquarium. The number of adult crow in Mayer Aquarium equals 4. The number of adult owl in Hamilton Farm equals 1. The number of adult crow in Bundle Ranch equals 1 plus the number of adult blue jay in Hamilton Farm. The number of adult owl in Jefferson Circus equals the total number of adult animals in Hamilton Farm. The number of adult blue jay in Hamilton Farm equals 4. The number of adult eagle in Bundle Ranch equals 4 times the sum of the number of adult blue jay in Hamilton Farm, the number of adult crow in Hamilton Farm, and the number of adult eagle in Hamilton Farm. The number of adult eagle in Hamilton Farm equals the number of adult blue jay in Hamilton Farm. The number of adult owl in Bundle Ranch equals 2 plus the sum of the number of adult crow in Hamilton Farm and the number of adult blue jay in Hamilton Farm. The number of adult crow in Hamilton Farm equals 4 plus the number of adult blue jay in Hamilton Farm. The number of adult blue jay in Jefferson Circus equals 4. The number of adult blue jay in Mayer Aquarium equals 2. ", "question": "What is the total number of adult animals in Mayer Aquarium?", "solution": "Define adult crow in Mayer Aquarium as Q; so Q = 4. Define adult eagle in Mayer Aquarium as d; v = Q = 4; so d = 4 + v = 4 + 4 = 8. Define adult blue jay in Mayer Aquarium as l; so l = 2. Define total number of adult animals in Mayer Aquarium as r; z = d + Q = 8 + 4 = 12; so r = z + l = 12 + 2 = 14. Answer: 14.", "op": 7, "id": "2_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult fox in Maple Creek equals 3. The number of adult bear in Maple Creek equals 4. The number of adult wolf in Cedar Valley equals 1. The number of adult wolf in Oakridge Riverside equals the number of adult bear in Oakridge Riverside. The number of adult fox in Cedar Valley equals 2. The number of adult bear in Cedar Valley equals 2 plus the number of adult fox in Cedar Valley. The number of adult bear in Oakridge Riverside equals 3. The number of adult fox in Oakridge Riverside equals 4 times the number of adult bear in Oakridge Riverside. The number of adult wolf in Maple Creek equals 2. ", "question": "What is the total number of adult animals in Oakridge Riverside?", "solution": "Define adult bear in Oakridge Riverside as S; so S = 3. Define adult fox in Oakridge Riverside as W; j = S = 3; so W = 4 * j = 4 * 3 = 12. Define adult wolf in Oakridge Riverside as C; so C = S = 3. Define total number of adult animals in Oakridge Riverside as e; Z = S + C = 3 + 3 = 6; so e = Z + W = 6 + 12 = 18. Answer: 18.", "op": 7, "id": "13_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult racoon in Beverly Forest equals 4. The number of adult deer in Maple Creek equals 1. The number of adult deer in Cedar Valley equals 4 plus the total number of adult animals in Maple Creek. The number of adult racoon in Cedar Valley equals 4. The number of adult fox in Beverly Forest equals 2 plus the total number of adult animals in Maple Creek. ", "question": "What is the total number of adult animals in Beverly Forest?", "solution": "Define adult deer in Maple Creek as e; so e = 1. Define total number of adult animals in Maple Creek as c; so c = e = 1. Define adult racoon in Beverly Forest as x; so x = 4. Define adult fox in Beverly Forest as y; W = c = 1; so y = 2 + W = 2 + 1 = 3. Define total number of adult animals in Beverly Forest as I; so I = x + y = 4 + 3 = 7. Answer: 7.", "op": 7, "id": "4_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of regional medical school in Riverton City equals 4. The number of regional medical school in Oakbridge City equals 3. The number of private middle school in Shoreline City equals 2 times the number of public highschool in Shoreline City. The number of private middle school in Riverton City equals 3 times the number of regional medical school in Riverton City. The number of public highschool in Clearwater Bay equals 3. The number of elementary school in Shoreline City equals the number of public highschool in Shoreline City. The number of public highschool in Oakbridge City equals 1. The number of public highschool in Shoreline City equals 4. ", "question": "What is the total number of schools in Shoreline City?", "solution": "Define public highschool in Shoreline City as j; so j = 4. Define elementary school in Shoreline City as L; so L = j = 4. Define private middle school in Shoreline City as I; b = j = 4; so I = 2 * b = 2 * 4 = 8. Define total number of schools in Shoreline City as N; g = I + L = 8 + 4 = 12; so N = g + j = 12 + 4 = 16. Answer: 16.", "op": 7, "id": "16_p5", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult eagle in Beverly Forest equals the number of adult parrot in Maple Creek. The number of adult crow in Maple Creek equals the number of adult parrot in Pine Ridge. The number of adult blue jay in Oakridge Riverside equals the total number of adult animals in Beverly Forest. The number of adult eagle in Pine Ridge equals 2 plus the number of adult crow in Maple Creek. The number of adult blue jay in Beverly Forest equals 4. The number of adult parrot