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1.32M
Mass of H2SO4 Density x volume 184gcm3 x 3cm3 552 g
Mass of H2O Density x volume 100gcm3 x 100cm3 100 g
Moles of H2SO4 mass 552 g 00563 moles
Molar mass of H2SO4 98g
Enthalpy change H mass of acid water x specific heat capacity of water x T 100 552 g x 42 x 13oC 5761392 J 5761392 kJ
1000
Hs of H2SO4 H 5761392 kJ 10233378kJmoles1
Moles of H2SO4 00563 moles
eStandard enthalpyheat of formation Hf
The molar enthalpy of formation Hf is defined as the energy change when one mole of a compound is formed from its elements at 298K25oC and 101325Paone atmospherepressure Hf is practically difficult to determine in a school laboratory
It is determined normally determined by applying Hess law of constant heat summation
Hess law of constant heat summation states that the total enthalpyheatenergy change of a reaction is the same regardless of the route taken from reactants to products at the same temperature and pressure
Hess law of constant heat summation is as a result of a series of experiments done by the German Scientist Henri Hess18021850
He found that the total energy change from the reactants to products was the same irrespective of the intermediate products between ie
As H1Cs As H2BsH3Cs
Applying Hess law of constant heat summation then
As H2 Bs
H1 H3
Cs
The above is called an energy cycle diagram It can be used to calculate any of the missing energy changes since
i H1 H2 H3
ii H2 H1 H3
iii H3 H1 H2
Examples of applying Hess law of constant heat summation
1Calculate the molar enthalpy of formation of methane CH4 given that Hc of carbongraphite is 3935kJmole1Hydrogen is 2857 kJmole1 and that of methane is 890 kJmole1
Working
Carbongraphite hydrogen and oxygen can react to first form methane
Methane will then burn in the oxygen present to form carbonIVoxide and water Carbongraphite can burn in the oxygen to form carbonIVoxide
Hydrogen can burn in the oxygen to form water
Cs 2H2 g2O2 g H1 CH4g 2O2g H2 CO2g2H2Ol
Cs 2H2 g2O2 g H3 CO2g2H2Ol
Energy cycle diagram
Cs 2H2 g 2O2g H1Hc 8904kJ CH4g2O2g
H3Hc 3935kJ H3Hc 2857kJ x 2 H2 Hf x
CO2g 2H2Ol
Substituting
H3 H1 H2
3935 2857 x 2 8904kJ x
x 745 kJ
Heat of formation Hf CH4 745 kJmole1
2 Calculate the molar enthalpy of formation of ethyne C2H2 given Hc of carbongraphite 394kJmole1Hydrogen 286 kJmole1 C2H2 1300 kJmole1
Working
Carbongraphite hydrogen and oxygen can react to first form ethyne
Ethyne will then burn in the oxygen present to form carbonIVoxide and water Carbongraphite can burn in the oxygen to form carbonIVoxide
Hydrogen can burn in the oxygen to form water
2Cs H2 g2 O2 g H1 C2 H2 g 2 O2g H2 CO2gH2Ol
2Cs H2 g 2 O2 g H3 2CO2gH2Ol
Energy cycle diagram
2Cs H2 g 2O2g H1Hf x C2 H22O2g
H3Hc 394kJx 2 H3Hc 286kJ H2 Hc 1300kJ
2CO2g H2Ol
Substituting
H3 H1 H2
394 x 2 286 1300kJ x
x 244 kJ
Heat of formation Hf CH4 244 kJmole1
3 Calculate the molar enthalpy of formation of carbonIIoxide CO given Hc of carbongraphite 3935kJmole1 Hc of carbonIIoxide CO 283 kJmole1
Working
Carbongraphite reacts with oxygen first to form carbon IIoxide CO
CarbonIIoxide CO then burn in the excess oxygen to form carbonIVoxide Carbongraphite can burn in excess oxygen to form carbon IV oxide
Cs O2 g H1 CO g O2g H2 CO2g
Cs O2 g H3 CO2g
Energy cycle diagram
Cs O2g H1Hf x COO2g
H3Hc 3935kJ H2 Hc 283kJ
CO2g
Substituting
H3 H1 H2
3935kJ 283kJ x
x 110 kJ
Heat of formation Hf CO 110 kJmole1
4Study the information below
H2g O2g H2Ol H1286 kJmole1
Cs O2g CO2g H2393 kJmole1
2Cs H2g O2g C2H5OHl H3277 kJmole1
Use the information to calculate the molar enthalpy of combustion H4 of ethanol
Energy cycle diagram
2Cs 3H2 g 3O2g H3Hf 227kJ C2 H5OH 3O2g
H2Hc 394kJx 2 H1Hc 286kJx 3 H4 Hc x
2CO2g 3H2Ol
Substituting
H1 H2 H3 H4
394 x 2 286 x 3 277 x
H4 1369 kJ
Heat of combustion Hc C2H5OH 1369 kJmole1
5Given the following information below
CuSO4s aq CuSO4aq H661 kJmole1
CuSO4s aq 5H2Ol CuSO4 5H2O aq H774 kJmole1
Calculate H for the reaction
CuSO4aq 5H2O CuSO4 5H2O aq H774 kJmole1
Working
CuSO4s aq 5H2Ol CuSO4aq 5H2Ol CuSO4 5H2O aq
CuSO4s aq 5H2Ol CuSO4 5H2O aq
Energy cycle diagram
CuSO4s aq 5H2Ol H1661kJ CuSO4aq 5H2Ol
H3 774kJ H2 x
CuSO4 5H2O aq
Substituting
H3 H2 H1
774kJ x 661kJ