in Maple Creek equals 3. The number of adult crow in Pine Ridge equals the number of adult eagle in Beverly Forest. The number of adult parrot in Pine Ridge equals 1. ", "question": "What is the total number of adult animals in Oakridge Riverside?", "solution": "Define adult blue jay in Beverly Forest as r; so r = 4. Define adult parrot in Maple Creek as N; so N = 3. Define adult eagle in Beverly Forest as m; so m = N = 3. Define total number of adult animals in Beverly Forest as w; so w = m + r = 3 + 4 = 7. Define adult blue jay in Oakridge Riverside as x; so x = w = 7. Define total number of adult animals in Oakridge Riverside as A; so A = x = 7. Answer: 7.", "op": 7, "id": "3_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult parrot in Cedar Valley equals 4. The number of adult crow in Pine Ridge equals the difference between the number of adult crow in Oakridge Riverside and the number of adult parrot in Oakridge Riverside. The number of adult blue jay in Cedar Valley equals the sum of the number of adult parrot in Cedar Valley and the number of adult crow in Cedar Valley. The number of adult crow in Oakridge Riverside equals 4. The number of adult parrot in Pine Ridge equals the difference between the number of adult blue jay in Oakridge Riverside and the number of adult parrot in Oakridge Riverside. The number of adult parrot in Oakridge Riverside equals 4 plus the number of adult crow in Oakridge Riverside. The number of adult blue jay in Oakridge Riverside equals 1. The number of adult crow in Cedar Valley equals the number of adult parrot in Cedar Valley. The number of adult blue jay in Pine Ridge equals the sum of the total number of adult animals in Cedar Valley, the number of adult parrot in Cedar Valley, the total number of adult animals in Oakridge Riverside, and the number of adult blue jay in Cedar Valley. ", "question": "What is the total number of adult animals in Cedar Valley?", "solution": "Define adult parrot in Cedar Valley as O; so O = 4. Define adult crow in Cedar Valley as L; so L = O = 4. Define adult blue jay in Cedar Valley as K; so K = O + L = 4 + 4 = 8. Define total number of adult animals in Cedar Valley as M; D = O + L = 4 + 4 = 8; so M = D + K = 8 + 8 = 16. Answer: 16.", "op": 7, "id": "12_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult owl in Maple Creek equals 3 times the number of adult owl in Cedar Valley. The number of adult blue jay in Cedar Valley equals the total number of adult animals in Maple Creek. The number of adult crow in Cedar Valley equals 1. The number of adult blue jay in Maple Creek equals the number of adult owl in Cedar Valley. The number of adult owl in Cedar Valley equals 4. ", "question": "How many adult blue jay does Cedar Valley have?", "solution": "Define adult owl in Cedar Valley as l; so l = 4. Define adult blue jay in Maple Creek as I; so I = l = 4. Define adult owl in Maple Creek as q; j = l = 4; so q = 3 * j = 3 * 4 = 12. Define total number of adult animals in Maple Creek as F; so F = q + I = 12 + 4 = 16. Define adult blue jay in Cedar Valley as g; so g = F = 16. Answer: 16.", "op": 7, "id": "1_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult blue jay in Oakridge Riverside equals 3. The number of adult owl in Oakridge Riverside equals 4. The number of adult eagle in Oakridge Riverside equals 1 plus the sum of the total number of adult animals in Cedar Valley, the total number of adult animals in Pine Ridge, and the number of adult owl in Cedar Valley. The number of adult parrot in Pine Ridge equals 3 plus the number of adult crow in Pine Ridge. The number of adult owl in Cedar Valley equals 1. The number of adult owl in Beverly Forest equals 4. The number of adult crow in Pine Ridge equals the total number of adult animals in Cedar Valley. The number of adult blue jay in Maple Creek equals 2 plus the difference between the number of adult owl in Cedar Valley and the number of adult eagle in Oakridge Riverside. ", "question": "What is the total number of adult animals in Pine Ridge?", "solution": "Define adult owl in Cedar Valley as T; so T = 1. Define total number of adult animals in Cedar Valley as P; so P = T = 1. Define adult crow in Pine Ridge as v; so v = P = 1. Define adult parrot in Pine Ridge as a; q = v = 1; so a = 3 + q = 3 + 1 = 4. Define total number of adult animals in Pine Ridge as Z; so Z = a + v = 4 + 1 = 5. Answer: 5.", "op": 7, "id": "18_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of intense detective thriller in Taylor Movie Festival equals 2 plus the number of upbeat metropolis comedy in Taylor Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals 2 times the difference between the number of upbeat metropolis comedy in Northwood Movie Festival and the number of calm road movie in Northwood Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the total number of movies in Taylor Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 4. The number of calm road movie in Taylor Movie Festival equals 3. The number of calm road movie in Northwood Movie Festival equals the number of upbeat metropolis comedy in Northwood Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals the total number of movies in Taylor Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 3. ", "question": "What is the total number of movies in Taylor Movie Festival?", "solution": "Define upbeat metropolis comedy in Taylor Movie Festival as o; so o = 3. Define intense detective thriller in Taylor Movie Festival as O; S = o = 3; so O = 2 + S = 2 + 3 = 5. Define calm road movie in Taylor Movie Festival as c; so c = 3. Define total number of movies in Taylor Movie Festival as P; w = o + c = 3 + 3 = 6; so P = w + O = 6 + 5 = 11. Answer: 11.", "op": 7, "id": "8_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult bear in Maple Creek equals 3 times the sum of the number of adult bear in Oakridge Riverside, the total number of adult animals in Oakridge Riverside, and the number of adult deer in Maple Creek. The number of adult bear in Oakridge Riverside equals 3 times the number of adult deer in Maple Creek. The number of adult wolf in Oakridge Riverside equals 3 plus the number of adult bear in Oakridge Riverside. The number of adult wolf in Maple Creek equals 2. The number of adult deer in Maple Creek equals 4. ", "question": "What is the total number of adult animals in Oakridge Riverside?", "solution": "Define adult deer in Maple Creek as d; so d = 4. Define adult bear in Oakridge Riverside as h; I = d = 4; so h = 3 * I = 3 * 4 = 12. Define adult wolf in Oakridge Riverside as U; e = h = 12; so U = 3 + e = 3 + 12 = 15. Define total number of adult animals in Oakridge Riverside as l; so l = U + h = 15 + 12 = 27. Answer: 27.", "op": 7, "id": "16_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of calm road movie in R\u00eaves de Belleville equals 3 plus the number of futuristic sci-fi movie in Festival de Clairmont. The number of intense detective thriller in Festival de Saint-Rivage equals 2 times the number of calm road movie in R\u00eaves de Belleville. The number of futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont equals 4. The number of calm road movie in Festival de Saint-Rivage equals the number of futuristic sci-fi movie in Festival de Clairmont. The number of upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont equals 4 plus the number of futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont. The number of calm road movie in Cin\u00e9ma de Montreval equals the sum of the total number of movies in Festival Lumi\u00e8re de Valmont and the number of upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont. The number of futuristic sci-fi movie in Festival de Clairmont equals 2. The number of solemn period drama in Festival de Saint-Rivage equals 3. ", "question": "How many calm road movie does Cin\u00e9ma de Montreval have?", "solution": "Define futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont as B; so B = 4. Define upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont as i; K = B = 4; so i = 4 + K = 4 + 4 = 8. Define total number of movies in Festival Lumi\u00e8re de Valmont as c; so c = B + i = 4 + 8 = 12. Define calm road movie in Cin\u00e9ma de Montreval as Z; so Z = c + i = 12 + 8 = 20. Answer: 20.", "op": 7, "id": "15_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 4. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 3. The number of futuristic sci-fi movie in Northwood Movie Festival equals 4 times the sum of the total number of movies in Golden Banana Movie Festival and the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 3. ", "question": "How many futuristic sci-fi movie does Northwood Movie Festival have?", "solution": "Define futuristic sci-fi movie in Golden Banana Movie Festival as f; so f = 3. Define upbeat metropolis comedy in Golden Banana Movie Festival as z; so z = 4. Define total number of movies in Golden Banana Movie Festival as L; so L = z + f = 4 + 3 = 7. Define futuristic sci-fi movie in Northwood Movie Festival as l; s = L + z = 7 + 4 = 11; so l = 4 * s = 4 * 11 = 44. Answer: 44.", "op": 7, "id": "2_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult fox in Beverly Forest equals 4. The number of adult bear in Maple Creek equals 4 times the number of adult fox in Beverly Forest. The number of adult bear in Oakridge Riverside equals 2. The number of adult bear in Beverly Forest equals 3 times the number of adult fox in Beverly Forest. The number of adult fox in Maple Creek equals the difference between the total number of adult animals in Pine Ridge and the number of adult fox in Pine Ridge. The number of adult deer in Cedar Valley equals 2. The number of adult racoon in Cedar Valley equals 3 plus the sum of the total number of adult animals in Pine Ridge, the number of adult bear in Oakridge Riverside, and the number of adult fox in Pine Ridge. The number of adult fox in Pine Ridge equals the number of adult bear in Oakridge Riverside. The number of adult wolf in Cedar Valley equals 2. The number of adult wolf in Beverly Forest equals the sum of the number of adult fox in Maple Creek, the number of adult bear in Maple Creek, and the total number of adult animals in Oakridge Riverside. ", "question": "How many adult racoon does Cedar Valley have?", "solution": "Define adult bear in Oakridge Riverside as J; so J = 2. Define adult fox in Pine Ridge as t; so t = J = 2. Define total number of adult animals in Pine Ridge as Q; so Q = t = 2. Define adult racoon in Cedar Valley as u; Z = Q + J = 2 + 2 = 4; D = Z + t = 4 + 2 = 6; so u = 3 + D = 3 + 6 = 9. Answer: 9.", "op": 7, "id": "4_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of private middle school in Hawkesbury equals 3. The number of regional medical school in Glenfield City equals 3 plus the sum of the number of public highschool in Hawkesbury, the total number of schools in Evervale City, and the total number of schools in Glenfield City. The number of public highschool in Hawkesbury equals 4. The number of public highschool in Evervale City equals 2. The number of private middle school in Brightford equals the number of private middle school in Glenfield City. The number of regional medical school in Hawkesbury equals 3 times the number of private middle school in Hawkesbury. The number of public highschool in Glenfield City equals the number of public highschool in Hawkesbury. The number of private middle school in Glenfield City equals 2. The number of private middle school in Evervale City equals 4 times the total number of schools in Hawkesbury. The number of regional medical school in Brightford equals 4 times the number of private middle school in Glenfield City. ", "question": "What is the total number of schools in Hawkesbury?", "solution": "Define private middle school in Hawkesbury as D; so D = 3. Define regional medical school in Hawkesbury as r; H = D = 3; so r = 3 * H = 3 * 3 = 9. Define public highschool in Hawkesbury as s; so s = 4. Define total number of schools in Hawkesbury as b; K = s + D = 4 + 3 = 7; so b = K + r = 7 + 9 = 16. Answer: 16.", "op": 7, "id": "12_p5", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult racoon in Oakridge Riverside equals the number of adult bear in Pine Ridge. The number of adult bear in Maple Creek equals 1 plus the number of adult bear in Pine Ridge. The number of adult deer in Pine Ridge equals 2. The number of adult racoon in Pine Ridge equals 3 plus the sum of the number of adult bear in Oakridge Riverside and the number of adult wolf in Oakridge Riverside. The number of adult deer in Cedar Valley equals 4 times the number of adult wolf in Cedar Valley. The number of adult bear in Oakridge Riverside equals 3. The number of adult bear in Cedar Valley equals 2. The number of adult deer in Oakridge Riverside equals the sum of the number of adult bear in Pine Ridge and the number of adult wolf in Oakridge Riverside. The number of adult racoon in Maple Creek equals 2 plus the sum of the number of adult deer in Oakridge Riverside, the number of adult racoon in Pine Ridge, and the number of adult wolf in Oakridge Riverside. The number of adult wolf in Oakridge Riverside equals 4 times the number of adult bear in Oakridge Riverside. The number of adult bear in Pine Ridge equals 4. The number of adult wolf in Cedar Valley equals 2. The number of adult wolf in Pine Ridge equals 2 plus the sum of the total number of adult animals in Cedar Valley, the number of adult bear in Oakridge Riverside, and the number of adult racoon in Pine Ridge. The number of adult deer in Maple Creek equals the sum of the number of adult wolf in Pine Ridge, the total number of adult animals in Pine Ridge, the total number of adult animals in Cedar Valley, and the number of adult deer in Pine Ridge. ", "question": "What is the total number of adult animals in Cedar Valley?", "solution": "Define adult wolf in Cedar Valley as E; so E = 2. Define adult deer in Cedar Valley as a; l = E = 2; so a = 4 * l = 4 * 2 = 8. Define adult bear in Cedar Valley as i; so i = 2. Define total number of adult animals in Cedar Valley as Y; f = a + i = 8 + 2 = 10; so Y = f + E = 10 + 2 = 12. Answer: 12.", "op": 7, "id": "2_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of regional medical school in Shoreline City equals 2. The number of regional medical school in Clearwater Bay equals the difference between the number of regional medical school in Shoreline City and the number of elementary school in Clearwater Bay. The number of culinarian school in Shoreline City equals the number of regional medical school in Shoreline City. The number of culinarian school in Clearwater Bay equals 4 times the sum of the number of culinarian school in Ruby Bay, the total number of schools in Ruby Bay, and the number of regional medical school in Ruby Bay. The number of elementary school in Shoreline City equals 2. The number of regional medical school in Ruby Bay equals 2. The number of elementary school in Ruby Bay equals the sum of the number of culinarian school in Ruby Bay and the number of regional medical school in Ruby Bay. The number of culinarian school in Ruby Bay equals the number of regional medical school in Ruby Bay. The number of elementary school in Clearwater Bay equals 1. ", "question": "What is the total number of schools in Ruby Bay?", "solution": "Define regional medical school in Ruby Bay as e; so e = 2. Define culinarian school in Ruby Bay as I; so I = e = 2. Define elementary school in Ruby Bay as U; so U = I + e = 2 + 2 = 4. Define total number of schools in Ruby Bay as Z; o = e + I = 2 + 2 = 4; so Z = o + U = 4 + 4 = 8. Answer: 8.", "op": 7, "id": "19_p5", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of intense detective thriller in West Sahara Movie Festival equals 4. The number of upbeat metropolis comedy in Verdi Movie Festival equals the number of futuristic sci-fi movie in Verdi Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 2. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals the sum of the total number of movies in West Sahara Movie Festival and the number of futuristic sci-fi movie in West Sahara Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals the sum of the number of futuristic sci-fi movie in Golden Banana Movie Festival, the number of futuristic sci-fi movie in Verdi Movie Festival, the total number of movies in West Sahara Movie Festival, and the number of futuristic sci-fi movie in West Sahara Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals 2. ", "question": "What is the total number of movies in Golden Banana Movie Festival?", "solution": "Define futuristic sci-fi movie in West Sahara Movie Festival as W; so W = 2. Define intense detective thriller in West Sahara Movie Festival as o; so o = 4. Define total number of movies in West Sahara Movie Festival as d; so d = o + W = 4 + 2 = 6. Define futuristic sci-fi movie in Golden Banana Movie Festival as T; so T = d + W = 6 + 2 = 8. Define total number of movies in Golden Banana Movie Festival as p; so p = T = 8. Answer: 8.", "op": 7, "id": "15_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of futuristic sci-fi movie in Festival de Saint-Rivage equals the total number of movies in Festival Lumi\u00e8re de Valmont. The number of futuristic sci-fi movie in Festival de Clairmont equals the total number of movies in Festival Lumi\u00e8re de Valmont. The number of intense detective thriller in Festival de Clairmont equals 3. The number of intense detective thriller in Festival de Saint-Rivage equals the number of futuristic sci-fi movie in Festival de Saint-Rivage. The number of upbeat metropolis comedy in Cin\u00e9ma de Montreval equals 3. The number of futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont equals the number of upbeat metropolis comedy in Cin\u00e9ma de Montreval. The number of intense detective thriller in Cin\u00e9ma de Montreval equals 1. The number of solemn period drama in Cin\u00e9ma de Montreval equals the total number of movies in Cin\u00e9ma de Montreval. ", "question": "What is the total number of movies in Festival de Saint-Rivage?", "solution": "Define upbeat metropolis comedy in Cin\u00e9ma de Montreval as q; so q = 3. Define futuristic sci-fi movie in Festival Lumi\u00e8re de Valmont as Y; so Y = q = 3. Define total number of movies in Festival Lumi\u00e8re de Valmont as i; so i = Y = 3. Define futuristic sci-fi movie in Festival de Saint-Rivage as Z; so Z = i = 3. Define intense detective thriller in Festival de Saint-Rivage as X; so X = Z = 3. Define total number of movies in Festival de Saint-Rivage as h; so h = Z + X = 3 + 3 = 6. Answer: 6.", "op": 7, "id": "7_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of futuristic sci-fi movie in Taylor Movie Festival equals 3 times the number of upbeat metropolis comedy in Taylor Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals the number of futuristic sci-fi movie in Taylor Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals 2 plus the difference between the number of upbeat metropolis comedy in Golden Banana Movie Festival and the number of intense detective thriller in Taylor Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals 3. The number of intense detective thriller in Verdi Movie Festival equals 2 times the number of intense detective thriller in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 2. The number of futuristic sci-fi movie in Verdi Movie Festival equals the number of intense detective thriller in Golden Banana Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 4 times the sum of the total number of movies in Taylor Movie Festival, the number of intense detective thriller in Taylor Movie Festival, and the number of upbeat metropolis comedy in Taylor Movie Festival. ", "question": "What is the total number of movies in Taylor Movie Festival?", "solution": "Define upbeat metropolis comedy in Taylor Movie Festival as I; so I = 2. Define futuristic sci-fi movie in Taylor Movie Festival as m; k = I = 2; so m = 3 * k = 3 * 2 = 6. Define intense detective thriller in Taylor Movie Festival as K; so K = m = 6. Define total number of movies in Taylor Movie Festival as W; w = K + m = 6 + 6 = 12; so W = w + I = 12 + 2 = 14. Answer: 14.", "op": 7, "id": "14_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in Festival de Clairmont equals 2. The number of upbeat metropolis comedy in Cin\u00e9ma de Montreval equals 2 times the sum of the number of intense detective thriller in Festival de Clairmont, the total number of movies in Festival de Clairmont, and the number of upbeat metropolis comedy in Festival de Clairmont. The number of intense detective thriller in Festival de Clairmont equals 3. The number of calm road movie in Cin\u00e9ma de Montreval equals the sum of the number of upbeat metropolis comedy in Cin\u00e9ma de Montreval, the total number of movies in Festival de Clairmont, the number of solemn period drama in Festival de Clairmont, and the number of intense detective thriller in Festival de Clairmont. The number of upbeat metropolis comedy in Festival de Clairmont equals the sum of the number of intense detective thriller in Festival de Clairmont and the number of solemn period drama in Festival de Clairmont. The number of solemn period drama in Festival de Saint-Rivage equals 3. The number of intense detective thriller in Cin\u00e9ma de Montreval equals 4 plus the sum of the number of upbeat metropolis comedy in Cin\u00e9ma de Montreval, the number of solemn period drama in Festival de Clairmont, and the number of intense detective thriller in Festival de Clairmont. The number of calm road movie in Festival de Saint-Rivage equals the number of upbeat metropolis comedy in Cin\u00e9ma de Montreval. The number of solemn period drama in Cin\u00e9ma de Montreval equals 4. ", "question": "What is the total number of movies in Festival de Clairmont?", "solution": "Define solemn period drama in Festival de Clairmont as N; so N = 2. Define intense detective thriller in Festival de Clairmont as e; so e = 3. Define upbeat metropolis comedy in Festival de Clairmont as S; so S = e + N = 3 + 2 = 5. Define total number of movies in Festival de Clairmont as d; Y = N + e = 2 + 3 = 5; so d = Y + S = 5 + 5 = 10. Answer: 10.", "op": 7, "id": "3_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in West Sahara Movie Festival equals 1. The number of solemn period drama in Northwood Movie Festival equals 4. The number of intense detective thriller in Northwood Movie Festival equals 3 times the total number of movies in Taylor Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 3. ", "question": "What is the total number of movies in Northwood Movie Festival?", "solution": "Define intense detective thriller in Taylor Movie Festival as Z; so Z = 3. Define total number of movies in Taylor Movie Festival as C; so C = Z = 3. Define intense detective thriller in Northwood Movie Festival as p; E = C = 3; so p = 3 * E = 3 * 3 = 9. Define solemn period drama in Northwood Movie Festival as e; so e = 4. Define total number of movies in Northwood Movie Festival as d; so d = p + e = 9 + 4 = 13. Answer: 13.", "op": 7, "id": "15_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult blue jay in Hamilton Farm equals 1 plus the number of adult crow in Hamilton Farm. The number of adult blue jay in South Zoo equals 2. The number of adult crow in South Zoo equals 4. The number of adult eagle in South Zoo equals 3 times the number of adult crow in South Zoo. The number of adult crow in Hamilton Farm equals 2. The number of adult eagle in Hamilton Farm equals 4 plus the number of adult blue jay in Hamilton Farm. ", "question": "What is the total number of adult animals in South Zoo?", "solution": "Define adult crow in South Zoo as S; so S = 4. Define adult blue jay in South Zoo as h; so h = 2. Define adult eagle in South Zoo as g; e = S = 4; so g = 3 * e = 3 * 4 = 12. Define total number of adult animals in South Zoo as J; t = h + S = 2 + 4 = 6; so J = t + g = 6 + 12 = 18. Answer: 18.", "op": 7, "id": "4_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult eagle in Bundle Ranch equals 4. The number of adult parrot in South Zoo equals the difference between the total number of adult animals in Bundle Ranch and the number of adult parrot in Bundle Ranch. The number of adult parrot in Bundle Ranch equals the number of adult eagle in Bundle Ranch. ", "question": "What is the total number of adult animals in South Zoo?", "solution": "Define adult eagle in Bundle Ranch as G; so G = 4. Define adult parrot in Bundle Ranch as e; so e = G = 4. Define total number of adult animals in Bundle Ranch as b; so b = G + e = 4 + 4 = 8. Define adult parrot in South Zoo as j; so j = b - e = 8 - 4 = 4. Define total number of adult animals in South Zoo as K; so K = j = 4. Answer: 4.", "op": 7, "id": "11_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of regional medical school in Evervale City equals 4. The number of private middle school in Brightford equals 4. The number of public highschool in Brightford equals the sum of the total number of schools in Evervale City, the number of private middle school in Brightford, the number of public highschool in Evervale City, and the number of regional medical school in Evervale City. The number of culinarian school in Brightford equals 1. The number of public highschool in Evervale City equals 1 plus the sum of the number of culinarian school in Brightford and the number of regional medical school in Evervale City. ", "question": "What is the total number of schools in Evervale City?", "solution": "Define regional medical school in Evervale City as n; so n = 4. Define culinarian school in Brightford as Q; so Q = 1. Define public highschool in Evervale City as j; y = Q + n = 1 + 4 = 5; so j = 1 + y = 1 + 5 = 6. Define total number of schools in Evervale City as O; so O = n + j = 4 + 6 = 10. Answer: 10.", "op": 7, "id": "5_p5", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in R\u00eaves de Belleville equals 2. The number of solemn period drama in Festival de Saint-Rivage equals the number of calm road movie in Festival de Saint-Rivage. The number of calm road movie in Festival de Saint-Rivage equals 2. The number of calm road movie in R\u00eaves de Belleville equals 2 times the number of calm road movie in Festival Lumi\u00e8re de Valmont. The number of upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont equals the number of calm road movie in Festival Lumi\u00e8re de Valmont. The number of calm road movie in Festival Lumi\u00e8re de Valmont equals 4. The number of upbeat metropolis comedy in R\u00eaves de Belleville equals 4 times the sum of the total number of movies in Festival Lumi\u00e8re de Valmont and the total number of movies in R\u00eaves de Belleville. The number of solemn period drama in Festival Lumi\u00e8re de Valmont equals 4 plus the number of calm road movie in Festival Lumi\u00e8re de Valmont. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the number of solemn period drama in Festival Lumi\u00e8re de Valmont. ", "question": "What is the total number of movies in Festival Lumi\u00e8re de Valmont?", "solution": "Define calm road movie in Festival Lumi\u00e8re de Valmont as p; so p = 4. Define solemn period drama in Festival Lumi\u00e8re de Valmont as Y; v = p = 4; so Y = 4 + v = 4 + 4 = 8. Define upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont as j; so j = p = 4. Define total number of movies in Festival Lumi\u00e8re de Valmont as h; k = Y + p = 8 + 4 = 12; so h = k + j = 12 + 4 = 16. Answer: 16.", "op": 7, "id": "8_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of intense detective thriller in West Sahara Movie Festival equals the number of upbeat metropolis comedy in Golden Banana Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 2. The number of upbeat metropolis comedy in Northwood Movie Festival equals the number of intense detective thriller in Northwood Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals 4. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the number of solemn period drama in Golden Banana Movie Festival. The number of solemn period drama in Northwood Movie Festival equals 4 times the number of intense detective thriller in Northwood Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals the total number of movies in Northwood Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals the total number of movies in Golden Banana Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals the number of upbeat metropolis comedy in Golden Banana Movie Festival. ", "question": "What is the total number of movies in Northwood Movie Festival?", "solution": "Define intense detective thriller in Northwood Movie Festival as y; so y = 2. Define solemn period drama in Northwood Movie Festival as T; A = y = 2; so T = 4 * A = 4 * 2 = 8. Define upbeat metropolis comedy in Northwood Movie Festival as H; so H = y = 2. Define total number of movies in Northwood Movie Festival as b; i = y + T = 2 + 8 = 10; so b = i + H = 10 + 2 = 12. Answer: 12.", "op": 7, "id": "3_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of adult bear in Maple Creek equals the total number of adult animals in Oakridge Riverside. The number of adult wolf in Pine Ridge equals 4. The number of adult fox in Maple Creek equals 4 times the total number of adult animals in Oakridge Riverside. The number of adult fox in Oakridge Riverside equals 3. The number of adult bear in Pine Ridge equals 4. The number of adult wolf in Maple Creek equals the number of adult fox in Pine Ridge. The number of adult bear in Oakridge Riverside equals 2 times the number of adult wolf in Oakridge Riverside. The number of adult wolf in Oakridge Riverside equals 2. The number of adult fox in Pine Ridge equals 2. ", "question": "What is the total number of adult animals in Oakridge Riverside?", "solution": "Define adult wolf in Oakridge Riverside as c; so c = 2. Define adult bear in Oakridge Riverside as A; n = c = 2; so A = 2 * n = 2 * 2 = 4. Define adult fox in Oakridge Riverside as i; so i = 3. Define total number of adult animals in Oakridge Riverside as z; h = A + c = 4 + 2 = 6; so z = h + i = 6 + 3 = 9. Answer: 9.", "op": 7, "id": "4_p5", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of regional medical school in Ruby Bay equals the sum of the number of public highschool in Shoreline City and the total number of schools in Shoreline City. The number of public highschool in Shoreline City equals 2. The number of culinarian school in Ruby Bay equals the total number of schools in Shoreline City. ", "question": "What is the total number of schools in Ruby Bay?", "solution": "Define public highschool in Shoreline City as t; so t = 2. Define total number of schools in Shoreline City as c; so c = t = 2. Define culinarian school in Ruby Bay as U; so U = c = 2. Define regional medical school in Ruby Bay as h; so h = t + c = 2 + 2 = 4. Define total number of schools in Ruby Bay as B; so B = U + h = 2 + 4 = 6. Answer: 6.", "op": 7, "id": "5_p5", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of culinarian school in Shoreline City equals 1. The number of culinarian school in Riverton City equals 2. The number of regional medical school in Riverton City equals the number of culinarian school in Shoreline City. The number of private middle school in Shoreline City equals 2 times the number of private middle school in Oakbridge City. The number of private middle school in Riverton City equals 4. The number of culinarian school in Oakbridge City equals 1 plus the number of private middle school in Oakbridge City. The number of regional medical school in Oakbridge City equals the number of private middle school in Oakbridge City. The number of private middle school in Oakbridge City equals 4. ", "question": "What is the total number of schools in Oakbridge City?", "solution": "Define private middle school in Oakbridge City as y; so y = 4. Define culinarian school in Oakbridge City as S; l = y = 4; so S = 1 + l = 1 + 4 = 5. Define regional medical school in Oakbridge City as f; so f = y = 4. Define total number of schools in Oakbridge City as E; O = y + f = 4 + 4 = 8; so E = O + S = 8 + 5 = 13. Answer: 13.", "op": 7, "id": "4_p5", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of upbeat metropolis comedy in West Sahara Movie Festival equals 1. The number of upbeat metropolis comedy in Northwood Movie Festival equals the total number of movies in Verdi Movie Festival. The number of solemn period drama in Northwood Movie Festival equals the sum of the total number of movies in Verdi Movie Festival, the number of solemn period drama in Verdi Movie Festival, the total number of movies in West Sahara Movie Festival, and the number of upbeat metropolis comedy in Verdi Movie Festival. The number of solemn period drama in West Sahara Movie Festival equals 2. The number of intense detective thriller in Northwood Movie Festival equals 2 times the sum of the number of intense detective thriller in Verdi Movie Festival, the total number of movies in West Sahara Movie Festival, and the total number of movies in Verdi Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals the number of solemn period drama in Verdi Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals 3. The number of solemn period drama in Verdi Movie Festival equals 1. The number of intense detective thriller in Verdi Movie Festival equals 2 plus the number of solemn period drama in Verdi Movie Festival. ", "question": "What is the total number of movies in Verdi Movie Festival?", "solution": "Define solemn period drama in Verdi Movie Festival as b; so b = 1. Define upbeat metropolis comedy in Verdi Movie Festival as B; so B = b = 1. Define intense detective thriller in Verdi Movie Festival as E; V = b = 1; so E = 2 + V = 2 + 1 = 3. Define total number of movies in Verdi Movie Festival as x; P = B + b = 1 + 1 = 2; so x = P + E = 2 + 3 = 5. Answer: 5.", "op": 7, "id": "15_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
{"problem": "The number of solemn period drama in Taylor Movie Festival equals the number of intense detective thriller in Taylor Movie Festival. The number of solemn period drama in Golden Banana Movie Festival equals the sum of the number of calm road movie in Golden Banana Movie Festival, the number of intense detective thriller in Verdi Movie Festival, the total number of movies in Verdi Movie Festival, and the number of solemn period drama in Verdi Movie Festival. The number of intense detective thriller in Taylor Movie Festival equals 1. The number of calm road movie in Taylor Movie Festival equals 2 times the number of solemn period drama in Taylor Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 2. The number of solemn period drama in Verdi Movie Festival equals 1. The number of intense detective thriller in Verdi Movie Festival equals the number of calm road movie in Taylor Movie Festival. The number of calm road movie in Verdi Movie Festival equals the number of solemn period drama in Verdi Movie Festival. ", "question": "What is the total number of movies in Taylor Movie Festival?", "solution": "Define intense detective thriller in Taylor Movie Festival as O; so O = 1. Define solemn period drama in Taylor Movie Festival as x; so x = O = 1. Define calm road movie in Taylor Movie Festival as L; o = x = 1; so L = 2 * o = 2 * 1 = 2. Define total number of movies in Taylor Movie Festival as y; R = L + x = 2 + 1 = 3; so y = R + O = 3 + 1 = 4. Answer: 4.", "op": 7, "id": "0_p5", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}